我想用Python编写一个函数,根据输入索引的值返回不同的固定值。

在其他语言中,我会使用switch或case语句,但Python似乎没有switch语句。在此场景中,推荐的Python解决方案是什么?


当前回答

扩展“dict as switch”思想。如果要为交换机使用默认值:

def f(x):
    try:
        return {
            'a': 1,
            'b': 2,
        }[x]
    except KeyError:
        return 'default'

其他回答

我做了一个switch-case实现,它在外部不太使用if(它仍然在类中使用if)。

class SwitchCase(object):
    def __init__(self):
        self._cases = dict()

    def add_case(self,value, fn):
        self._cases[value] = fn

    def add_default_case(self,fn):
        self._cases['default']  = fn

    def switch_case(self,value):
        if value in self._cases.keys():
            return self._cases[value](value)
        else:
            return self._cases['default'](0)

这样使用:

from switch_case import SwitchCase
switcher = SwitchCase()
switcher.add_case(1, lambda x:x+1)
switcher.add_case(2, lambda x:x+3)
switcher.add_default_case(lambda _:[1,2,3,4,5])

print switcher.switch_case(1) #2
print switcher.switch_case(2) #5
print switcher.switch_case(123) #[1, 2, 3, 4, 5]

我最喜欢的是一个非常好的食谱。这是我见过的最接近实际switchcase语句的语句,尤其是在特性中。

class switch(object):
    def __init__(self, value):
        self.value = value
        self.fall = False

    def __iter__(self):
        """Return the match method once, then stop"""
        yield self.match
        raise StopIteration
    
    def match(self, *args):
        """Indicate whether or not to enter a case suite"""
        if self.fall or not args:
            return True
        elif self.value in args: # changed for v1.5, see below
            self.fall = True
            return True
        else:
            return False

下面是一个示例:

# The following example is pretty much the exact use-case of a dictionary,
# but is included for its simplicity. Note that you can include statements
# in each suite.
v = 'ten'
for case in switch(v):
    if case('one'):
        print 1
        break
    if case('two'):
        print 2
        break
    if case('ten'):
        print 10
        break
    if case('eleven'):
        print 11
        break
    if case(): # default, could also just omit condition or 'if True'
        print "something else!"
        # No need to break here, it'll stop anyway

# break is used here to look as much like the real thing as possible, but
# elif is generally just as good and more concise.

# Empty suites are considered syntax errors, so intentional fall-throughs
# should contain 'pass'
c = 'z'
for case in switch(c):
    if case('a'): pass # only necessary if the rest of the suite is empty
    if case('b'): pass
    # ...
    if case('y'): pass
    if case('z'):
        print "c is lowercase!"
        break
    if case('A'): pass
    # ...
    if case('Z'):
        print "c is uppercase!"
        break
    if case(): # default
        print "I dunno what c was!"

# As suggested by Pierre Quentel, you can even expand upon the
# functionality of the classic 'case' statement by matching multiple
# cases in a single shot. This greatly benefits operations such as the
# uppercase/lowercase example above:
import string
c = 'A'
for case in switch(c):
    if case(*string.lowercase): # note the * for unpacking as arguments
        print "c is lowercase!"
        break
    if case(*string.uppercase):
        print "c is uppercase!"
        break
    if case('!', '?', '.'): # normal argument passing style also applies
        print "c is a sentence terminator!"
        break
    if case(): # default
        print "I dunno what c was!"

一些评论指出,使用foo作为case而不是foo中的case的上下文管理器解决方案可能更干净,对于大型switch语句,线性而不是二次行为可能是一个不错的选择。使用for循环的答案的一部分价值是有中断和突破的能力,如果我们愿意稍微使用我们选择的关键字,我们也可以在上下文管理器中实现这一点:

class Switch:
    def __init__(self, value):
        self.value = value
        self._entered = False
        self._broken = False
        self._prev = None

    def __enter__(self):
        return self

    def __exit__(self, type, value, traceback):
        return False # Allows a traceback to occur

    def __call__(self, *values):
        if self._broken:
            return False
        
        if not self._entered:
            if values and self.value not in values:
                return False
            self._entered, self._prev = True, values
            return True
        
        if self._prev is None:
            self._prev = values
            return True
        
        if self._prev != values:
            self._broken = True
            return False
        
        if self._prev == values:
            self._prev = None
            return False
    
    @property
    def default(self):
        return self()

下面是一个示例:

# Prints 'bar' then 'baz'.
with Switch(2) as case:
    while case(0):
        print('foo')
    while case(1, 2, 3):
        print('bar')
    while case(4, 5):
        print('baz')
        break
    while case.default:
        print('default')
        break

switch语句只是if/elif/else的语法糖。任何控制语句所做的都是基于某个条件(即决策路径)来授权作业。为了将其包装到模块中并能够基于其唯一id调用作业,可以使用继承和Python中的任何方法都是虚拟的这一事实来提供派生类特定的作业实现,作为特定的“case”处理程序:

#!/usr/bin/python

import sys

class Case(object):
    """
        Base class which specifies the interface for the "case" handler.
        The all required arbitrary arguments inside "execute" method will be
        provided through the derived class
        specific constructor

        @note in Python, all class methods are virtual
    """
    def __init__(self, id):
        self.id = id

    def pair(self):
        """
            Pairs the given id of the "case" with
            the instance on which "execute" will be called
        """
        return (self.id, self)

    def execute(self): # Base class virtual method that needs to be overridden
        pass

class Case1(Case):
    def __init__(self, id, msg):
        self.id = id
        self.msg = msg
    def execute(self): # Override the base class method
        print("<Case1> id={}, message: \"{}\"".format(str(self.id), self.msg))

class Case2(Case):
    def __init__(self, id, n):
        self.id = id
        self.n = n
    def execute(self): # Override the base class method
        print("<Case2> id={}, n={}.".format(str(self.id), str(self.n)))
        print("\n".join(map(str, range(self.n))))


class Switch(object):
    """
        The class which delegates the jobs
        based on the given job id
    """
    def __init__(self, cases):
        self.cases = cases # dictionary: time complexity for the access operation is 1
    def resolve(self, id):

        try:
            cases[id].execute()
        except KeyError as e:
            print("Given id: {} is wrong!".format(str(id)))



if __name__ == '__main__':

    # Cases
    cases=dict([Case1(0, "switch").pair(), Case2(1, 5).pair()])

    switch = Switch(cases)

    # id will be dynamically specified
    switch.resolve(0)
    switch.resolve(1)
    switch.resolve(2)

Python 3.10(2021)引入了match-case语句,该语句提供了Pythons“switch”的一流实现。例如:

def f(x):
    match x:
        case 'a':
            return 1
        case 'b':
            return 2
        case _:
            return 0   # 0 is the default case if x is not found

match-case语句比这个简单的示例强大得多。


以下原始答案写于2008年,当时还未提供匹配案例:

你可以用字典:

def f(x):
    return {
        'a': 1,
        'b': 2,
    }[x]
# simple case alternative

some_value = 5.0

# this while loop block simulates a case block

# case
while True:

    # case 1
    if some_value > 5:
        print ('Greater than five')
        break

    # case 2
    if some_value == 5:
        print ('Equal to five')
        break

    # else case 3
    print ( 'Must be less than 5')
    break