允许函数和重试消息

public static T RetryMethod<T>(Func<T> method, int numRetries, int retryTimeout, Action onFailureAction)
{
 Guard.IsNotNull(method, "method");            
 T retval = default(T);
 do
 {
   try
   {
     retval = method();
     return retval;
   }
   catch
   {
     onFailureAction();
      if (numRetries <= 0) throw; // improved to avoid silent failure
      Thread.Sleep(retryTimeout);
   }
} while (numRetries-- > 0);
  return retval;
}

6年后更新:现在我认为下面的方法非常糟糕。为了创建重试逻辑，我们应该考虑使用Polly这样的库。

重试方法的异步实现:

public static async Task<T> DoAsync<T>(Func<dynamic> action, TimeSpan retryInterval, int retryCount = 3)
    {
        var exceptions = new List<Exception>();

        for (int retry = 0; retry < retryCount; retry++)
        {
            try
            {
                return await action().ConfigureAwait(false);
            }
            catch (Exception ex)
            {
                exceptions.Add(ex);
            }

            await Task.Delay(retryInterval).ConfigureAwait(false);
        }
        throw new AggregateException(exceptions);
    }

重点:我使用。configureawait (false);和Func<dynamic>代替Func<T>

或者做得更整洁一点....

int retries = 3;
while (retries > 0)
{
  if (DoSomething())
  {
    retries = 0;
  }
  else
  {
    retries--;
  }
}

我认为抛出异常通常应该避免作为一种机制，除非你想在边界之间传递异常(比如构建一个其他人可以使用的库)。为什么不只是让DoSomething()命令在成功时返回true，否则返回false呢?

编辑:这也可以像其他人建议的那样封装在函数中。唯一的问题是如果您不是自己编写DoSomething()函数

你应该试试波莉。它是由我编写的。net库，允许开发人员以流畅的方式表达临时异常处理策略，如重试，永远重试，等待和重试或断路器。

例子

Policy
    .Handle<SqlException>(ex => ex.Number == 1205)
    .Or<ArgumentException>(ex => ex.ParamName == "example")
    .WaitAndRetry(3, _ => TimeSpan.FromSeconds(3))
    .Execute(DoSomething);

您还可以考虑添加要重试的异常类型。例如，这是您想要重试的超时异常吗?数据库异常?

RetryForExcpetionType(DoSomething, typeof(TimeoutException), 5, 1000);

public static void RetryForExcpetionType(Action action, Type retryOnExceptionType, int numRetries, int retryTimeout)
{
    if (action == null)
        throw new ArgumentNullException("action");
    if (retryOnExceptionType == null)
        throw new ArgumentNullException("retryOnExceptionType");
    while (true)
    {
        try
        {
            action();
            return;
        }
        catch(Exception e)
        {
            if (--numRetries <= 0 || !retryOnExceptionType.IsAssignableFrom(e.GetType()))
                throw;

            if (retryTimeout > 0)
                System.Threading.Thread.Sleep(retryTimeout);
        }
    }
}

您可能还注意到，所有其他示例在测试retries == 0时都存在类似的问题，要么重试无穷大，要么在给定负值时无法引发异常。Sleep(-1000)在上面的catch块中也会失败。这取决于你期望人们有多“愚蠢”，但防御性编程永远不会伤害到你。

我需要一个支持取消的方法，在此过程中，我添加了返回中间故障的支持。

public static class ThreadUtils
{
    public static RetryResult Retry(
        Action target,
        CancellationToken cancellationToken,
        int timeout = 5000,
        int retries = 0)
    {
        CheckRetryParameters(timeout, retries)
        var failures = new List<Exception>();
        while(!cancellationToken.IsCancellationRequested)
        {
            try
            {
                target();
                return new RetryResult(failures);
            }
            catch (Exception ex)
            {
                failures.Add(ex);
            }

            if (retries > 0)
            {
                retries--;
                if (retries == 0)
                {
                    throw new AggregateException(
                     "Retry limit reached, see InnerExceptions for details.",
                     failures);
                }
            }

            if (cancellationToken.WaitHandle.WaitOne(timeout))
            {
                break;
            }
        }

        failures.Add(new OperationCancelledException(
            "The Retry Operation was cancelled."));
        throw new AggregateException("Retry was cancelled.", failures);
    }

    private static void CheckRetryParameters(int timeout, int retries)
    {
        if (timeout < 1)
        {
            throw new ArgumentOutOfRangeException(...
        }

        if (retries < 0)
        {
            throw new ArgumentOutOfRangeException(...

        }
    }

    public class RetryResult : IEnumerable<Exception>
    {
        private readonly IEnumerable<Exception> failureExceptions;
        private readonly int failureCount;

         protected internal RetryResult(
             ICollection<Exception> failureExceptions)
         {
             this.failureExceptions = failureExceptions;
             this.failureCount = failureExceptions.Count;
         }
    }

    public int FailureCount
    {
        get { return this.failureCount; }
    }

    public IEnumerator<Exception> GetEnumerator()
    {
        return this.failureExceptions.GetEnumerator();
    }

    System.Collections.IEnumerator 
        System.Collections.IEnumerable.GetEnumerator()
    {
        return this.GetEnumerator();
    }
}

您可以像这样使用重试功能，重试3次，延迟10秒，但不会取消。

try
{
    var result = ThreadUtils.Retry(
        SomeAction, 
        CancellationToken.None,
        10000,
        3);

    // it worked
    result.FailureCount // but failed this many times first.
}
catch (AggregationException ex)
{
   // oops, 3 retries wasn't enough.
}

或者，除非取消，否则每隔5秒永远重试一次。

try
{
    var result = ThreadUtils.Retry(
        SomeAction, 
        someTokenSource.Token);

    // it worked
    result.FailureCount // but failed this many times first.
}
catch (AggregationException ex)
{
   // operation was cancelled before success.
}

正如您可以猜到的那样，在我的源代码中，我重载了Retry函数，以支持我希望使用的不同委托类型。