我想设置一个特定的Drawable作为设备的壁纸,但所有的壁纸功能只接受位图。我不能使用WallpaperManager,因为我是pre 2.1。
另外,我的drawables是从网上下载的,并不存在于R.drawable中。
我想设置一个特定的Drawable作为设备的壁纸,但所有的壁纸功能只接受位图。我不能使用WallpaperManager,因为我是pre 2.1。
另外,我的drawables是从网上下载的,并不存在于R.drawable中。
当前回答
Bitmap Bitmap = BitmapFactory.decodeResource(context.getResources(), R.drawable.icon);
这将不会每次工作,例如,如果你的可绘制层列表可绘制,然后它给出一个空响应,所以作为一个替代方案,你需要绘制你的可绘制到画布,然后保存为位图,请参考下面的一杯代码。
public void drawableToBitMap(Context context, int drawable, int widthPixels, int heightPixels) {
try {
File file = new File(Environment.getExternalStoragePublicDirectory(Environment.DIRECTORY_DOWNLOADS) + "/", "drawable.png");
FileOutputStream fOut = new FileOutputStream(file);
Drawable drw = ResourcesCompat.getDrawable(context.getResources(), drawable, null);
if (drw != null) {
convertToBitmap(drw, widthPixels, heightPixels).compress(Bitmap.CompressFormat.PNG, 100, fOut);
}
fOut.flush();
fOut.close();
} catch (Exception e) {
e.printStackTrace();
}
}
private Bitmap convertToBitmap(Drawable drawable, int widthPixels, int heightPixels) {
Bitmap bitmap = Bitmap.createBitmap(widthPixels, heightPixels, Bitmap.Config.ARGB_8888);
Canvas canvas = new Canvas(bitmap);
drawable.setBounds(0, 0, widthPixels, heightPixels);
drawable.draw(canvas);
return bitmap;
}
以上代码保存为drawable.png在下载目录
其他回答
// get image path from gallery
protected void onActivityResult(int requestCode, int resultcode, Intent intent) {
super.onActivityResult(requestCode, resultcode, intent);
if (requestCode == 1) {
if (intent != null && resultcode == RESULT_OK) {
Uri selectedImage = intent.getData();
String[] filePathColumn = {MediaStore.Images.Media.DATA};
Cursor cursor = getContentResolver().query(selectedImage, filePathColumn, null, null, null);
cursor.moveToFirst();
int columnIndex = cursor.getColumnIndex(filePathColumn[0]);
filePath = cursor.getString(columnIndex);
//display image using BitmapFactory
cursor.close(); bmp = BitmapFactory.decodeFile(filepath);
iv.setBackgroundResource(0);
iv.setImageBitmap(bmp);
}
}
}
也许这能帮助到某人…
从PictureDrawable到Bitmap,使用:
private Bitmap pictureDrawableToBitmap(PictureDrawable pictureDrawable){
Bitmap bmp = Bitmap.createBitmap(pictureDrawable.getIntrinsicWidth(), pictureDrawable.getIntrinsicHeight(), Config.ARGB_8888);
Canvas canvas = new Canvas(bmp);
canvas.drawPicture(pictureDrawable.getPicture());
return bmp;
}
... 这样执行的:
Bitmap bmp = pictureDrawableToBitmap((PictureDrawable) drawable);
我在这个帖子上使用了一些答案,但其中一些并没有像预期的那样工作(也许他们在旧版本中工作),但我想在尝试了几次和错误后分享我的答案,使用扩展函数:
val markerOption = MarkerOptions().apply {
position(LatLng(driver.lat, driver.lng))
icon(R.drawabel.your_drawable.toBitmapDescriptor(context))
snippet(driver.driverId.toString())
}
mMap.addMarker(markerOption)
这是扩展函数:
fun Int.toBitmapDescriptor(context: Context): BitmapDescriptor {
val vectorDrawable = ResourcesCompat.getDrawable(context.resources, this, context.theme)
val bitmap = vectorDrawable?.toBitmap(
vectorDrawable.intrinsicWidth,
vectorDrawable.intrinsicHeight,
Bitmap.Config.ARGB_8888
)
return BitmapDescriptorFactory.fromBitmap(bitmap!!)
}
最新的androidx核心库(androidx.core:core-ktx:1.2.0)现在有一个扩展函数:Drawable. tobitmap(…)来将Drawable转换为Bitmap。
BitmapFactory.decodeResource()自动缩放位图,因此您的位图可能会变得模糊。为了防止结垢,请这样做:
BitmapFactory.Options options = new BitmapFactory.Options();
options.inScaled = false;
Bitmap source = BitmapFactory.decodeResource(context.getResources(),
R.drawable.resource_name, options);
or
InputStream is = context.getResources().openRawResource(R.drawable.resource_name)
bitmap = BitmapFactory.decodeStream(is);