我想设置一个特定的Drawable作为设备的壁纸,但所有的壁纸功能只接受位图。我不能使用WallpaperManager,因为我是pre 2.1。
另外,我的drawables是从网上下载的,并不存在于R.drawable中。
我想设置一个特定的Drawable作为设备的壁纸,但所有的壁纸功能只接受位图。我不能使用WallpaperManager,因为我是pre 2.1。
另外,我的drawables是从网上下载的,并不存在于R.drawable中。
当前回答
BitmapFactory.decodeResource()自动缩放位图,因此您的位图可能会变得模糊。为了防止结垢,请这样做:
BitmapFactory.Options options = new BitmapFactory.Options();
options.inScaled = false;
Bitmap source = BitmapFactory.decodeResource(context.getResources(),
R.drawable.resource_name, options);
or
InputStream is = context.getResources().openRawResource(R.drawable.resource_name)
bitmap = BitmapFactory.decodeStream(is);
其他回答
这是更好的分辨率
public static Bitmap drawableToBitmap (Drawable drawable) {
if (drawable instanceof BitmapDrawable) {
return ((BitmapDrawable)drawable).getBitmap();
}
Bitmap bitmap = Bitmap.createBitmap(drawable.getIntrinsicWidth(), drawable.getIntrinsicHeight(), Config.ARGB_8888);
Canvas canvas = new Canvas(bitmap);
drawable.setBounds(0, 0, canvas.getWidth(), canvas.getHeight());
drawable.draw(canvas);
return bitmap;
}
public static InputStream bitmapToInputStream(Bitmap bitmap) {
int size = bitmap.getHeight() * bitmap.getRowBytes();
ByteBuffer buffer = ByteBuffer.allocate(size);
bitmap.copyPixelsToBuffer(buffer);
return new ByteArrayInputStream(buffer.array());
}
如何将可绘制的位读取为输入流的代码
BitmapFactory.decodeResource()自动缩放位图,因此您的位图可能会变得模糊。为了防止结垢,请这样做:
BitmapFactory.Options options = new BitmapFactory.Options();
options.inScaled = false;
Bitmap source = BitmapFactory.decodeResource(context.getResources(),
R.drawable.resource_name, options);
or
InputStream is = context.getResources().openRawResource(R.drawable.resource_name)
bitmap = BitmapFactory.decodeStream(is);
public static Bitmap drawableToBitmap (Drawable drawable) {
Bitmap bitmap = null;
if (drawable instanceof BitmapDrawable) {
BitmapDrawable bitmapDrawable = (BitmapDrawable) drawable;
if(bitmapDrawable.getBitmap() != null) {
return bitmapDrawable.getBitmap();
}
}
if(drawable.getIntrinsicWidth() <= 0 || drawable.getIntrinsicHeight() <= 0) {
bitmap = Bitmap.createBitmap(1, 1, Bitmap.Config.ARGB_8888); // Single color bitmap will be created of 1x1 pixel
} else {
bitmap = Bitmap.createBitmap(drawable.getIntrinsicWidth(), drawable.getIntrinsicHeight(), Bitmap.Config.ARGB_8888);
}
Canvas canvas = new Canvas(bitmap);
drawable.setBounds(0, 0, canvas.getWidth(), canvas.getHeight());
drawable.draw(canvas);
return bitmap;
}
下面是@Chris提供的答案的Kotlin版本。Jenkins在这里:https://stackoverflow.com/a/27543712/1016462
fun Drawable.toBitmap(): Bitmap {
if (this is BitmapDrawable) {
return bitmap
}
val width = if (bounds.isEmpty) intrinsicWidth else bounds.width()
val height = if (bounds.isEmpty) intrinsicHeight else bounds.height()
return Bitmap.createBitmap(width.nonZero(), height.nonZero(), Bitmap.Config.ARGB_8888).also {
val canvas = Canvas(it)
setBounds(0, 0, canvas.width, canvas.height)
draw(canvas)
}
}
private fun Int.nonZero() = if (this <= 0) 1 else this
也许这能帮助到某人…
从PictureDrawable到Bitmap,使用:
private Bitmap pictureDrawableToBitmap(PictureDrawable pictureDrawable){
Bitmap bmp = Bitmap.createBitmap(pictureDrawable.getIntrinsicWidth(), pictureDrawable.getIntrinsicHeight(), Config.ARGB_8888);
Canvas canvas = new Canvas(bmp);
canvas.drawPicture(pictureDrawable.getPicture());
return bmp;
}
... 这样执行的:
Bitmap bmp = pictureDrawableToBitmap((PictureDrawable) drawable);