有时,我需要在放弃之前将一个操作重试几次。我的代码是:
int retries = 3;
while(true) {
try {
DoSomething();
break; // success!
} catch {
if(--retries == 0) throw;
else Thread.Sleep(1000);
}
}
我想在一个通用的重试函数中重写这个:
TryThreeTimes(DoSomething);
这在c#中可行吗?TryThreeTimes()方法的代码是什么?
我需要一个支持取消的方法,在此过程中,我添加了返回中间故障的支持。
public static class ThreadUtils
{
public static RetryResult Retry(
Action target,
CancellationToken cancellationToken,
int timeout = 5000,
int retries = 0)
{
CheckRetryParameters(timeout, retries)
var failures = new List<Exception>();
while(!cancellationToken.IsCancellationRequested)
{
try
{
target();
return new RetryResult(failures);
}
catch (Exception ex)
{
failures.Add(ex);
}
if (retries > 0)
{
retries--;
if (retries == 0)
{
throw new AggregateException(
"Retry limit reached, see InnerExceptions for details.",
failures);
}
}
if (cancellationToken.WaitHandle.WaitOne(timeout))
{
break;
}
}
failures.Add(new OperationCancelledException(
"The Retry Operation was cancelled."));
throw new AggregateException("Retry was cancelled.", failures);
}
private static void CheckRetryParameters(int timeout, int retries)
{
if (timeout < 1)
{
throw new ArgumentOutOfRangeException(...
}
if (retries < 0)
{
throw new ArgumentOutOfRangeException(...
}
}
public class RetryResult : IEnumerable<Exception>
{
private readonly IEnumerable<Exception> failureExceptions;
private readonly int failureCount;
protected internal RetryResult(
ICollection<Exception> failureExceptions)
{
this.failureExceptions = failureExceptions;
this.failureCount = failureExceptions.Count;
}
}
public int FailureCount
{
get { return this.failureCount; }
}
public IEnumerator<Exception> GetEnumerator()
{
return this.failureExceptions.GetEnumerator();
}
System.Collections.IEnumerator
System.Collections.IEnumerable.GetEnumerator()
{
return this.GetEnumerator();
}
}
您可以像这样使用重试功能,重试3次,延迟10秒,但不会取消。
try
{
var result = ThreadUtils.Retry(
SomeAction,
CancellationToken.None,
10000,
3);
// it worked
result.FailureCount // but failed this many times first.
}
catch (AggregationException ex)
{
// oops, 3 retries wasn't enough.
}
或者,除非取消,否则每隔5秒永远重试一次。
try
{
var result = ThreadUtils.Retry(
SomeAction,
someTokenSource.Token);
// it worked
result.FailureCount // but failed this many times first.
}
catch (AggregationException ex)
{
// operation was cancelled before success.
}
正如您可以猜到的那样,在我的源代码中,我重载了Retry函数,以支持我希望使用的不同委托类型。
重试助手:一个通用的java实现,它包含可返回类型和无效类型的重试。
import java.util.function.Supplier;
import org.slf4j.Logger;
import org.slf4j.LoggerFactory;
public class RetryHelper {
private static final Logger log = LoggerFactory.getLogger(RetryHelper.class);
private int retryWaitInMS;
private int maxRetries;
public RetryHelper() {
this.retryWaitInMS = 300;
this.maxRetries = 3;
}
public RetryHelper(int maxRetry) {
this.maxRetries = maxRetry;
this.retryWaitInMS = 300;
}
public RetryHelper(int retryWaitInSeconds, int maxRetry) {
this.retryWaitInMS = retryWaitInSeconds;
this.maxRetries = maxRetry;
}
public <T> T retryAndReturn(Supplier<T> supplier) {
try {
return supplier.get();
} catch (Exception var3) {
return this.retrySupplier(supplier);
}
}
public void retry(Runnable runnable) {
try {
runnable.run();
} catch (Exception var3) {
this.retrySupplier(() -> {
runnable.run();
return null;
});
}
}
private <T> T retrySupplier(Supplier<T> supplier) {
log.error("Failed <TASK>, will be retried " + this.maxRetries + " times.");
int retryCounter = 0;
while(retryCounter < this.maxRetries) {
try {
return supplier.get();
} catch (Exception var6) {
++retryCounter;
log.error("<TASK> failed on retry: " + retryCounter + " of " + this.maxRetries + " with error: " + var6.getMessage());
if (retryCounter >= this.maxRetries) {
log.error("Max retries exceeded.");
throw var6;
}
try {
Thread.sleep((long)this.retryWaitInMS);
} catch (InterruptedException var5) {
var5.printStackTrace();
}
}
}
return supplier.get();
}
public int getRetryWaitInMS() {
return this.retryWaitInMS;
}
public int getMaxRetries() {
return this.maxRetries;
}
}
用法:
try {
returnValue = new RetryHelper().retryAndReturn(() -> performSomeTask(args));
//or no return type:
new RetryHelper().retry(() -> mytask(args));
} catch(Exception ex){
log.error(e.getMessage());
throw new CustomException();
}
我要实现这个:
public static bool Retry(int maxRetries, Func<bool, bool> method)
{
while (maxRetries > 0)
{
if (method(maxRetries == 1))
{
return true;
}
maxRetries--;
}
return false;
}
我不会像在其他例子中那样使用异常。在我看来,如果我们期待一种方法不会成功的可能性,那么它的失败也不是例外。我调用的方法如果成功就返回true,失败就返回false。
为什么它是Func<bool>而不是Func<bool>?因此,如果我希望一个方法能够在失败时抛出异常,我有一种方法可以通知它这是最后一次尝试。
因此,我可能会将它用于如下代码:
Retry(5, delegate(bool lastIteration)
{
// do stuff
if (!succeeded && lastIteration)
{
throw new InvalidOperationException(...)
}
return succeeded;
});
or
if (!Retry(5, delegate(bool lastIteration)
{
// do stuff
return succeeded;
}))
{
Console.WriteLine("Well, that didn't work.");
}
如果传递一个方法不使用的参数被证明很尴尬,那么实现一个重载的Retry也很简单,它只接受Func<bool>。
用c#、Java或其他语言简单地完成:
internal class ShouldRetryHandler {
private static int RETRIES_MAX_NUMBER = 3;
private static int numberTryes;
public static bool shouldRetry() {
var statusRetry = false;
if (numberTryes< RETRIES_MAX_NUMBER) {
numberTryes++;
statusRetry = true;
//log msg -> 'retry number' + numberTryes
}
else {
statusRetry = false;
//log msg -> 'reached retry number limit'
}
return statusRetry;
}
}
并在你的代码中简单地使用它:
void simpleMethod(){
//some code
if(ShouldRetryHandler.shouldRetry()){
//do some repetitive work
}
//some code
}
或者你可以在递归方法中使用它:
void recursiveMethod(){
//some code
if(ShouldRetryHandler.shouldRetry()){
recursiveMethod();
}
//some code
}
6年后更新:现在我认为下面的方法非常糟糕。为了创建重试逻辑,我们应该考虑使用Polly这样的库。
重试方法的异步实现:
public static async Task<T> DoAsync<T>(Func<dynamic> action, TimeSpan retryInterval, int retryCount = 3)
{
var exceptions = new List<Exception>();
for (int retry = 0; retry < retryCount; retry++)
{
try
{
return await action().ConfigureAwait(false);
}
catch (Exception ex)
{
exceptions.Add(ex);
}
await Task.Delay(retryInterval).ConfigureAwait(false);
}
throw new AggregateException(exceptions);
}
重点:我使用。configureawait (false);和Func<dynamic>代替Func<T>