使用c# 6.0保持简单

public async Task<T> Retry<T>(Func<T> action, TimeSpan retryInterval, int retryCount)
{
    try
    {
        return action();
    }
    catch when (retryCount != 0)
    {
        await Task.Delay(retryInterval);
        return await Retry(action, retryInterval, --retryCount);
    }
}

如果将简单地重试同一个调用的通用catch语句用作通用异常处理机制，则可能是危险的。话虽如此，这里有一个基于lambda的重试包装器，您可以将其用于任何方法。为了获得更大的灵活性，我选择将重试次数和重试超时作为参数:

public static class Retry
{
    public static void Do(
        Action action,
        TimeSpan retryInterval,
        int maxAttemptCount = 3)
    {
        Do<object>(() =>
        {
            action();
            return null;
        }, retryInterval, maxAttemptCount);
    }

    public static T Do<T>(
        Func<T> action,
        TimeSpan retryInterval,
        int maxAttemptCount = 3)
    {
        var exceptions = new List<Exception>();

        for (int attempted = 0; attempted < maxAttemptCount; attempted++)
        {
            try
            {
                if (attempted > 0)
                {
                    Thread.Sleep(retryInterval);
                }
                return action();
            }
            catch (Exception ex)
            {
                exceptions.Add(ex);
            }
        }
        throw new AggregateException(exceptions);
    }
}

你现在可以使用这个实用程序方法来执行重试逻辑:

Retry.Do(() => SomeFunctionThatCanFail(), TimeSpan.FromSeconds(1));

or:

Retry.Do(SomeFunctionThatCanFail, TimeSpan.FromSeconds(1));

or:

int result = Retry.Do(SomeFunctionWhichReturnsInt, TimeSpan.FromSeconds(1), 4);

或者你甚至可以做一个异步重载。

我已经实现了一个异步版本的接受的答案，就像这样-它似乎工作得很好-有评论吗?

        public static async Task DoAsync(
            Action action,
            TimeSpan retryInterval,
            int maxAttemptCount = 3)
        {
            DoAsync<object>(() =>
            {
                action();
                return null;
            }, retryInterval, maxAttemptCount);
        }

        public static async Task<T> DoAsync<T>(
            Func<Task<T>> action,
            TimeSpan retryInterval,
            int maxAttemptCount = 3)
        {
            var exceptions = new List<Exception>();

            for (int attempted = 0; attempted < maxAttemptCount; attempted++)
            {
                try
                {
                    if (attempted > 0)
                    {
                        Thread.Sleep(retryInterval);
                    }
                    return await action();
                }
                catch (Exception ex)
                {
                    exceptions.Add(ex);
                }
            }
            throw new AggregateException(exceptions);
        }

并且，简单地像这样称呼它:

var result = await Retry.DoAsync(() => MyAsyncMethod(), TimeSpan.FromSeconds(5), 4);

以最新的方式实现了LBushkin的答案:

    public static async Task Do(Func<Task> task, TimeSpan retryInterval, int maxAttemptCount = 3)
    {
        var exceptions = new List<Exception>();
        for (int attempted = 0; attempted < maxAttemptCount; attempted++)
        {
            try
            {
                if (attempted > 0)
                {
                    await Task.Delay(retryInterval);
                }

                await task();
                return;
            }
            catch (Exception ex)
            {
                exceptions.Add(ex);
            }
        }
        throw new AggregateException(exceptions);
    }

    public static async Task<T> Do<T>(Func<Task<T>> task, TimeSpan retryInterval, int maxAttemptCount = 3)
    {
        var exceptions = new List<Exception>();
        for (int attempted = 0; attempted < maxAttemptCount; attempted++)
        {
            try
            {
                if (attempted > 0)
                {
                    await Task.Delay(retryInterval);
                }
                return await task();
            }
            catch (Exception ex)
            {
                exceptions.Add(ex);
            }
        }
        throw new AggregateException(exceptions);
    }  

要使用它:

await Retry.Do([TaskFunction], retryInterval, retryAttempts);

而函数[TaskFunction]可以是Task<T>，也可以只是Task。

你应该试试波莉。它是由我编写的。net库，允许开发人员以流畅的方式表达临时异常处理策略，如重试，永远重试，等待和重试或断路器。

例子

Policy
    .Handle<SqlException>(ex => ex.Number == 1205)
    .Or<ArgumentException>(ex => ex.ParamName == "example")
    .WaitAndRetry(3, _ => TimeSpan.FromSeconds(3))
    .Execute(DoSomething);

或者做得更整洁一点....

int retries = 3;
while (retries > 0)
{
  if (DoSomething())
  {
    retries = 0;
  }
  else
  {
    retries--;
  }
}

我认为抛出异常通常应该避免作为一种机制，除非你想在边界之间传递异常(比如构建一个其他人可以使用的库)。为什么不只是让DoSomething()命令在成功时返回true，否则返回false呢?

编辑:这也可以像其他人建议的那样封装在函数中。唯一的问题是如果您不是自己编写DoSomething()函数