我想设置一个特定的Drawable作为设备的壁纸,但所有的壁纸功能只接受位图。我不能使用WallpaperManager,因为我是pre 2.1。
另外,我的drawables是从网上下载的,并不存在于R.drawable中。
我想设置一个特定的Drawable作为设备的壁纸,但所有的壁纸功能只接受位图。我不能使用WallpaperManager,因为我是pre 2.1。
另外,我的drawables是从网上下载的,并不存在于R.drawable中。
当前回答
非常简单的
Bitmap tempBMP = BitmapFactory.decodeResource(getResources(),R.drawable.image);
其他回答
// get image path from gallery
protected void onActivityResult(int requestCode, int resultcode, Intent intent) {
super.onActivityResult(requestCode, resultcode, intent);
if (requestCode == 1) {
if (intent != null && resultcode == RESULT_OK) {
Uri selectedImage = intent.getData();
String[] filePathColumn = {MediaStore.Images.Media.DATA};
Cursor cursor = getContentResolver().query(selectedImage, filePathColumn, null, null, null);
cursor.moveToFirst();
int columnIndex = cursor.getColumnIndex(filePathColumn[0]);
filePath = cursor.getString(columnIndex);
//display image using BitmapFactory
cursor.close(); bmp = BitmapFactory.decodeFile(filepath);
iv.setBackgroundResource(0);
iv.setImageBitmap(bmp);
}
}
}
这段代码有帮助。
Bitmap icon = BitmapFactory.decodeResource(context.getResources(),
R.drawable.icon_resource);
这里是下载图像的版本。
String name = c.getString(str_url);
URL url_value = new URL(name);
ImageView profile = (ImageView)v.findViewById(R.id.vdo_icon);
if (profile != null) {
Bitmap mIcon1 =
BitmapFactory.decodeStream(url_value.openConnection().getInputStream());
profile.setImageBitmap(mIcon1);
}
这是更好的分辨率
public static Bitmap drawableToBitmap (Drawable drawable) {
if (drawable instanceof BitmapDrawable) {
return ((BitmapDrawable)drawable).getBitmap();
}
Bitmap bitmap = Bitmap.createBitmap(drawable.getIntrinsicWidth(), drawable.getIntrinsicHeight(), Config.ARGB_8888);
Canvas canvas = new Canvas(bitmap);
drawable.setBounds(0, 0, canvas.getWidth(), canvas.getHeight());
drawable.draw(canvas);
return bitmap;
}
public static InputStream bitmapToInputStream(Bitmap bitmap) {
int size = bitmap.getHeight() * bitmap.getRowBytes();
ByteBuffer buffer = ByteBuffer.allocate(size);
bitmap.copyPixelsToBuffer(buffer);
return new ByteArrayInputStream(buffer.array());
}
如何将可绘制的位读取为输入流的代码
下面是@Chris提供的答案的Kotlin版本。Jenkins在这里:https://stackoverflow.com/a/27543712/1016462
fun Drawable.toBitmap(): Bitmap {
if (this is BitmapDrawable) {
return bitmap
}
val width = if (bounds.isEmpty) intrinsicWidth else bounds.width()
val height = if (bounds.isEmpty) intrinsicHeight else bounds.height()
return Bitmap.createBitmap(width.nonZero(), height.nonZero(), Bitmap.Config.ARGB_8888).also {
val canvas = Canvas(it)
setBounds(0, 0, canvas.width, canvas.height)
draw(canvas)
}
}
private fun Int.nonZero() = if (this <= 0) 1 else this
BitmapFactory.decodeResource()自动缩放位图,因此您的位图可能会变得模糊。为了防止结垢,请这样做:
BitmapFactory.Options options = new BitmapFactory.Options();
options.inScaled = false;
Bitmap source = BitmapFactory.decodeResource(context.getResources(),
R.drawable.resource_name, options);
or
InputStream is = context.getResources().openRawResource(R.drawable.resource_name)
bitmap = BitmapFactory.decodeStream(is);