假设我有一个完整的文件路径:(/sdcard/tlogo.png)。我想知道它的mime类型。
我为它创建了一个函数
public static String getMimeType(File file, Context context)
{
Uri uri = Uri.fromFile(file);
ContentResolver cR = context.getContentResolver();
MimeTypeMap mime = MimeTypeMap.getSingleton();
String type = mime.getExtensionFromMimeType(cR.getType(uri));
return type;
}
但当我调用它时，它返回null。
File file = new File(filePath);
String fileType=CommonFunctions.getMimeType(file, context);
首先，你应该考虑调用MimeTypeMap#getMimeTypeFromExtension()，就像这样:
// url = file path or whatever suitable URL you want.
public static String getMimeType(String url) {
String type = null;
String extension = MimeTypeMap.getFileExtensionFromUrl(url);
if (extension != null) {
type = MimeTypeMap.getSingleton().getMimeTypeFromExtension(extension);
}
return type;
}
上面的MimeTypeMap解决方案在我的使用中返回null。这很有效，而且更简单:
Uri uri = Uri.fromFile(file);
ContentResolver cR = context.getContentResolver();
String mime = cR.getType(uri);
以下是我在我的Android应用程序中使用的解决方案:
public static String getMimeType(String url)
{
String extension = url.substring(url.lastIndexOf("."));
String mimeTypeMap = MimeTypeMap.getFileExtensionFromUrl(extension);
String mimeType = MimeTypeMap.getSingleton().getMimeTypeFromExtension(mimeTypeMap);
return mimeType;
}
File file = new File(path, name);
MimeTypeMap mime = MimeTypeMap.getSingleton();
int index = file.getName().lastIndexOf('.')+1;
String ext = file.getName().substring(index).toLowerCase();
String type = mime.getMimeTypeFromExtension(ext);
intent.setDataAndType(Uri.fromFile(file), type);
try
{
context.startActivity(intent);
}
catch(ActivityNotFoundException ex)
{
ex.printStackTrace();
}
请密切关注上面umerk44的解决方案。getMimeTypeFromExtension调用guessMimeTypeTypeFromExtension并且区分大小写。我花了一个下午的时间，然后仔细观察- getMimeTypeFromExtension将返回NULL，如果你传递它“JPG”，而它将返回“image/jpeg”，如果你传递它“JPG”。
MimeTypeMap可能无法识别一些文件扩展名，如flv,mpeg,3gpp,cpp。因此，您需要考虑如何扩展MimeTypeMap以维护代码。这里有这样一个例子。 http://grepcode.com/file/repo1.maven.org/maven2/com.google.okhttp/okhttp/20120626/libcore/net/MimeUtils.java#MimeUtils 另外，这里有一个完整的mime类型列表 http: / / www.sitepoint.com/web-foundations/mime-types-complete-list/
有时Jeb和Jens的答案不工作并返回null。在这种情况下，我使用跟随解决方案。文件头通常包含类型签名。我阅读了它，并与已知的签名列表进行了比较。
/**
*
* @param is InputStream on start of file. Otherwise signature can not be defined.
* @return int id of signature or -1, if unknown signature was found. See SIGNATURE_ID_(type) constants to
* identify signature by its id.
* @throws IOException in cases of read errors.
*/
public static int getSignatureIdFromHeader(InputStream is) throws IOException {
// read signature from head of source and compare with known signatures
int signatureId = -1;
int sigCount = SIGNATURES.length;
int[] byteArray = new int[MAX_SIGNATURE_LENGTH];
StringBuilder builder = new StringBuilder();
for (int i = 0; i < MAX_SIGNATURE_LENGTH; i++) {
byteArray[i] = is.read();
builder.append(Integer.toHexString(byteArray[i]));
}
if (DEBUG) {
Log.d(TAG, "head bytes=" + builder.toString());
}
for (int i = 0; i < MAX_SIGNATURE_LENGTH; i++) {
// check each bytes with known signatures
int bytes = byteArray[i];
int lastSigId = -1;
int coincidences = 0;
for (int j = 0; j < sigCount; j++) {
int[] sig = SIGNATURES[j];
if (DEBUG) {
Log.d(TAG, "compare" + i + ": " + Integer.toHexString(bytes) + " with " + sig[i]);
}
if (bytes == sig[i]) {
lastSigId = j;
coincidences++;
}
}
// signature is unknown
if (coincidences == 0) {
break;
}
// if first bytes of signature is known we check signature for full coincidence
if (coincidences == 1) {
int[] sig = SIGNATURES[lastSigId];
int sigLength = sig.length;
boolean isSigKnown = true;
for (; i < MAX_SIGNATURE_LENGTH && i < sigLength; i++) {
bytes = byteArray[i];
if (bytes != sig[i]) {
isSigKnown = false;
break;
}
}
if (isSigKnown) {
signatureId = lastSigId;
}
break;
}
}
return signatureId;
}
signatureId是签名数组中签名的索引。例如,
private static final int[] SIGNATURE_PNG = hexStringToIntArray("89504E470D0A1A0A");
private static final int[] SIGNATURE_JPEG = hexStringToIntArray("FFD8FF");
private static final int[] SIGNATURE_GIF = hexStringToIntArray("474946");
public static final int SIGNATURE_ID_JPEG = 0;
public static final int SIGNATURE_ID_PNG = 1;
public static final int SIGNATURE_ID_GIF = 2;
private static final int[][] SIGNATURES = new int[3][];
static {
SIGNATURES[SIGNATURE_ID_JPEG] = SIGNATURE_JPEG;
SIGNATURES[SIGNATURE_ID_PNG] = SIGNATURE_PNG;
SIGNATURES[SIGNATURE_ID_GIF] = SIGNATURE_GIF;
}
现在我有了文件类型，即使文件的URI没有。接下来我得到mime类型的文件类型。如果你不知道要获取哪种mime类型，你可以在这个表中找到proper。
它适用于许多文件类型。但是对于视频，它不起作用，因为你需要知道视频编解码器来获得mime类型。为了获得视频的mime类型，我使用mediametadatareretrieve。
Mime从本地文件:
String url = file.getAbsolutePath();
FileNameMap fileNameMap = URLConnection.getFileNameMap();
String mime = fileNameMap.getContentTypeFor("file://"+url);
检测任何文件的mime类型
public String getMimeType(Uri uri) {
String mimeType = null;
if (ContentResolver.SCHEME_CONTENT.equals(uri.getScheme())) {
ContentResolver cr = getAppContext().getContentResolver();
mimeType = cr.getType(uri);
} else {
String fileExtension = MimeTypeMap.getFileExtensionFromUrl(uri
.toString());
mimeType = MimeTypeMap.getSingleton().getMimeTypeFromExtension(
fileExtension.toLowerCase());
}
return mimeType;
}
你有多种选择来获得文件扩展名: 字符串文件名= uri.getLastPathSegment();请看这个链接
2-你也可以使用这段代码
filePath .substring(filePath.lastIndexOf(".")+1);
但这不是一个好方法。 3-如果你有文件的URI，那么使用这个代码
String[] projection = { MediaStore.MediaColumns.DATA,
MediaStore.MediaColumns.MIME_TYPE };
4-如果你有URL，那么使用下面的代码:
public static String getMimeType(String url) {
String type = null;
String extension = MimeTypeMap.getFileExtensionFromUrl(url);
if (extension != null) {
type = MimeTypeMap.getSingleton().getMimeTypeFromExtension(extension);
}
return type;
}
享受你的代码:)
// new processing the mime type out of Uri which may return null in some cases
String mimeType = getContentResolver().getType(uri);
// old processing the mime type out of path using the extension part if new way returned null
if (mimeType == null){mimeType URLConnection.guessContentTypeFromName(path);}
get file object....
File file = new File(filePath);
then....pass as a parameter to...
getMimeType(file);
...here is
public String getMimeType(File file) {
String mimetype = MimeTypeMap.getSingleton().getMimeTypeFromExtension(MimeTypeMap.getFileExtensionFromUrl(Uri.fromFile(file).toString()).toLowerCase());
if (mimetype == null) {
return "*/*";
}
return mimetype;///return the mimeType
}
而从资产/文件(注意，在MimeTypeMap中缺少一些情况)。
private String getMimeType(String path) {
if (null == path) return "*/*";
String extension = path;
int lastDot = extension.lastIndexOf('.');
if (lastDot != -1) {
extension = extension.substring(lastDot + 1);
}
// Convert the URI string to lower case to ensure compatibility with MimeTypeMap (see CB-2185).
extension = extension.toLowerCase(Locale.getDefault());
if (extension.equals("3ga")) {
return "audio/3gpp";
} else if (extension.equals("js")) {
return "text/javascript";
} else if (extension.equals("woff")) {
return "application/x-font-woff";
} else {
// TODO
// anyting missing from the map (http://www.sitepoint.com/web-foundations/mime-types-complete-list/)
// reference: http://grepcode.com/file/repo1.maven.org/maven2/com.google.okhttp/okhttp/20120626/libcore/net/MimeUtils.java#MimeUtils
}
return MimeTypeMap.getSingleton().getMimeTypeFromExtension(extension);
}
而使用ContentResolver
contentResolver.getType(uri)
当http/https请求
try {
HttpURLConnection conn = httpClient.open(new URL(uri.toString()));
conn.setDoInput(false);
conn.setRequestMethod("HEAD");
return conn.getHeaderField("Content-Type");
} catch (IOException e) {
}
我尝试使用标准方法来确定mime类型，但我不能使用MimeTypeMap.getFileExtensionFromUrl(uri.getPath())保留文件扩展名。这个方法返回一个空字符串。所以我做了一个重要的解决方案来保留文件扩展名。
下面是返回文件扩展名的方法:
private String getExtension(String fileName){
char[] arrayOfFilename = fileName.toCharArray();
for(int i = arrayOfFilename.length-1; i > 0; i--){
if(arrayOfFilename[i] == '.'){
return fileName.substring(i+1, fileName.length());
}
}
return "";
}
并且保留了文件扩展名，可以获得如下所示的mime类型:
public String getMimeType(File file) {
String mimeType = "";
String extension = getExtension(file.getName());
if (MimeTypeMap.getSingleton().hasExtension(extension)) {
mimeType = MimeTypeMap.getSingleton().getMimeTypeFromExtension(extension);
}
return mimeType;
}
Jens的回答的优化版本与零安全和回退类型。
@NonNull
static String getMimeType(@NonNull File file) {
String type = null;
final String url = file.toString();
final String extension = MimeTypeMap.getFileExtensionFromUrl(url);
if (extension != null) {
type = MimeTypeMap.getSingleton().getMimeTypeFromExtension(extension.toLowerCase());
}
if (type == null) {
type = "image/*"; // fallback type. You might set it to */*
}
return type;
}
重要:getFileExtensionFromUrl()只适用于小写字母!
更新(19.03.2018)
好处:上面的方法是一个不那么冗长的Kotlin扩展函数:
fun File.getMimeType(fallback: String = "image/*"): String {
return MimeTypeMap.getFileExtensionFromUrl(toString())
?.run { MimeTypeMap.getSingleton().getMimeTypeFromExtension(toLowerCase()) }
?: fallback // You might set it to */*
}
对于Xamarin Android(来自@HoaLe的回答)
public String getMimeType(Uri uri) {
String mimeType = null;
if (uri.Scheme.Equals(ContentResolver.SchemeContent))
{
ContentResolver cr = Application.Context.ContentResolver;
mimeType = cr.GetType(uri);
}
else
{
String fileExtension = MimeTypeMap.GetFileExtensionFromUrl(uri.ToString());
mimeType = MimeTypeMap.Singleton.GetMimeTypeFromExtension(
fileExtension.ToLower());
}
return mimeType;
}
public static String getFileType(Uri file)
{
try
{
if (file.getScheme().equals(ContentResolver.SCHEME_CONTENT))
return subStringFromLastMark(SystemMaster.getContentResolver().getType(file), "/");
else
return MimeTypeMap.getFileExtensionFromUrl(file.toString()).toLowerCase();
}
catch(Exception e)
{
return null;
}
}
public static String getMimeType(Uri file)
{
try
{
return MimeTypeMap.getSingleton().getMimeTypeFromExtension(getFileType(file));
}
catch(Exception e)
{
return null;
}
}
public static String subStringFromLastMark(String str,String mark)
{
int l = str.lastIndexOf(mark);
int end = str.length();
if(l == -1)
return str;
return str.substring(l + 1, end);
}
是否也返回空值 在我的案例中，路径是
/storage/ emululated /0/Music/01 - Ghost on the Dance Floor.mp3
在工作中使用
瓦尔·奥尼。replace(“”、“”)
方法是这样的
@JvmStatic
fun getMimeType(inUrl: String?): String {
if (inUrl == null) return ""
val url = inUrl.replace(" ","")
var type: String? = null
val extension = MimeTypeMap.getFileExtensionFromUrl(url)
if (extension != null) {
type = MimeTypeMap.getSingleton().getMimeTypeFromExtension(extension.toLowerCase())
}
if(type ==null){
val cR = WifiTalkie.getApplicationContext().contentResolver
type = cR.getType(Uri.parse(url))
}
if (type == null) {
type = "*/*" // fallback method_type. You might set it to */*
}
return type
}
结果返回成功结果:
音频/ mpeg
希望能对大家有所帮助
这里没有一个答案是完美的。以下是一个结合了所有热门答案的最佳元素的答案:
public final class FileUtil {
// By default, Android doesn't provide support for JSON
public static final String MIME_TYPE_JSON = "application/json";
@Nullable
public static String getMimeType(@NonNull Context context, @NonNull Uri uri) {
String mimeType = null;
if (uri.getScheme().equals(ContentResolver.SCHEME_CONTENT)) {
ContentResolver cr = context.getContentResolver();
mimeType = cr.getType(uri);
} else {
String fileExtension = getExtension(uri.toString());
if(fileExtension == null){
return null;
}
mimeType = MimeTypeMap.getSingleton().getMimeTypeFromExtension(
fileExtension.toLowerCase());
if(mimeType == null){
// Handle the misc file extensions
return handleMiscFileExtensions(fileExtension);
}
}
return mimeType;
}
@Nullable
private static String getExtension(@Nullable String fileName){
if(fileName == null || TextUtils.isEmpty(fileName)){
return null;
}
char[] arrayOfFilename = fileName.toCharArray();
for(int i = arrayOfFilename.length-1; i > 0; i--){
if(arrayOfFilename[i] == '.'){
return fileName.substring(i+1, fileName.length());
}
}
return null;
}
@Nullable
private static String handleMiscFileExtensions(@NonNull String extension){
if(extension.equals("json")){
return MIME_TYPE_JSON;
}
else{
return null;
}
}
}
Intent myIntent = new Intent(android.content.Intent.ACTION_VIEW);
File file = new File(filePatch);
Uri uris = Uri.fromFile(file);
String mimetype = null;
if
(uris.getScheme().equals(ContentResolver.SCHEME_CONTENT)) {
ContentResolver cr =
getApplicationContext().getContentResolver();
mimetype = cr.getType(uris);
} else {
String fileExtension =
MimeTypeMap.getFileExtensionFromUrl(uris.toString());
mimetype = MimeTypeMap.getSingleton().getMimeTypeFromExtension(fileExtension.toLowerCase());
}
// This will return the mimeType.
// for eg. xyz.png it will return image/png.
// here uri is the file that we were picked using intent from ext/internal storage.
private String getMimeType(Uri uri) {
// This class provides applications access to the content model.
ContentResolver contentResolver = getContentResolver();
// getType(Uri url)-Return the MIME type of the given content URL.
return contentResolver.getType(uri);
}
我也遇到过类似的问题。到目前为止，我知道不同的名字可能会有不同的结果，所以最终得出了这个解决方案。
public String getMimeType(String filePath) {
String type = null;
String extension = null;
int i = filePath.lastIndexOf('.');
if (i > 0)
extension = filePath.substring(i+1);
if (extension != null)
type = MimeTypeMap.getSingleton().getMimeTypeFromExtension(extension);
return type;
}
我认为最简单的方法是引用这个资源文件: https://android.googlesource.com/platform/libcore/+/master/luni/src/main/java/libcore/net/android.mime.types
I don't realize why MimeTypeMap.getFileExtensionFromUrl() has problems with spaces and some other characters, that returns "", but I just wrote this method to change the file name to an admit-able one. It's just playing with Strings. However, It kind of works. Through the method, the spaces existing in the file name is turned into a desirable character (which, here, is "x") via replaceAll(" ", "x") and other unsuitable characters are turned into a suitable one via URLEncoder. so the usage (according to the codes presented in the question and the selected answer) should be something like getMimeType(reviseUrl(url)).
private String reviseUrl(String url) {
String revisedUrl = "";
int fileNameBeginning = url.lastIndexOf("/");
int fileNameEnding = url.lastIndexOf(".");
String cutFileNameFromUrl = url.substring(fileNameBeginning + 1, fileNameEnding).replaceAll(" ", "x");
revisedUrl = url.
substring(0, fileNameBeginning + 1) +
java.net.URLEncoder.encode(cutFileNameFromUrl) +
url.substring(fileNameEnding, url.length());
return revisedUrl;
}
EDIT
我为此创建了一个小型库。 但是底层代码几乎是一样的。
它在GitHub上可用
MimeMagic-Android
2020年9月
使用芬兰湾的科特林
fun File.getMimeType(context: Context): String? {
if (this.isDirectory) {
return null
}
fun fallbackMimeType(uri: Uri): String? {
return if (uri.scheme == ContentResolver.SCHEME_CONTENT) {
context.contentResolver.getType(uri)
} else {
val extension = MimeTypeMap.getFileExtensionFromUrl(uri.toString())
MimeTypeMap.getSingleton().getMimeTypeFromExtension(extension.toLowerCase(Locale.getDefault()))
}
}
fun catchUrlMimeType(): String? {
val uri = Uri.fromFile(this)
return if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.O) {
val path = Paths.get(uri.toString())
try {
Files.probeContentType(path) ?: fallbackMimeType(uri)
} catch (ignored: IOException) {
fallbackMimeType(uri)
}
} else {
fallbackMimeType(uri)
}
}
val stream = this.inputStream()
return try {
URLConnection.guessContentTypeFromStream(stream) ?: catchUrlMimeType()
} catch (ignored: IOException) {
catchUrlMimeType()
} finally {
stream.close()
}
}
这似乎是最好的选择，因为它结合了前面的答案。
首先，它尝试使用URLConnection获取类型。guessContentTypeFromStream，但如果这个失败或返回null，它会尝试在Android O和以上使用mimetype
java.nio.file.Files
java.nio.file.Paths
否则，如果Android版本低于O或方法失败，它将使用ContentResolver和MimeTypeMap返回类型
它适用于我和灵活的内容和文件
public static String getMimeType(Context context, Uri uri) {
String extension;
//Check uri format to avoid null
if (uri.getScheme().equals(ContentResolver.SCHEME_CONTENT)) {
//If scheme is a content
final MimeTypeMap mime = MimeTypeMap.getSingleton();
extension = mime.getExtensionFromMimeType(context.getContentResolver().getType(uri));
} else {
//If scheme is a File
//This will replace white spaces with %20 and also other special characters. This will avoid returning null values on file name with spaces and special characters.
extension = MimeTypeMap.getFileExtensionFromUrl(Uri.fromFile(new File(uri.getPath())).toString());
}
return extension;
}
在kotlin中，这要简单得多。
解决方案1:
fun getMimeType(file: File): String? =
MimeTypeMap.getSingleton().getMimeTypeFromExtension(file.extension)
方案二:(文件扩展名函数)
fun File.mimeType(): String? =
MimeTypeMap.getSingleton().getMimeTypeFromExtension(this.extension)
