假设我有一个完整的文件路径:(/sdcard/tlogo.png)。我想知道它的mime类型。
我为它创建了一个函数
public static String getMimeType(File file, Context context)
{
Uri uri = Uri.fromFile(file);
ContentResolver cR = context.getContentResolver();
MimeTypeMap mime = MimeTypeMap.getSingleton();
String type = mime.getExtensionFromMimeType(cR.getType(uri));
return type;
}
但当我调用它时，它返回null。
File file = new File(filePath);
String fileType=CommonFunctions.getMimeType(file, context);
当前回答
File file = new File(path, name);
MimeTypeMap mime = MimeTypeMap.getSingleton();
int index = file.getName().lastIndexOf('.')+1;
String ext = file.getName().substring(index).toLowerCase();
String type = mime.getMimeTypeFromExtension(ext);
intent.setDataAndType(Uri.fromFile(file), type);
try
{
context.startActivity(intent);
}
catch(ActivityNotFoundException ex)
{
ex.printStackTrace();
}
其他回答
public static String getFileType(Uri file)
{
try
{
if (file.getScheme().equals(ContentResolver.SCHEME_CONTENT))
return subStringFromLastMark(SystemMaster.getContentResolver().getType(file), "/");
else
return MimeTypeMap.getFileExtensionFromUrl(file.toString()).toLowerCase();
}
catch(Exception e)
{
return null;
}
}
public static String getMimeType(Uri file)
{
try
{
return MimeTypeMap.getSingleton().getMimeTypeFromExtension(getFileType(file));
}
catch(Exception e)
{
return null;
}
}
public static String subStringFromLastMark(String str,String mark)
{
int l = str.lastIndexOf(mark);
int end = str.length();
if(l == -1)
return str;
return str.substring(l + 1, end);
}
你有多种选择来获得文件扩展名: 字符串文件名= uri.getLastPathSegment();请看这个链接
2-你也可以使用这段代码
filePath .substring(filePath.lastIndexOf(".")+1);
但这不是一个好方法。 3-如果你有文件的URI，那么使用这个代码
String[] projection = { MediaStore.MediaColumns.DATA,
MediaStore.MediaColumns.MIME_TYPE };
4-如果你有URL，那么使用下面的代码:
public static String getMimeType(String url) {
String type = null;
String extension = MimeTypeMap.getFileExtensionFromUrl(url);
if (extension != null) {
type = MimeTypeMap.getSingleton().getMimeTypeFromExtension(extension);
}
return type;
}
享受你的代码:)
File file = new File(path, name);
MimeTypeMap mime = MimeTypeMap.getSingleton();
int index = file.getName().lastIndexOf('.')+1;
String ext = file.getName().substring(index).toLowerCase();
String type = mime.getMimeTypeFromExtension(ext);
intent.setDataAndType(Uri.fromFile(file), type);
try
{
context.startActivity(intent);
}
catch(ActivityNotFoundException ex)
{
ex.printStackTrace();
}
检测任何文件的mime类型
public String getMimeType(Uri uri) {
String mimeType = null;
if (ContentResolver.SCHEME_CONTENT.equals(uri.getScheme())) {
ContentResolver cr = getAppContext().getContentResolver();
mimeType = cr.getType(uri);
} else {
String fileExtension = MimeTypeMap.getFileExtensionFromUrl(uri
.toString());
mimeType = MimeTypeMap.getSingleton().getMimeTypeFromExtension(
fileExtension.toLowerCase());
}
return mimeType;
}
I don't realize why MimeTypeMap.getFileExtensionFromUrl() has problems with spaces and some other characters, that returns "", but I just wrote this method to change the file name to an admit-able one. It's just playing with Strings. However, It kind of works. Through the method, the spaces existing in the file name is turned into a desirable character (which, here, is "x") via replaceAll(" ", "x") and other unsuitable characters are turned into a suitable one via URLEncoder. so the usage (according to the codes presented in the question and the selected answer) should be something like getMimeType(reviseUrl(url)).
private String reviseUrl(String url) {
String revisedUrl = "";
int fileNameBeginning = url.lastIndexOf("/");
int fileNameEnding = url.lastIndexOf(".");
String cutFileNameFromUrl = url.substring(fileNameBeginning + 1, fileNameEnding).replaceAll(" ", "x");
revisedUrl = url.
substring(0, fileNameBeginning + 1) +
java.net.URLEncoder.encode(cutFileNameFromUrl) +
url.substring(fileNameEnding, url.length());
return revisedUrl;
}
