我正在寻找一个算法之间的HSL颜色转换为RGB。
在我看来，HSL不是很广泛地使用，所以我没有太多的运气寻找一个转换器。
当前回答
我是这样做的，这很容易记住，把RGB想象成一个轮子上的三条辐条，相隔120度。
H = hue (0-360)
S = saturation (0-1)
L = luminance (0-1)
R1 = SIN( H ) * L
G1 = SIN( H + 120 ) * L
B1 = SIN( H + 240 ) * L
棘手的部分是饱和度，即缩小到这三者的平均值。
AVERAGE = (R1 + G1 + B1) / 3
R2 = ((R1 - AVERAGE) * S) + AVERAGE
G2 = ((G1 - AVERAGE) * S) + AVERAGE
B2 = ((B1 - AVERAGE) * S) + AVERAGE
RED = R2 * 255
GREEN = G2 * 255
BLUE = B2 * 255
其他回答
当你需要RGB到HSV，反之亦然:
function rgbToHsv(r, g, b)
{
r /= 255, g /= 255, b /= 255;
var min = Math.min(r, g, b),
max = Math.max(r, g, b),
delta = max - min,
h = 0, s = 0, v = max;
if (min != max)
{
s = (delta / max);
switch (max)
{
case r: h = (g - b) / delta + (g < b ? 6 : 0); break;
case g: h = (b - r) / delta + 2; break;
case b: h = (r - g) / delta + 4; break;
}
h /= 6;
}
return [h, s, v];
}
function hsvToRgb(h, s, v)
{
var step = h / (1 / 6),
pos = step - Math.floor(step), // the hue position within the current step
m = (Math.floor(step) % 2) ? (1 - pos) * v : pos * v, // mix color value adjusted to the brightness(v)
max = 1 * v,
min = (1 - s) * v,
med = m + ((1 - s) * (v - m)),
r, g, b;
switch (Math.floor(step))
{
case 0:
r = max;
g = med;
b = min;
break;
case 1:
r = med;
g = max;
b = min;
break;
case 2:
r = min;
g = max;
b = med;
break;
case 3:
r = min;
g = med;
b = max;
break;
case 4:
r = med;
g = min;
b = max;
break;
case 5:
r = max;
g = min;
b = med;
break;
}
return [Math.round(r * 255), Math.round(g * 255), Math.round(b * 255)];
}
我是这样做的，这很容易记住，把RGB想象成一个轮子上的三条辐条，相隔120度。
H = hue (0-360)
S = saturation (0-1)
L = luminance (0-1)
R1 = SIN( H ) * L
G1 = SIN( H + 120 ) * L
B1 = SIN( H + 240 ) * L
棘手的部分是饱和度，即缩小到这三者的平均值。
AVERAGE = (R1 + G1 + B1) / 3
R2 = ((R1 - AVERAGE) * S) + AVERAGE
G2 = ((G1 - AVERAGE) * S) + AVERAGE
B2 = ((B1 - AVERAGE) * S) + AVERAGE
RED = R2 * 255
GREEN = G2 * 255
BLUE = B2 * 255
由于circuitpython不支持colorsys(或目前移植到)，如果你试图在树莓派上处理这个转换，下面的工作(受制于本线程其他地方提到的舍入精度限制):
def hslToRgb (h, s, l): #in range 0-1 for h,s,l
if s == 0:
r = g = b = l #achromatic
else:
def hue2rgb(p, q, t):
if t < 0: t += 1
if t > 1: t -= 1
if t < 1.0 / 6.0: return p + (q - p) * 6 * t
if t < 1.0 / 2.0: return q
if t < 2.0 / 3.0: return p + (q - p) * ((2.0 / 3.0) - t) * 6
return p
if l < 0.5:
q = l * (1 + s)
else:
q = l + s - l * s
p = 2 * l - q
r = hue2rgb(p, q, h + 1.0/3.0)
g = hue2rgb(p, q, h)
b = hue2rgb(p, q, h - 1.0/3.0)
return [round(r * 255), round(g * 255), round(b * 255)]
Garry Tan在他的博客上发布了一个Javascript解决方案(他把它归为现已不存在的mjijackson.com，但存档在这里，原作者有一个要点——感谢user2441511)。
代码重新发布如下:
HSL到RGB:
/**
* Converts an HSL color value to RGB. Conversion formula
* adapted from http://en.wikipedia.org/wiki/HSL_color_space.
* Assumes h, s, and l are contained in the set [0, 1] and
* returns r, g, and b in the set [0, 255].
*
* @param {number} h The hue
* @param {number} s The saturation
* @param {number} l The lightness
* @return {Array} The RGB representation
*/
function hslToRgb(h, s, l){
var r, g, b;
if(s == 0){
r = g = b = l; // achromatic
}else{
var hue2rgb = function hue2rgb(p, q, t){
if(t < 0) t += 1;
if(t > 1) t -= 1;
if(t < 1/6) return p + (q - p) * 6 * t;
if(t < 1/2) return q;
if(t < 2/3) return p + (q - p) * (2/3 - t) * 6;
return p;
}
var q = l < 0.5 ? l * (1 + s) : l + s - l * s;
var p = 2 * l - q;
r = hue2rgb(p, q, h + 1/3);
g = hue2rgb(p, q, h);
b = hue2rgb(p, q, h - 1/3);
}
return [Math.round(r * 255), Math.round(g * 255), Math.round(b * 255)];
}
RGB转HSL:
/**
* Converts an RGB color value to HSL. Conversion formula
* adapted from http://en.wikipedia.org/wiki/HSL_color_space.
* Assumes r, g, and b are contained in the set [0, 255] and
* returns h, s, and l in the set [0, 1].
*
* @param {number} r The red color value
* @param {number} g The green color value
* @param {number} b The blue color value
* @return {Array} The HSL representation
*/
function rgbToHsl(r, g, b){
r /= 255, g /= 255, b /= 255;
var max = Math.max(r, g, b), min = Math.min(r, g, b);
var h, s, l = (max + min) / 2;
if(max == min){
h = s = 0; // achromatic
}else{
var d = max - min;
s = l > 0.5 ? d / (2 - max - min) : d / (max + min);
switch(max){
case r: h = (g - b) / d + (g < b ? 6 : 0); break;
case g: h = (b - r) / d + 2; break;
case b: h = (r - g) / d + 4; break;
}
h /= 6;
}
return [h, s, l];
}
PHP -简短但精确
在这里，我将我的JS答案(数学细节在那里)重写为PHP -你可以在这里运行它
function hsl2rgb($h,$s,$l)
{
$a = $s * min($l, 1-$l);
$k = function($n,$h) { return ($n+$h/30)%12;};
$f = function($n) use ($h,$s,$l,$a,$k) {
return $l - $a * max( min($k($n,$h)-3, 9-$k($n,$h), 1),-1);
};
return [ $f(0), $f(8), $f(4) ];
}
