谁能告诉我为什么这行不通?

>>> import mock
>>> @mock.patch('datetime.date.today')
... def today(cls):
...  return date(2010, 1, 1)
...
>>> from datetime import date
>>> date.today()
datetime.date(2010, 12, 19)

也许有人能提出一个更好的办法?


当前回答

monkeypatch的最小工作示例

这个解决方案使用https://pypi.org/project/pytest-mock/包中的monkeypatch。

特点:

仅模拟datetime.today(),但datetime.now()仍然可以正常工作 仅在特定范围内模拟(即块)

import sys
from datetime import datetime

MOCKED_DATETIME_TODAY = datetime(1900, 1, 1, 0, 0, 0)

class MockedDatetime(datetime):
    @classmethod
    def today(cls):
        return MOCKED_DATETIME_TODAY

def test_mock_datetime_today(monkeypatch):
    """Only datetime.today() is mocked and returns some date in 1900. datetime.now() returns still the current date."""
    with monkeypatch.context() as mpc:
        mpc.setattr(sys.modules[__name__], 'datetime', MockedDatetime)
        assert datetime.today() == MOCKED_DATETIME_TODAY  # datetime.today() mocked
        assert datetime.now() > MOCKED_DATETIME_TODAY    # datetime.now() not mocked

    assert datetime.today() > MOCKED_DATETIME_TODAY  # not mocked anymore

其他回答

下面是另一种模拟datetime.date.today()的方法,其额外的好处是其余的datetime函数继续工作,因为模拟对象被配置为包装原始的datetime模块:

from unittest import mock, TestCase

import foo_module

class FooTest(TestCase):

    @mock.patch(f'{foo_module.__name__}.datetime', wraps=datetime)
    def test_something(self, mock_datetime):
        # mock only datetime.date.today()
        mock_datetime.date.today.return_value = datetime.date(2019, 3, 15)
        # other calls to datetime functions will be forwarded to original datetime

注意mock.patch()的wraps=datetime参数——当foo_module使用date.today()之外的其他datetime函数时,它们将被转发到原始包装的datetime模块。

我们可以使用pytest-mock (https://pypi.org/project/pytest-mock/)模拟器对象来模拟特定模块中的日期时间行为

假设您想在以下文件中模拟日期时间

# File path - source_dir/x/a.py
import datetime

def name_function():
     name = datetime.now()
     return f"name_{name}"

在测试函数中,mock将在测试运行时添加到函数中

def test_name_function(mocker):
     mocker.patch('x.a.datetime')
     x.a.datetime.now.return_value = datetime(2019, 1, 1)

     actual = name_function()

     assert actual == "name_2019-01-01"

也许您可以使用自己的“today()”方法,在需要的地方打补丁。使用utcnow()的示例可以在这里找到:https://bitbucket.org/k_bx/blog/src/tip/source/en_posts/2012-07-13-double-call-hack.rst?at=default

在Daniel G的解决方案中补充一点:

from datetime import date

class FakeDate(date):
    "A manipulable date replacement"
    def __new__(cls, *args, **kwargs):
        return date.__new__(date, *args, **kwargs)

这将创建一个类,当实例化时,该类将返回一个正常的datetime。对象,但也可以更改。

@mock.patch('datetime.date', FakeDate)
def test():
    from datetime import date
    FakeDate.today = classmethod(lambda cls: date(2010, 1, 1))
    return date.today()

test() # datetime.date(2010, 1, 1)

http://blog.xelnor.net/python-mocking-datetime/中讨论了几种解决方案。总而言之:

模拟对象-简单有效,但打破isinstance()检查:

target = datetime.datetime(2009, 1, 1)
with mock.patch.object(datetime, 'datetime', mock.Mock(wraps=datetime.datetime)) as patched:
    patched.now.return_value = target
    print(datetime.datetime.now())

模拟类

import datetime
import mock

real_datetime_class = datetime.datetime

def mock_datetime_now(target, dt):
    class DatetimeSubclassMeta(type):
        @classmethod
        def __instancecheck__(mcs, obj):
            return isinstance(obj, real_datetime_class)

    class BaseMockedDatetime(real_datetime_class):
        @classmethod
        def now(cls, tz=None):
            return target.replace(tzinfo=tz)

        @classmethod
        def utcnow(cls):
            return target

    # Python2 & Python3 compatible metaclass
    MockedDatetime = DatetimeSubclassMeta('datetime', (BaseMockedDatetime,), {})

    return mock.patch.object(dt, 'datetime', MockedDatetime)

使用:

with mock_datetime_now(target, datetime):
   ....