我想设置一个特定的Drawable作为设备的壁纸,但所有的壁纸功能只接受位图。我不能使用WallpaperManager,因为我是pre 2.1。
另外,我的drawables是从网上下载的,并不存在于R.drawable中。
我想设置一个特定的Drawable作为设备的壁纸,但所有的壁纸功能只接受位图。我不能使用WallpaperManager,因为我是pre 2.1。
另外,我的drawables是从网上下载的,并不存在于R.drawable中。
这段代码有帮助。
Bitmap icon = BitmapFactory.decodeResource(context.getResources(),
R.drawable.icon_resource);
这里是下载图像的版本。
String name = c.getString(str_url);
URL url_value = new URL(name);
ImageView profile = (ImageView)v.findViewById(R.id.vdo_icon);
if (profile != null) {
Bitmap mIcon1 =
BitmapFactory.decodeStream(url_value.openConnection().getInputStream());
profile.setImageBitmap(mIcon1);
}
这将BitmapDrawable转换为Bitmap。
Drawable d = ImagesArrayList.get(0);
Bitmap bitmap = ((BitmapDrawable)d).getBitmap();
也许这能帮助到某人…
从PictureDrawable到Bitmap,使用:
private Bitmap pictureDrawableToBitmap(PictureDrawable pictureDrawable){
Bitmap bmp = Bitmap.createBitmap(pictureDrawable.getIntrinsicWidth(), pictureDrawable.getIntrinsicHeight(), Config.ARGB_8888);
Canvas canvas = new Canvas(bmp);
canvas.drawPicture(pictureDrawable.getPicture());
return bmp;
}
... 这样执行的:
Bitmap bmp = pictureDrawableToBitmap((PictureDrawable) drawable);
一个可绘制对象可以被绘制到画布上,一个画布可以被位图支持:
(更新到处理BitmapDrawables的快速转换,并确保创建的位图具有有效的大小)
public static Bitmap drawableToBitmap (Drawable drawable) {
if (drawable instanceof BitmapDrawable) {
return ((BitmapDrawable)drawable).getBitmap();
}
int width = drawable.getIntrinsicWidth();
width = width > 0 ? width : 1;
int height = drawable.getIntrinsicHeight();
height = height > 0 ? height : 1;
Bitmap bitmap = Bitmap.createBitmap(width, height, Bitmap.Config.ARGB_8888);
Canvas canvas = new Canvas(bitmap);
drawable.setBounds(0, 0, canvas.getWidth(), canvas.getHeight());
drawable.draw(canvas);
return bitmap;
}
public static Bitmap drawableToBitmap (Drawable drawable) {
Bitmap bitmap = null;
if (drawable instanceof BitmapDrawable) {
BitmapDrawable bitmapDrawable = (BitmapDrawable) drawable;
if(bitmapDrawable.getBitmap() != null) {
return bitmapDrawable.getBitmap();
}
}
if(drawable.getIntrinsicWidth() <= 0 || drawable.getIntrinsicHeight() <= 0) {
bitmap = Bitmap.createBitmap(1, 1, Bitmap.Config.ARGB_8888); // Single color bitmap will be created of 1x1 pixel
} else {
bitmap = Bitmap.createBitmap(drawable.getIntrinsicWidth(), drawable.getIntrinsicHeight(), Bitmap.Config.ARGB_8888);
}
Canvas canvas = new Canvas(bitmap);
drawable.setBounds(0, 0, canvas.getWidth(), canvas.getHeight());
drawable.draw(canvas);
return bitmap;
}
// get image path from gallery
protected void onActivityResult(int requestCode, int resultcode, Intent intent) {
super.onActivityResult(requestCode, resultcode, intent);
if (requestCode == 1) {
if (intent != null && resultcode == RESULT_OK) {
Uri selectedImage = intent.getData();
String[] filePathColumn = {MediaStore.Images.Media.DATA};
Cursor cursor = getContentResolver().query(selectedImage, filePathColumn, null, null, null);
cursor.moveToFirst();
int columnIndex = cursor.getColumnIndex(filePathColumn[0]);
filePath = cursor.getString(columnIndex);
//display image using BitmapFactory
cursor.close(); bmp = BitmapFactory.decodeFile(filepath);
iv.setBackgroundResource(0);
iv.setImageBitmap(bmp);
}
}
}
非常简单的
Bitmap tempBMP = BitmapFactory.decodeResource(getResources(),R.drawable.image);
这是更好的分辨率
public static Bitmap drawableToBitmap (Drawable drawable) {
if (drawable instanceof BitmapDrawable) {
return ((BitmapDrawable)drawable).getBitmap();
}
Bitmap bitmap = Bitmap.createBitmap(drawable.getIntrinsicWidth(), drawable.getIntrinsicHeight(), Config.ARGB_8888);
Canvas canvas = new Canvas(bitmap);
drawable.setBounds(0, 0, canvas.getWidth(), canvas.getHeight());
drawable.draw(canvas);
return bitmap;
}
public static InputStream bitmapToInputStream(Bitmap bitmap) {
int size = bitmap.getHeight() * bitmap.getRowBytes();
ByteBuffer buffer = ByteBuffer.allocate(size);
bitmap.copyPixelsToBuffer(buffer);
return new ByteArrayInputStream(buffer.array());
}
如何将可绘制的位读取为输入流的代码
Android提供了一个非直接的解决方案:BitmapDrawable。为了获得位图,我们必须提供资源id R.drawable。flower_pic到BitmapDrawable,然后将其转换为Bitmap。
Bitmap bm = ((BitmapDrawable) getResources().getDrawable(R.drawable.flower_pic)).getBitmap();
使用这段代码。它将帮助你实现你的目标。
Bitmap bmp=BitmapFactory.decodeResource(getResources(), R.drawable.profileimage);
if (bmp!=null) {
Bitmap bitmap_round=getRoundedShape(bmp);
if (bitmap_round!=null) {
profileimage.setImageBitmap(bitmap_round);
}
}
public Bitmap getRoundedShape(Bitmap scaleBitmapImage) {
int targetWidth = 100;
int targetHeight = 100;
Bitmap targetBitmap = Bitmap.createBitmap(targetWidth,
targetHeight,Bitmap.Config.ARGB_8888);
Canvas canvas = new Canvas(targetBitmap);
Path path = new Path();
path.addCircle(((float) targetWidth - 1) / 2,
((float) targetHeight - 1) / 2,
(Math.min(((float) targetWidth),
((float) targetHeight)) / 2),
Path.Direction.CCW);
canvas.clipPath(path);
Bitmap sourceBitmap = scaleBitmapImage;
canvas.drawBitmap(sourceBitmap,
new Rect(0, 0, sourceBitmap.getWidth(),
sourceBitmap.getHeight()),
new Rect(0, 0, targetWidth, targetHeight), new Paint(Paint.FILTER_BITMAP_FLAG));
return targetBitmap;
}
所以在看了(和使用)其他答案后,似乎他们都处理ColorDrawable和PaintDrawable很糟糕。(特别是在棒棒糖上)似乎着色器被调整了,所以固体块的颜色没有被正确处理。
我现在使用以下代码:
public static Bitmap drawableToBitmap(Drawable drawable) {
if (drawable instanceof BitmapDrawable) {
return ((BitmapDrawable) drawable).getBitmap();
}
// We ask for the bounds if they have been set as they would be most
// correct, then we check we are > 0
final int width = !drawable.getBounds().isEmpty() ?
drawable.getBounds().width() : drawable.getIntrinsicWidth();
final int height = !drawable.getBounds().isEmpty() ?
drawable.getBounds().height() : drawable.getIntrinsicHeight();
// Now we check we are > 0
final Bitmap bitmap = Bitmap.createBitmap(width <= 0 ? 1 : width, height <= 0 ? 1 : height,
Bitmap.Config.ARGB_8888);
Canvas canvas = new Canvas(bitmap);
drawable.setBounds(0, 0, canvas.getWidth(), canvas.getHeight());
drawable.draw(canvas);
return bitmap;
}
与其他方法不同,如果你在要求将Drawable转换为位图之前调用setBounds,它将以正确的大小绘制位图!
下面是@Chris提供的答案的Kotlin版本。Jenkins在这里:https://stackoverflow.com/a/27543712/1016462
fun Drawable.toBitmap(): Bitmap {
if (this is BitmapDrawable) {
return bitmap
}
val width = if (bounds.isEmpty) intrinsicWidth else bounds.width()
val height = if (bounds.isEmpty) intrinsicHeight else bounds.height()
return Bitmap.createBitmap(width.nonZero(), height.nonZero(), Bitmap.Config.ARGB_8888).also {
val canvas = Canvas(it)
setBounds(0, 0, canvas.width, canvas.height)
draw(canvas)
}
}
private fun Int.nonZero() = if (this <= 0) 1 else this
方法1:你可以像这样直接转换成位图
Bitmap myLogo = BitmapFactory.decodeResource(context.getResources(), R.drawable.my_drawable);
方法2:你甚至可以把资源转换成可绘制的,从那里你可以得到像这样的位图
Bitmap myLogo = ((BitmapDrawable)getResources().getDrawable(R.drawable.logo)).getBitmap();
对于API > 22 getDrawable方法移动到ResourcesCompat类,因此你可以这样做
Bitmap myLogo = ((BitmapDrawable) ResourcesCompat.getDrawable(context.getResources(), R.drawable.logo, null)).getBitmap();
ImageWorker库可以将位图转换为可绘制或base64,反之亦然。
val bitmap: Bitmap? = ImageWorker.convert().drawableToBitmap(sourceDrawable)
实现
在项目级别Gradle
allprojects {
repositories {
...
maven { url 'https://jitpack.io' }
}
}
在应用级Gradle
dependencies {
implementation 'com.github.1AboveAll:ImageWorker:0.51'
}
您还可以从外部存储和检索位图/绘图/base64图像。
检查在这里。https://github.com/1AboveAll/ImageWorker/edit/master/README.md
android-ktx有Drawable。toBitmap方法:https://android.github.io/android-ktx/core-ktx/androidx.graphics.drawable/android.graphics.drawable.-drawable/to-bitmap.html
从芬兰湾的科特林
val bitmap = myDrawable.toBitmap()
BitmapFactory.decodeResource()自动缩放位图,因此您的位图可能会变得模糊。为了防止结垢,请这样做:
BitmapFactory.Options options = new BitmapFactory.Options();
options.inScaled = false;
Bitmap source = BitmapFactory.decodeResource(context.getResources(),
R.drawable.resource_name, options);
or
InputStream is = context.getResources().openRawResource(R.drawable.resource_name)
bitmap = BitmapFactory.decodeStream(is);
如果您正在使用kotlin,请使用以下代码。它会工作
//使用image路径
val image = Drawable.createFromPath(path)
val bitmap = (image as BitmapDrawable).bitmap
1)可绘制位图:
Bitmap mIcon = BitmapFactory.decodeResource(context.getResources(),R.drawable.icon);
// mImageView.setImageBitmap(mIcon);
2)位图到可绘制:
Drawable mDrawable = new BitmapDrawable(getResources(), bitmap);
// mImageView.setDrawable(mDrawable);
最新的androidx核心库(androidx.core:core-ktx:1.2.0)现在有一个扩展函数:Drawable. tobitmap(…)来将Drawable转换为Bitmap。
Bitmap Bitmap = BitmapFactory.decodeResource(context.getResources(), R.drawable.icon);
这将不会每次工作,例如,如果你的可绘制层列表可绘制,然后它给出一个空响应,所以作为一个替代方案,你需要绘制你的可绘制到画布,然后保存为位图,请参考下面的一杯代码。
public void drawableToBitMap(Context context, int drawable, int widthPixels, int heightPixels) {
try {
File file = new File(Environment.getExternalStoragePublicDirectory(Environment.DIRECTORY_DOWNLOADS) + "/", "drawable.png");
FileOutputStream fOut = new FileOutputStream(file);
Drawable drw = ResourcesCompat.getDrawable(context.getResources(), drawable, null);
if (drw != null) {
convertToBitmap(drw, widthPixels, heightPixels).compress(Bitmap.CompressFormat.PNG, 100, fOut);
}
fOut.flush();
fOut.close();
} catch (Exception e) {
e.printStackTrace();
}
}
private Bitmap convertToBitmap(Drawable drawable, int widthPixels, int heightPixels) {
Bitmap bitmap = Bitmap.createBitmap(widthPixels, heightPixels, Bitmap.Config.ARGB_8888);
Canvas canvas = new Canvas(bitmap);
drawable.setBounds(0, 0, widthPixels, heightPixels);
drawable.draw(canvas);
return bitmap;
}
以上代码保存为drawable.png在下载目录
我在这个帖子上使用了一些答案,但其中一些并没有像预期的那样工作(也许他们在旧版本中工作),但我想在尝试了几次和错误后分享我的答案,使用扩展函数:
val markerOption = MarkerOptions().apply {
position(LatLng(driver.lat, driver.lng))
icon(R.drawabel.your_drawable.toBitmapDescriptor(context))
snippet(driver.driverId.toString())
}
mMap.addMarker(markerOption)
这是扩展函数:
fun Int.toBitmapDescriptor(context: Context): BitmapDescriptor {
val vectorDrawable = ResourcesCompat.getDrawable(context.resources, this, context.theme)
val bitmap = vectorDrawable?.toBitmap(
vectorDrawable.intrinsicWidth,
vectorDrawable.intrinsicHeight,
Bitmap.Config.ARGB_8888
)
return BitmapDescriptorFactory.fromBitmap(bitmap!!)
}
在Kotlin中,最简单的方法是:
Drawable.toBitmap(width: Int, height: Int, config: Bitmap.Config?): Bitmap
是这样的:
val bitmapResult = yourDrawable.toBitmap(1,1,null)
在哪里,只需要一个可绘制的变量,没有资源,没有上下文,没有id