假设我有一个完整的文件路径:(/sdcard/tlogo.png)。我想知道它的mime类型。

我为它创建了一个函数

public static String getMimeType(File file, Context context)    
{
    Uri uri = Uri.fromFile(file);
    ContentResolver cR = context.getContentResolver();
    MimeTypeMap mime = MimeTypeMap.getSingleton();
    String type = mime.getExtensionFromMimeType(cR.getType(uri));
    return type;
}

但当我调用它时,它返回null。

File file = new File(filePath);
String fileType=CommonFunctions.getMimeType(file, context);

当前回答

上面的解决方案在.rar文件的情况下返回null,使用URLConnection.guessContentTypeFromName(url)在这种情况下工作。

其他回答

上面的MimeTypeMap解决方案在我的使用中返回null。这很有效,而且更简单:

Uri uri = Uri.fromFile(file);
ContentResolver cR = context.getContentResolver();
String mime = cR.getType(uri);

而从资产/文件(注意,在MimeTypeMap中缺少一些情况)。

private String getMimeType(String path) {
    if (null == path) return "*/*";

    String extension = path;
    int lastDot = extension.lastIndexOf('.');
    if (lastDot != -1) {
        extension = extension.substring(lastDot + 1);
    }

    // Convert the URI string to lower case to ensure compatibility with MimeTypeMap (see CB-2185).
    extension = extension.toLowerCase(Locale.getDefault());
    if (extension.equals("3ga")) {
        return "audio/3gpp";
    } else if (extension.equals("js")) {
        return "text/javascript";
    } else if (extension.equals("woff")) {
        return "application/x-font-woff";
    } else {
        // TODO
        // anyting missing from the map (http://www.sitepoint.com/web-foundations/mime-types-complete-list/)
        // reference: http://grepcode.com/file/repo1.maven.org/maven2/com.google.okhttp/okhttp/20120626/libcore/net/MimeUtils.java#MimeUtils
    }

    return MimeTypeMap.getSingleton().getMimeTypeFromExtension(extension);
}

而使用ContentResolver

contentResolver.getType(uri)

当http/https请求

    try {
        HttpURLConnection conn = httpClient.open(new URL(uri.toString()));
        conn.setDoInput(false);
        conn.setRequestMethod("HEAD");
        return conn.getHeaderField("Content-Type");
    } catch (IOException e) {
    }
Intent myIntent = new Intent(android.content.Intent.ACTION_VIEW);
                        File file = new File(filePatch); 
                        Uri uris = Uri.fromFile(file);
                        String mimetype = null;
                        if 
(uris.getScheme().equals(ContentResolver.SCHEME_CONTENT)) {
                            ContentResolver cr = 
getApplicationContext().getContentResolver();
                            mimetype = cr.getType(uris);
                        } else {
                            String fileExtension = 
MimeTypeMap.getFileExtensionFromUrl(uris.toString());
mimetype =  MimeTypeMap.getSingleton().getMimeTypeFromExtension(fileExtension.toLowerCase());
                        }

首先,你应该考虑调用MimeTypeMap#getMimeTypeFromExtension(),就像这样:

// url = file path or whatever suitable URL you want.
public static String getMimeType(String url) {
    String type = null;
    String extension = MimeTypeMap.getFileExtensionFromUrl(url);
    if (extension != null) {
        type = MimeTypeMap.getSingleton().getMimeTypeFromExtension(extension);
    }
    return type;
}

以下是我在我的Android应用程序中使用的解决方案:

public static String getMimeType(String url)
    {
        String extension = url.substring(url.lastIndexOf("."));
        String mimeTypeMap = MimeTypeMap.getFileExtensionFromUrl(extension);
        String mimeType = MimeTypeMap.getSingleton().getMimeTypeFromExtension(mimeTypeMap);
        return mimeType;
    }