有时,我需要在放弃之前将一个操作重试几次。我的代码是:

int retries = 3;
while(true) {
  try {
    DoSomething();
    break; // success!
  } catch {
    if(--retries == 0) throw;
    else Thread.Sleep(1000);
  }
}

我想在一个通用的重试函数中重写这个:

TryThreeTimes(DoSomething);

这在c#中可行吗?TryThreeTimes()方法的代码是什么?


public delegate void ThingToTryDeletage();

public static void TryNTimes(ThingToTryDelegate, int N, int sleepTime)
{
   while(true)
   {
      try
      {
        ThingToTryDelegate();
      } catch {

            if( --N == 0) throw;
          else Thread.Sleep(time);          
      }
}

public void TryThreeTimes(Action action)
{
    var tries = 3;
    while (true) {
        try {
            action();
            break; // success!
        } catch {
            if (--tries == 0)
                throw;
            Thread.Sleep(1000);
        }
    }
}

然后你会呼叫:

TryThreeTimes(DoSomething);

...或者……

TryThreeTimes(() => DoSomethingElse(withLocalVariable));

一个更灵活的选择:

public void DoWithRetry(Action action, TimeSpan sleepPeriod, int tryCount = 3)
{
    if (tryCount <= 0)
        throw new ArgumentOutOfRangeException(nameof(tryCount));

    while (true) {
        try {
            action();
            break; // success!
        } catch {
            if (--tryCount == 0)
                throw;
            Thread.Sleep(sleepPeriod);
        }
   }
}

用作:

DoWithRetry(DoSomething, TimeSpan.FromSeconds(2), tryCount: 10);

支持async/await的更现代的版本:

public async Task DoWithRetryAsync(Func<Task> action, TimeSpan sleepPeriod, int tryCount = 3)
{
    if (tryCount <= 0)
        throw new ArgumentOutOfRangeException(nameof(tryCount));

    while (true) {
        try {
            await action();
            return; // success!
        } catch {
            if (--tryCount == 0)
                throw;
            await Task.Delay(sleepPeriod);
        }
   }
}

用作:

await DoWithRetryAsync(DoSomethingAsync, TimeSpan.FromSeconds(2), tryCount: 10);

如果将简单地重试同一个调用的通用catch语句用作通用异常处理机制,则可能是危险的。话虽如此,这里有一个基于lambda的重试包装器,您可以将其用于任何方法。为了获得更大的灵活性,我选择将重试次数和重试超时作为参数:

public static class Retry
{
    public static void Do(
        Action action,
        TimeSpan retryInterval,
        int maxAttemptCount = 3)
    {
        Do<object>(() =>
        {
            action();
            return null;
        }, retryInterval, maxAttemptCount);
    }

    public static T Do<T>(
        Func<T> action,
        TimeSpan retryInterval,
        int maxAttemptCount = 3)
    {
        var exceptions = new List<Exception>();

        for (int attempted = 0; attempted < maxAttemptCount; attempted++)
        {
            try
            {
                if (attempted > 0)
                {
                    Thread.Sleep(retryInterval);
                }
                return action();
            }
            catch (Exception ex)
            {
                exceptions.Add(ex);
            }
        }
        throw new AggregateException(exceptions);
    }
}

你现在可以使用这个实用程序方法来执行重试逻辑:

Retry.Do(() => SomeFunctionThatCanFail(), TimeSpan.FromSeconds(1));

or:

Retry.Do(SomeFunctionThatCanFail, TimeSpan.FromSeconds(1));

or:

int result = Retry.Do(SomeFunctionWhichReturnsInt, TimeSpan.FromSeconds(1), 4);

或者你甚至可以做一个异步重载。


您还可以考虑添加要重试的异常类型。例如,这是您想要重试的超时异常吗?数据库异常?

RetryForExcpetionType(DoSomething, typeof(TimeoutException), 5, 1000);

public static void RetryForExcpetionType(Action action, Type retryOnExceptionType, int numRetries, int retryTimeout)
{
    if (action == null)
        throw new ArgumentNullException("action");
    if (retryOnExceptionType == null)
        throw new ArgumentNullException("retryOnExceptionType");
    while (true)
    {
        try
        {
            action();
            return;
        }
        catch(Exception e)
        {
            if (--numRetries <= 0 || !retryOnExceptionType.IsAssignableFrom(e.GetType()))
                throw;

            if (retryTimeout > 0)
                System.Threading.Thread.Sleep(retryTimeout);
        }
    }
}

您可能还注意到,所有其他示例在测试retries == 0时都存在类似的问题,要么重试无穷大,要么在给定负值时无法引发异常。Sleep(-1000)在上面的catch块中也会失败。这取决于你期望人们有多“愚蠢”,但防御性编程永远不会伤害到你。


或者做得更整洁一点....

int retries = 3;
while (retries > 0)
{
  if (DoSomething())
  {
    retries = 0;
  }
  else
  {
    retries--;
  }
}

我认为抛出异常通常应该避免作为一种机制,除非你想在边界之间传递异常(比如构建一个其他人可以使用的库)。为什么不只是让DoSomething()命令在成功时返回true,否则返回false呢?

编辑:这也可以像其他人建议的那样封装在函数中。唯一的问题是如果您不是自己编写DoSomething()函数


我要实现这个:

public static bool Retry(int maxRetries, Func<bool, bool> method)
{
    while (maxRetries > 0)
    {
        if (method(maxRetries == 1))
        {
            return true;
        }
        maxRetries--;
    }
    return false;        
}

我不会像在其他例子中那样使用异常。在我看来,如果我们期待一种方法不会成功的可能性,那么它的失败也不是例外。我调用的方法如果成功就返回true,失败就返回false。

为什么它是Func<bool>而不是Func<bool>?因此,如果我希望一个方法能够在失败时抛出异常,我有一种方法可以通知它这是最后一次尝试。

因此,我可能会将它用于如下代码:

Retry(5, delegate(bool lastIteration)
   {
       // do stuff
       if (!succeeded && lastIteration)
       {
          throw new InvalidOperationException(...)
       }
       return succeeded;
   });

or

if (!Retry(5, delegate(bool lastIteration)
   {
       // do stuff
       return succeeded;
   }))
{
   Console.WriteLine("Well, that didn't work.");
}

如果传递一个方法不使用的参数被证明很尴尬,那么实现一个重载的Retry也很简单,它只接受Func<bool>。


这可能是个坏主意。首先,这是一句格言的象征:“疯狂的定义是做同一件事两次,每次都期待不同的结果”。其次,这种编码模式本身不能很好地组合。例如:

假设您的网络硬件层在失败时重发一个数据包三次,在两次失败之间等待一秒钟。

现在假设软件层在包失败时重发关于失败的通知三次。

现在假设通知层在通知传递失败时重新激活通知三次。

现在假设错误报告层在通知失败时重新激活通知层三次。

现在假设web服务器在错误失败时重新激活错误报告三次。

现在假设web客户端在从服务器得到错误后重新发送请求三次。

现在假设网络交换机上用来将通知路由到管理员的线路被拔掉。web客户端的用户什么时候最终得到错误消息?我大约12分钟后到。

以免您认为这只是一个愚蠢的例子:我们已经在客户代码中看到了这个错误,尽管比我在这里描述的要严重得多。在特定的客户代码中,错误条件发生和最终报告给用户之间的间隔是几个星期,因为有很多层自动重试并等待。想象一下,如果是十次而不是三次,会发生什么。

通常正确的处理错误的方法是立即报告它,让用户决定怎么做。如果用户想要创建自动重试的策略,让他们在软件抽象的适当级别上创建该策略。


允许函数和重试消息

public static T RetryMethod<T>(Func<T> method, int numRetries, int retryTimeout, Action onFailureAction)
{
 Guard.IsNotNull(method, "method");            
 T retval = default(T);
 do
 {
   try
   {
     retval = method();
     return retval;
   }
   catch
   {
     onFailureAction();
      if (numRetries <= 0) throw; // improved to avoid silent failure
      Thread.Sleep(retryTimeout);
   }
} while (numRetries-- > 0);
  return retval;
}

在之前工作的基础上,我考虑用三种方式增强重试逻辑:

Specifying what exception type to catch/retry. This is the primary enhacement as retrying for any exception is just plain wrong. Not nesting the last try in a try/catch, achieving slightly better performance Making it an Action extension method static class ActionExtensions { public static void InvokeAndRetryOnException<T> (this Action action, int retries, TimeSpan retryDelay) where T : Exception { if (action == null) throw new ArgumentNullException("action"); while( retries-- > 0 ) { try { action( ); return; } catch (T) { Thread.Sleep( retryDelay ); } } action( ); } }

然后可以像这样调用方法(当然也可以使用匿名方法):

new Action( AMethodThatMightThrowIntermittentException )
  .InvokeAndRetryOnException<IntermittentException>( 2, TimeSpan.FromSeconds( 1 ) );

我需要传递一些参数给我的方法来重试,并有一个结果值;所以我需要一个表达。 我建立了这个类来做这个工作(它是受布什金的启发) 你可以这样使用它:

static void Main(string[] args)
{
    // one shot
    var res = Retry<string>.Do(() => retryThis("try"), 4, TimeSpan.FromSeconds(2), fix);

    // delayed execute
    var retry = new Retry<string>(() => retryThis("try"), 4, TimeSpan.FromSeconds(2), fix);
    var res2 = retry.Execute();
}

static void fix()
{
    Console.WriteLine("oh, no! Fix and retry!!!");
}

static string retryThis(string tryThis)
{
    Console.WriteLine("Let's try!!!");
    throw new Exception(tryThis);
}

public class Retry<TResult>
{
    Expression<Func<TResult>> _Method;
    int _NumRetries;
    TimeSpan _RetryTimeout;
    Action _OnFailureAction;

    public Retry(Expression<Func<TResult>> method, int numRetries, TimeSpan retryTimeout, Action onFailureAction)
    {
        _Method = method;
        _NumRetries = numRetries;
        _OnFailureAction = onFailureAction;
        _RetryTimeout = retryTimeout;
    }

    public TResult Execute()
    {
        TResult result = default(TResult);
        while (_NumRetries > 0)
        {
            try
            {
                result = _Method.Compile()();
                break;
            }
            catch
            {
                _OnFailureAction();
                _NumRetries--;
                if (_NumRetries <= 0) throw; // improved to avoid silent failure
                Thread.Sleep(_RetryTimeout);
            }
        }
        return result;
    }

    public static TResult Do(Expression<Func<TResult>> method, int numRetries, TimeSpan retryTimeout, Action onFailureAction)
    {
        var retry = new Retry<TResult>(method, numRetries, retryTimeout, onFailureAction);
        return retry.Execute();
    }
}

ps。 b布什金的解再重试一次=D


瞬态故障处理应用程序块提供了可扩展的重试策略集合,包括:

增量 固定间隔 指数退下

它还包括一组用于基于云的服务的错误检测策略。

有关更多信息,请参阅开发人员指南的本章。

可通过NuGet(搜索'topaz')。


我需要一个支持取消的方法,在此过程中,我添加了返回中间故障的支持。

public static class ThreadUtils
{
    public static RetryResult Retry(
        Action target,
        CancellationToken cancellationToken,
        int timeout = 5000,
        int retries = 0)
    {
        CheckRetryParameters(timeout, retries)
        var failures = new List<Exception>();
        while(!cancellationToken.IsCancellationRequested)
        {
            try
            {
                target();
                return new RetryResult(failures);
            }
            catch (Exception ex)
            {
                failures.Add(ex);
            }

            if (retries > 0)
            {
                retries--;
                if (retries == 0)
                {
                    throw new AggregateException(
                     "Retry limit reached, see InnerExceptions for details.",
                     failures);
                }
            }

            if (cancellationToken.WaitHandle.WaitOne(timeout))
            {
                break;
            }
        }

        failures.Add(new OperationCancelledException(
            "The Retry Operation was cancelled."));
        throw new AggregateException("Retry was cancelled.", failures);
    }

    private static void CheckRetryParameters(int timeout, int retries)
    {
        if (timeout < 1)
        {
            throw new ArgumentOutOfRangeException(...
        }

        if (retries < 0)
        {
            throw new ArgumentOutOfRangeException(...

        }
    }

    public class RetryResult : IEnumerable<Exception>
    {
        private readonly IEnumerable<Exception> failureExceptions;
        private readonly int failureCount;

         protected internal RetryResult(
             ICollection<Exception> failureExceptions)
         {
             this.failureExceptions = failureExceptions;
             this.failureCount = failureExceptions.Count;
         }
    }

    public int FailureCount
    {
        get { return this.failureCount; }
    }

    public IEnumerator<Exception> GetEnumerator()
    {
        return this.failureExceptions.GetEnumerator();
    }

    System.Collections.IEnumerator 
        System.Collections.IEnumerable.GetEnumerator()
    {
        return this.GetEnumerator();
    }
}

您可以像这样使用重试功能,重试3次,延迟10秒,但不会取消。

try
{
    var result = ThreadUtils.Retry(
        SomeAction, 
        CancellationToken.None,
        10000,
        3);

    // it worked
    result.FailureCount // but failed this many times first.
}
catch (AggregationException ex)
{
   // oops, 3 retries wasn't enough.
}

或者,除非取消,否则每隔5秒永远重试一次。

try
{
    var result = ThreadUtils.Retry(
        SomeAction, 
        someTokenSource.Token);

    // it worked
    result.FailureCount // but failed this many times first.
}
catch (AggregationException ex)
{
   // operation was cancelled before success.
}

正如您可以猜到的那样,在我的源代码中,我重载了Retry函数,以支持我希望使用的不同委托类型。


我是递归和扩展方法的粉丝,所以这里是我的观点:

public static void InvokeWithRetries(this Action @this, ushort numberOfRetries)
{
    try
    {
        @this();
    }
    catch
    {
        if (numberOfRetries == 0)
            throw;

        InvokeWithRetries(@this, --numberOfRetries);
    }
}

你应该试试波莉。它是由我编写的。net库,允许开发人员以流畅的方式表达临时异常处理策略,如重试,永远重试,等待和重试或断路器。

例子

Policy
    .Handle<SqlException>(ex => ex.Number == 1205)
    .Or<ArgumentException>(ex => ex.ParamName == "example")
    .WaitAndRetry(3, _ => TimeSpan.FromSeconds(3))
    .Execute(DoSomething);

6年后更新:现在我认为下面的方法非常糟糕。为了创建重试逻辑,我们应该考虑使用Polly这样的库。


重试方法的异步实现:

public static async Task<T> DoAsync<T>(Func<dynamic> action, TimeSpan retryInterval, int retryCount = 3)
    {
        var exceptions = new List<Exception>();

        for (int retry = 0; retry < retryCount; retry++)
        {
            try
            {
                return await action().ConfigureAwait(false);
            }
            catch (Exception ex)
            {
                exceptions.Add(ex);
            }

            await Task.Delay(retryInterval).ConfigureAwait(false);
        }
        throw new AggregateException(exceptions);
    }

重点:我使用。configureawait (false);和Func<dynamic>代替Func<T>


我将在接受的答案中添加以下代码

public static class Retry<TException> where TException : Exception //ability to pass the exception type
    {
        //same code as the accepted answer ....

        public static T Do<T>(Func<T> action, TimeSpan retryInterval, int retryCount = 3)
        {
            var exceptions = new List<Exception>();

            for (int retry = 0; retry < retryCount; retry++)
            {
                try
                {
                    return action();
                }
                catch (TException ex) //Usage of the exception type
                {
                    exceptions.Add(ex);
                    Thread.Sleep(retryInterval);
                }
            }

            throw new AggregateException(String.Format("Failed to excecute after {0} attempt(s)", retryCount), exceptions);
        }
    }

基本上,上面的代码使Retry类成为泛型,这样您就可以传递想要捕获的异常类型进行重试。

现在,以几乎相同的方式使用它,但指定异常类型

Retry<EndpointNotFoundException>.Do(() => SomeFunctionThatCanFail(), TimeSpan.FromSeconds(1));

用波利

https://github.com/App-vNext/Polly-Samples

这是我和波莉一起用的试药

public T Retry<T>(Func<T> action, int retryCount = 0)
{
    PolicyResult<T> policyResult = Policy
     .Handle<Exception>()
     .Retry(retryCount)
     .ExecuteAndCapture<T>(action);

    if (policyResult.Outcome == OutcomeType.Failure)
    {
        throw policyResult.FinalException;
    }

    return policyResult.Result;
}

像这样使用它

var result = Retry(() => MyFunction()), 3);

我知道这个答案很老了,但我只是想对此进行评论,因为我在使用这些while, do, whatever语句时遇到了问题。

多年来,我认为我找到了一个更好的方法。这就是使用某种事件聚合,如响应式扩展“Subject”或类似的。当尝试失败时,只需发布一个事件,说明尝试失败,并让聚合器函数重新调度该事件。这使您可以更好地控制重试,而不会用一堆重试循环或其他东西污染调用本身。你也不是用一堆线程来捆绑一个线程。


用c#、Java或其他语言简单地完成:

  internal class ShouldRetryHandler {
    private static int RETRIES_MAX_NUMBER = 3;
    private static int numberTryes;

    public static bool shouldRetry() {
        var statusRetry = false;

        if (numberTryes< RETRIES_MAX_NUMBER) {
            numberTryes++;
            statusRetry = true;
            //log msg -> 'retry number' + numberTryes

        }

        else {
            statusRetry = false;
            //log msg -> 'reached retry number limit' 
        }

        return statusRetry;
    }
}

并在你的代码中简单地使用它:

 void simpleMethod(){
    //some code

    if(ShouldRetryHandler.shouldRetry()){
    //do some repetitive work
     }

    //some code    
    }

或者你可以在递归方法中使用它:

void recursiveMethod(){
    //some code

    if(ShouldRetryHandler.shouldRetry()){
    recursiveMethod();
     }

    //some code    
    }

int retries = 3;
while (true)
{
    try
    {
        //Do Somthing
        break;
    }
    catch (Exception ex)
    {
        if (--retries == 0)
            return Request.BadRequest(ApiUtil.GenerateRequestResponse(false, "3 Times tried it failed do to : " + ex.Message, new JObject()));
        else
            System.Threading.Thread.Sleep(100);
    }

指数回退是比简单地尝试x次更好的重试策略。您可以使用Polly这样的库来实现它。


对于那些既想对任何异常进行重试,又想显式设置异常类型的人,可以使用以下方法:

public class RetryManager 
{
    public void Do(Action action, 
                    TimeSpan interval, 
                    int retries = 3)
    {
        Try<object, Exception>(() => {
            action();
            return null;
        }, interval, retries);
    }

    public T Do<T>(Func<T> action, 
                    TimeSpan interval, 
                    int retries = 3)
    {
        return Try<T, Exception>(
              action
            , interval
            , retries);
    }

    public T Do<E, T>(Func<T> action, 
                       TimeSpan interval, 
                       int retries = 3) where E : Exception
    {
        return Try<T, E>(
              action
            , interval
            , retries);
    }

    public void Do<E>(Action action, 
                       TimeSpan interval, 
                       int retries = 3) where E : Exception
    {
        Try<object, E>(() => {
            action();
            return null;
        }, interval, retries);
    }

    private T Try<T, E>(Func<T> action, 
                       TimeSpan interval, 
                       int retries = 3) where E : Exception
    {
        var exceptions = new List<E>();

        for (int retry = 0; retry < retries; retry++)
        {
            try
            {
                if (retry > 0)
                    Thread.Sleep(interval);
                return action();
            }
            catch (E ex)
            {
                exceptions.Add(ex);
            }
        }

        throw new AggregateException(exceptions);
    }
}

我根据这里发布的答案写了一个小课。希望它能帮助到某人:https://github.com/natenho/resiliency

using System;
using System.Threading;

/// <summary>
/// Classe utilitária para suporte a resiliência
/// </summary>
public sealed class Resiliency
{
    /// <summary>
    /// Define o valor padrão de número de tentativas
    /// </summary>
    public static int DefaultRetryCount { get; set; }

    /// <summary>
    /// Define o valor padrão (em segundos) de tempo de espera entre tentativas
    /// </summary>
    public static int DefaultRetryTimeout { get; set; }

    /// <summary>
    /// Inicia a parte estática da resiliência, com os valores padrões
    /// </summary>
    static Resiliency()
    {
        DefaultRetryCount = 3;
        DefaultRetryTimeout = 0;
    }

    /// <summary>
    /// Executa uma <see cref="Action"/> e tenta novamente DefaultRetryCount vezes  quando for disparada qualquer <see cref="Exception"/> 
    /// </summary>
    /// <param name="action">Ação a ser realizada</param>
    /// <remarks>Executa uma vez e realiza outras DefaultRetryCount tentativas em caso de exceção. Não aguarda para realizar novas tentativa.</remarks>
    public static void Try(Action action)
    {
        Try<Exception>(action, DefaultRetryCount, TimeSpan.FromMilliseconds(DefaultRetryTimeout), null);
    }

    /// <summary>
    /// Executa uma <see cref="Action"/> e tenta novamente determinado número de vezes quando for disparada qualquer <see cref="Exception"/> 
    /// </summary>
    /// <param name="action">Ação a ser realizada</param>
    /// <param name="retryCount">Número de novas tentativas a serem realizadas</param>
    /// <param name="retryTimeout">Tempo de espera antes de cada nova tentativa</param>
    public static void Try(Action action, int retryCount, TimeSpan retryTimeout)
    {
        Try<Exception>(action, retryCount, retryTimeout, null);
    }

    /// <summary>
    /// Executa uma <see cref="Action"/> e tenta novamente determinado número de vezes quando for disparada qualquer <see cref="Exception"/> 
    /// </summary>
    /// <param name="action">Ação a ser realizada</param>
    /// <param name="retryCount">Número de novas tentativas a serem realizadas</param>
    /// <param name="retryTimeout">Tempo de espera antes de cada nova tentativa</param>
    /// <param name="tryHandler">Permitindo manipular os critérios para realizar as tentativas</param>
    public static void Try(Action action, int retryCount, TimeSpan retryTimeout, Action<ResiliencyTryHandler<Exception>> tryHandler)
    {
        Try<Exception>(action, retryCount, retryTimeout, tryHandler);
    }

    /// <summary>
    /// Executa uma <see cref="Action"/> e tenta novamente por até DefaultRetryCount vezes quando for disparada qualquer <see cref="Exception"/> 
    /// </summary>
    /// <param name="action">Ação a ser realizada</param>
    /// <param name="tryHandler">Permitindo manipular os critérios para realizar as tentativas</param>
    /// <remarks>Executa uma vez e realiza outras DefaultRetryCount tentativas em caso de exceção. Aguarda DefaultRetryTimeout segundos antes de realizar nova tentativa.</remarks>
    public static void Try(Action action, Action<ResiliencyTryHandler<Exception>> tryHandler)
    {
        Try<Exception>(action, DefaultRetryCount, TimeSpan.FromSeconds(DefaultRetryTimeout), null);
    }

    /// <summary>
    /// Executa uma <see cref="Action"/> e tenta novamente determinado número de vezes quando for disparada qualquer <see cref="TException"/> 
    /// </summary>
    /// <param name="action">Ação a ser realizada</param>
    /// <remarks>Executa uma vez e realiza outras DefaultRetryCount tentativas em caso de exceção. Aguarda DefaultRetryTimeout segundos antes de realizar nova tentativa.</remarks>
    public static void Try<TException>(Action action) where TException : Exception
    {
        Try<TException>(action, DefaultRetryCount, TimeSpan.FromSeconds(DefaultRetryTimeout), null);
    }

    /// <summary>
    /// Executa uma <see cref="Action"/> e tenta novamente determinado número de vezes quando for disparada qualquer <see cref="TException"/> 
    /// </summary>
    /// <param name="action">Ação a ser realizada</param>
    /// <param name="retryCount"></param>
    public static void Try<TException>(Action action, int retryCount) where TException : Exception
    {
        Try<TException>(action, retryCount, TimeSpan.FromSeconds(DefaultRetryTimeout), null);
    }

    /// <summary>
    /// Executa uma <see cref="Action"/> e tenta novamente determinado número de vezes quando for disparada qualquer <see cref="Exception"/> 
    /// </summary>
    /// <param name="action">Ação a ser realizada</param>
    /// <param name="retryCount"></param>
    /// <param name="retryTimeout"></param>
    public static void Try<TException>(Action action, int retryCount, TimeSpan retryTimeout) where TException : Exception
    {
        Try<TException>(action, retryCount, retryTimeout, null);
    }

    /// <summary>
    /// Executa uma <see cref="Action"/> e tenta novamente determinado número de vezes quando for disparada qualquer <see cref="Exception"/> 
    /// </summary>
    /// <param name="action">Ação a ser realizada</param>
    /// <param name="tryHandler">Permitindo manipular os critérios para realizar as tentativas</param>
    /// <remarks>Executa uma vez e realiza outras DefaultRetryCount tentativas em caso de exceção. Aguarda DefaultRetryTimeout segundos antes de realizar nova tentativa.</remarks>
    public static void Try<TException>(Action action, Action<ResiliencyTryHandler<TException>> tryHandler) where TException : Exception
    {
        Try(action, DefaultRetryCount, TimeSpan.FromSeconds(DefaultRetryTimeout), tryHandler);
    }

    /// <summary>
    /// Executa uma <see cref="Action"/> e tenta novamente determinado número de vezes quando for disparada uma <see cref="Exception"/> definida no tipo genérico
    /// </summary>
    /// <param name="action">Ação a ser realizada</param>
    /// <param name="retryCount">Número de novas tentativas a serem realizadas</param>
    /// <param name="retryTimeout">Tempo de espera antes de cada nova tentativa</param>
    /// <param name="tryHandler">Permitindo manipular os critérios para realizar as tentativas</param>
    /// <remarks>Construído a partir de várias ideias no post <seealso cref="http://stackoverflow.com/questions/156DefaultRetryCount191/c-sharp-cleanest-way-to-write-retry-logic"/></remarks>
    public static void Try<TException>(Action action, int retryCount, TimeSpan retryTimeout, Action<ResiliencyTryHandler<TException>> tryHandler) where TException : Exception
    {
        if (action == null)
            throw new ArgumentNullException(nameof(action));

        while (retryCount-- > 0)
        {
            try
            {
                action();
                return;
            }
            catch (TException ex)
            {
                //Executa o manipulador de exception
                if (tryHandler != null)
                {
                    var callback = new ResiliencyTryHandler<TException>(ex, retryCount);
                    tryHandler(callback);
                    //A propriedade que aborta pode ser alterada pelo cliente
                    if (callback.AbortRetry)
                        throw;
                }

                //Aguarda o tempo especificado antes de tentar novamente
                Thread.Sleep(retryTimeout);
            }
        }

        //Na última tentativa, qualquer exception será lançada de volta ao chamador
        action();
    }

}

/// <summary>
/// Permite manipular o evento de cada tentativa da classe de <see cref="Resiliency"/>
/// </summary>
public class ResiliencyTryHandler<TException> where TException : Exception
{
    #region Properties

    /// <summary>
    /// Opção para abortar o ciclo de tentativas
    /// </summary>
    public bool AbortRetry { get; set; }

    /// <summary>
    /// <see cref="Exception"/> a ser tratada
    /// </summary>
    public TException Exception { get; private set; }

    /// <summary>
    /// Identifca o número da tentativa atual
    /// </summary>
    public int CurrentTry { get; private set; }

    #endregion

    #region Constructors

    /// <summary>
    /// Instancia um manipulador de tentativa. É utilizado internamente
    /// por <see cref="Resiliency"/> para permitir que o cliente altere o
    /// comportamento do ciclo de tentativas
    /// </summary>
    public ResiliencyTryHandler(TException exception, int currentTry)
    {
        Exception = exception;
        CurrentTry = currentTry;
    }

    #endregion

}

使用c# 6.0保持简单

public async Task<T> Retry<T>(Func<T> action, TimeSpan retryInterval, int retryCount)
{
    try
    {
        return action();
    }
    catch when (retryCount != 0)
    {
        await Task.Delay(retryInterval);
        return await Retry(action, retryInterval, --retryCount);
    }
}

以最新的方式实现了LBushkin的答案:

    public static async Task Do(Func<Task> task, TimeSpan retryInterval, int maxAttemptCount = 3)
    {
        var exceptions = new List<Exception>();
        for (int attempted = 0; attempted < maxAttemptCount; attempted++)
        {
            try
            {
                if (attempted > 0)
                {
                    await Task.Delay(retryInterval);
                }

                await task();
                return;
            }
            catch (Exception ex)
            {
                exceptions.Add(ex);
            }
        }
        throw new AggregateException(exceptions);
    }

    public static async Task<T> Do<T>(Func<Task<T>> task, TimeSpan retryInterval, int maxAttemptCount = 3)
    {
        var exceptions = new List<Exception>();
        for (int attempted = 0; attempted < maxAttemptCount; attempted++)
        {
            try
            {
                if (attempted > 0)
                {
                    await Task.Delay(retryInterval);
                }
                return await task();
            }
            catch (Exception ex)
            {
                exceptions.Add(ex);
            }
        }
        throw new AggregateException(exceptions);
    }  

要使用它:

await Retry.Do([TaskFunction], retryInterval, retryAttempts);

而函数[TaskFunction]可以是Task<T>,也可以只是Task。


重试助手:一个通用的java实现,它包含可返回类型和无效类型的重试。

import java.util.function.Supplier;
import org.slf4j.Logger;
import org.slf4j.LoggerFactory;

public class RetryHelper {
  private static final Logger log = LoggerFactory.getLogger(RetryHelper.class);
  private int retryWaitInMS;
  private int maxRetries;

  public RetryHelper() {
    this.retryWaitInMS = 300;
    this.maxRetries = 3;
  }

  public RetryHelper(int maxRetry) {
    this.maxRetries = maxRetry;
    this.retryWaitInMS = 300;
  }

  public RetryHelper(int retryWaitInSeconds, int maxRetry) {
    this.retryWaitInMS = retryWaitInSeconds;
    this.maxRetries = maxRetry;
  }

  public <T> T retryAndReturn(Supplier<T> supplier) {
    try {
      return supplier.get();
    } catch (Exception var3) {
      return this.retrySupplier(supplier);
    }
  }

  public void retry(Runnable runnable) {
    try {
      runnable.run();
    } catch (Exception var3) {
      this.retrySupplier(() -> {
        runnable.run();
        return null;
      });
    }

  }

  private <T> T retrySupplier(Supplier<T> supplier) {
    log.error("Failed <TASK>, will be retried " + this.maxRetries + " times.");
    int retryCounter = 0;

    while(retryCounter < this.maxRetries) {
      try {
        return supplier.get();
      } catch (Exception var6) {
        ++retryCounter;
        log.error("<TASK> failed on retry: " + retryCounter + " of " + this.maxRetries + " with error: " + var6.getMessage());
        if (retryCounter >= this.maxRetries) {
          log.error("Max retries exceeded.");
          throw var6;
        }

        try {
          Thread.sleep((long)this.retryWaitInMS);
        } catch (InterruptedException var5) {
          var5.printStackTrace();
        }
      }
    }

    return supplier.get();
  }

  public int getRetryWaitInMS() {
    return this.retryWaitInMS;
  }

  public int getMaxRetries() {
    return this.maxRetries;
  }
}

用法:

    try {
      returnValue = new RetryHelper().retryAndReturn(() -> performSomeTask(args));
      //or no return type:
      new RetryHelper().retry(() -> mytask(args));
    } catch(Exception ex){
      log.error(e.getMessage());
      throw new CustomException();
    }

此方法允许对某些异常类型进行重试(立即抛出其他异常类型)。

public static void DoRetry(
    List<Type> retryOnExceptionTypes,
    Action actionToTry,
    int retryCount = 5,
    int msWaitBeforeEachRety = 300)
{
    for (var i = 0; i < retryCount; ++i)
    {
        try
        {
            actionToTry();
            break;
        }
        catch (Exception ex)
        {
            // Retries exceeded
            // Throws on last iteration of loop
            if (i == retryCount - 1) throw;

            // Is type retryable?
            var exceptionType = ex.GetType();
            if (!retryOnExceptionTypes.Contains(exceptionType))
            {
                throw;
            }

            // Wait before retry
            Thread.Sleep(msWaitBeforeEachRety);
        }
    }
}
public static void DoRetry(
    Type retryOnExceptionType,
    Action actionToTry,
    int retryCount = 5,
    int msWaitBeforeEachRety = 300)
        => DoRetry(new List<Type> {retryOnExceptionType}, actionToTry, retryCount, msWaitBeforeEachRety);

使用示例:

DoRetry(typeof(IOException), () => {
    using (var fs = new FileStream(requestedFilePath, FileMode.Create, FileAccess.Write))
    {
        fs.Write(entryBytes, 0, entryBytes.Length);
    }
});

下面是一个async/await版本,它可以聚合异常并支持取消。

/// <seealso href="https://learn.microsoft.com/en-us/azure/architecture/patterns/retry"/>
protected static async Task<T> DoWithRetry<T>( Func<Task<T>> action, CancellationToken cancelToken, int maxRetries = 3 )
{
    var exceptions = new List<Exception>();

    for ( int retries = 0; !cancelToken.IsCancellationRequested; retries++ )
        try {
            return await action().ConfigureAwait( false );
        } catch ( Exception ex ) {
            exceptions.Add( ex );

            if ( retries < maxRetries )
                await Task.Delay( 500, cancelToken ).ConfigureAwait( false ); //ease up a bit
            else
                throw new AggregateException( "Retry limit reached", exceptions );
        }

    exceptions.Add( new OperationCanceledException( cancelToken ) );
    throw new AggregateException( "Retry loop was canceled", exceptions );
}

我已经实现了一个异步版本的接受的答案,就像这样-它似乎工作得很好-有评论吗?


        public static async Task DoAsync(
            Action action,
            TimeSpan retryInterval,
            int maxAttemptCount = 3)
        {
            DoAsync<object>(() =>
            {
                action();
                return null;
            }, retryInterval, maxAttemptCount);
        }

        public static async Task<T> DoAsync<T>(
            Func<Task<T>> action,
            TimeSpan retryInterval,
            int maxAttemptCount = 3)
        {
            var exceptions = new List<Exception>();

            for (int attempted = 0; attempted < maxAttemptCount; attempted++)
            {
                try
                {
                    if (attempted > 0)
                    {
                        Thread.Sleep(retryInterval);
                    }
                    return await action();
                }
                catch (Exception ex)
                {
                    exceptions.Add(ex);
                }
            }
            throw new AggregateException(exceptions);
        }

并且,简单地像这样称呼它:

var result = await Retry.DoAsync(() => MyAsyncMethod(), TimeSpan.FromSeconds(5), 4);

我使用Polly实现了该模式的两个实现。其一是异步。

我的同步方法是基于Erik Bergstedt的回答

public static T Retry<T>(Func<T> action, TimeSpan retryWait, int retryCount = 0)
{
    PolicyResult<T> policyResult = Policy
        .Handle<ApiException>(ex => ex.ResponseCode == (int)HttpStatusCode.TooManyRequests)
        .WaitAndRetry(retryCount, retryAttempt => retryWait)
        .ExecuteAndCapture(action);

    if (policyResult.Outcome == OutcomeType.Failure)
    {
        throw policyResult.FinalException;
    }

    return policyResult.Result;
}

异步:

public static async Task<T> RetryAsync<T>(Func<Task<T>> action, TimeSpan retryWait, int retryCount = 0)
{
    PolicyResult<T> policyResult = await Policy
        .Handle<ApiException>(ex => ex.ResponseCode == (int)HttpStatusCode.TooManyRequests)
        .WaitAndRetryAsync(retryCount, retryAttempt => retryWait)
        .ExecuteAndCaptureAsync(action);

    if (policyResult.Outcome == OutcomeType.Failure)
    {
        throw policyResult.FinalException;
    }

    return policyResult.Result;
}

允许传入异常类型以及异常类型的lambda也很容易。