如何使一个Python类序列化?
class FileItem:
def __init__(self, fname):
self.fname = fname
尝试序列化为JSON:
>>> import json
>>> x = FileItem('/foo/bar')
>>> json.dumps(x)
TypeError: Object of type 'FileItem' is not JSON serializable
如何使一个Python类序列化?
class FileItem:
def __init__(self, fname):
self.fname = fname
尝试序列化为JSON:
>>> import json
>>> x = FileItem('/foo/bar')
>>> json.dumps(x)
TypeError: Object of type 'FileItem' is not JSON serializable
当前回答
我选择使用装饰器来解决datetime对象序列化问题。 这是我的代码:
#myjson.py
#Author: jmooremcc 7/16/2017
import json
from datetime import datetime, date, time, timedelta
"""
This module uses decorators to serialize date objects using json
The filename is myjson.py
In another module you simply add the following import statement:
from myjson import json
json.dumps and json.dump will then correctly serialize datetime and date
objects
"""
def json_serial(obj):
"""JSON serializer for objects not serializable by default json code"""
if isinstance(obj, (datetime, date)):
serial = str(obj)
return serial
raise TypeError ("Type %s not serializable" % type(obj))
def FixDumps(fn):
def hook(obj):
return fn(obj, default=json_serial)
return hook
def FixDump(fn):
def hook(obj, fp):
return fn(obj,fp, default=json_serial)
return hook
json.dumps=FixDumps(json.dumps)
json.dump=FixDump(json.dump)
if __name__=="__main__":
today=datetime.now()
data={'atime':today, 'greet':'Hello'}
str=json.dumps(data)
print str
通过导入上述模块,我的其他模块以正常的方式(没有指定默认关键字)使用json来序列化包含日期时间对象的数据。datetime序列化器代码会自动为json调用。Dumps和json.dump。
其他回答
加拉科给出了一个非常简洁的答案。我需要修复一些小的东西,但这是有效的:
Code
# Your custom class
class MyCustom(object):
def __json__(self):
return {
'a': self.a,
'b': self.b,
'__python__': 'mymodule.submodule:MyCustom.from_json',
}
to_json = __json__ # supported by simplejson
@classmethod
def from_json(cls, json):
obj = cls()
obj.a = json['a']
obj.b = json['b']
return obj
# Dumping and loading
import simplejson
obj = MyCustom()
obj.a = 3
obj.b = 4
json = simplejson.dumps(obj, for_json=True)
# Two-step loading
obj2_dict = simplejson.loads(json)
obj2 = MyCustom.from_json(obj2_dict)
# Make sure we have the correct thing
assert isinstance(obj2, MyCustom)
assert obj2.__dict__ == obj.__dict__
注意,加载需要两个步骤。现在是__python__属性 未使用。
这种情况有多普遍?
使用AlJohri的方法,我检查了流行的方法:
序列化(Python -> JSON):
To_json: 266,595 on 2018-06-27 toJSON: 96,307 on 2018-06-27 __json__: 8504 on 2018-06-27 For_json: 6937 on 2018-06-27
反序列化(JSON -> Python):
From_json: 226,101 on 2018-06-27
我有了自己的解决办法。使用此方法,将任何文档(字典、列表、ObjectId等)传递给序列化。
def getSerializable(doc):
# check if it's a list
if isinstance(doc, list):
for i, val in enumerate(doc):
doc[i] = getSerializable(doc[i])
return doc
# check if it's a dict
if isinstance(doc, dict):
for key in doc.keys():
doc[key] = getSerializable(doc[key])
return doc
# Process ObjectId
if isinstance(doc, ObjectId):
doc = str(doc)
return doc
# Use any other custom serializting stuff here...
# For the rest of stuff
return doc
TLDR:复制-粘贴下面的选项1或选项2
真正的/完整的答案:让Pythons json模块与你的类一起工作
AKA,求解:json。dump ({"thing": YOUR_CLASS()})
解释:
Yes, a good reliable solution exists No, there is no python "official" solution By official solution, I mean there is no way (as of 2023) to add a method to your class (like toJSON in JavaScript) and/or no way to register your class with the built-in json module. When something like json.dumps([1,2, your_obj]) is executed, python doesn't check a lookup table or object method. I'm not sure why other answers don't explain this The closest official approach is probably andyhasit's answer which is to inherit from a dictionary. However, inheriting from a dictionary doesn't work very well for many custom classes like AdvancedDateTime, or pytorch tensors. The ideal workaround is this: Mutate json.dumps (affects everywhere, even pip modules that import json) Add def __json__(self) method to your class
选项1:让一个模块来做补丁
PIP安装json-fix (扩展+包装版FancyJohn的回答,谢谢@FancyJohn)
your_class_definition.py
import json_fix
class YOUR_CLASS:
def __json__(self):
# YOUR CUSTOM CODE HERE
# you probably just want to do:
# return self.__dict__
return "a built-in object that is naturally json-able"
这是它。
使用示例:
from your_class_definition import YOUR_CLASS
import json
json.dumps([1,2, YOUR_CLASS()], indent=0)
# '[\n1,\n2,\n"a built-in object that is naturally json-able"\n]'
生成json。dump适用于Numpy数组,Pandas DataFrames和其他第三方对象,请参阅模块(只有大约2行代码,但需要解释)。
它是如何工作的?嗯…
选项2:补丁json。把你自己
注意:这种方法是简化的,它在已知的edgcase上失败(例如:如果你的自定义类继承了dict或其他内置类),并且它错过了控制外部类的json行为(numpy数组,datetime, dataframes,张量等)。
some_file_thats_imported_before_your_class_definitions.py
# Step: 1
# create the patch
from json import JSONEncoder
def wrapped_default(self, obj):
return getattr(obj.__class__, "__json__", wrapped_default.default)(obj)
wrapped_default.default = JSONEncoder().default
# apply the patch
JSONEncoder.original_default = JSONEncoder.default
JSONEncoder.default = wrapped_default
your_class_definition.py
# Step 2
class YOUR_CLASS:
def __json__(self, **options):
# YOUR CUSTOM CODE HERE
# you probably just want to do:
# return self.__dict__
return "a built-in object that is natually json-able"
_
其他答案似乎都是“序列化自定义对象的最佳实践/方法”
在这里的文档中已经介绍过了(搜索“complex”可以找到编码复数的例子)
Json在它可以打印的对象方面受到限制,而jsonpickle(你可能需要一个PIP安装jsonpickle)在它不能缩进文本方面受到限制。如果你想检查一个你不能改变类的对象的内容,我仍然找不到比:
import json
import jsonpickle
...
print json.dumps(json.loads(jsonpickle.encode(object)), indent=2)
注意:他们仍然不能打印对象方法。
class DObject(json.JSONEncoder):
def delete_not_related_keys(self, _dict):
for key in ["skipkeys", "ensure_ascii", "check_circular", "allow_nan", "sort_keys", "indent"]:
try:
del _dict[key]
except:
continue
def default(self, o):
if hasattr(o, '__dict__'):
my_dict = o.__dict__.copy()
self.delete_not_related_keys(my_dict)
return my_dict
else:
return o
a = DObject()
a.name = 'abdul wahid'
b = DObject()
b.name = a
print(json.dumps(b, cls=DObject))