我正在寻找一个算法之间的HSL颜色转换为RGB。
在我看来,HSL不是很广泛地使用,所以我没有太多的运气寻找一个转换器。
我正在寻找一个算法之间的HSL颜色转换为RGB。
在我看来,HSL不是很广泛地使用,所以我没有太多的运气寻找一个转换器。
当前回答
Java版本:
/*
Converts color from HSL/A format to RGB/A format
0 <= h <= 360
0 <= s, l, a <= 1
Based on: https://en.wikipedia.org/wiki/HSL_and_HSV#:~:text=%5Bedit%5D-,HSL%20to%20RGB%5Bedit%5D,-Given%20a%20color
*/
public RGB toRGB(double h, double s, double l, Double a) {
double c = (1 - Math.abs(2 * l - 1)) * s;
double x = c * (1 - Math.abs((h / 60) % 2 - 1));
double m = l - c / 2;
int[] RGBTag = Arrays.stream(getRGBTag(c, x)).mapToInt(e -> (int)Math.round((e + m) * 255)).toArray();
return RGB(RGBTag[0], RGBTag[1], RGBTag[2], a);
}
private double[] getRGBTag(double c, double x) {
if (h < 60) {
return new double[] {c, x, 0};
} else if (h < 120) {
return new double[] {x, c, 0};
} else if (h < 180) {
return new double[] {0, c, x};
} else if (h < 240) {
return new double[] {0, x, c};
} else if (h < 300) {
return new double[] {x, 0, c};
}
return new double[] {c, 0, x};
}
其他回答
H, S, L在[0,1]范围内:
ConvertHslToRgb: function (iHsl)
{
var min, sv, sextant, fract, vsf;
var v = (iHsl.l <= 0.5) ? (iHsl.l * (1 + iHsl.s)) : (iHsl.l + iHsl.s - iHsl.l * iHsl.s);
if (v === 0)
return { Red: 0, Green: 0, Blue: 0 };
min = 2 * iHsl.l - v;
sv = (v - min) / v;
var h = (6 * iHsl.h) % 6;
sextant = Math.floor(h);
fract = h - sextant;
vsf = v * sv * fract;
switch (sextant)
{
case 0: return { r: v, g: min + vsf, b: min };
case 1: return { r: v - vsf, g: v, b: min };
case 2: return { r: min, g: v, b: min + vsf };
case 3: return { r: min, g: v - vsf, b: v };
case 4: return { r: min + vsf, g: min, b: v };
case 5: return { r: v, g: min, b: v - vsf };
}
}
来自Mohsen回答的c#代码。
下面是Mohsen用c#编写的答案代码,如果有人想要的话。注意:Color是自定义类,Vector4来自OpenTK。两者都很容易被你选择的其他东西取代。
Hsl到Rgba
/// <summary>
/// Converts an HSL color value to RGB.
/// Input: Vector4 ( X: [0.0, 1.0], Y: [0.0, 1.0], Z: [0.0, 1.0], W: [0.0, 1.0] )
/// Output: Color ( R: [0, 255], G: [0, 255], B: [0, 255], A: [0, 255] )
/// </summary>
/// <param name="hsl">Vector4 defining X = h, Y = s, Z = l, W = a. Ranges [0, 1.0]</param>
/// <returns>RGBA Color. Ranges [0, 255]</returns>
public static Color HslToRgba(Vector4 hsl)
{
float r, g, b;
if (hsl.Y == 0.0f)
r = g = b = hsl.Z;
else
{
var q = hsl.Z < 0.5f ? hsl.Z * (1.0f + hsl.Y) : hsl.Z + hsl.Y - hsl.Z * hsl.Y;
var p = 2.0f * hsl.Z - q;
r = HueToRgb(p, q, hsl.X + 1.0f / 3.0f);
g = HueToRgb(p, q, hsl.X);
b = HueToRgb(p, q, hsl.X - 1.0f / 3.0f);
}
return new Color((int)(r * 255), (int)(g * 255), (int)(b * 255), (int)(hsl.W * 255));
}
// Helper for HslToRgba
private static float HueToRgb(float p, float q, float t)
{
if (t < 0.0f) t += 1.0f;
if (t > 1.0f) t -= 1.0f;
if (t < 1.0f / 6.0f) return p + (q - p) * 6.0f * t;
if (t < 1.0f / 2.0f) return q;
if (t < 2.0f / 3.0f) return p + (q - p) * (2.0f / 3.0f - t) * 6.0f;
return p;
}
Rgba到Hsl
/// <summary>
/// Converts an RGB color value to HSL.
/// Input: Color ( R: [0, 255], G: [0, 255], B: [0, 255], A: [0, 255] )
/// Output: Vector4 ( X: [0.0, 1.0], Y: [0.0, 1.0], Z: [0.0, 1.0], W: [0.0, 1.0] )
/// </summary>
/// <param name="rgba"></param>
/// <returns></returns>
public static Vector4 RgbaToHsl(Color rgba)
{
float r = rgba.R / 255.0f;
float g = rgba.G / 255.0f;
float b = rgba.B / 255.0f;
float max = (r > g && r > b) ? r : (g > b) ? g : b;
float min = (r < g && r < b) ? r : (g < b) ? g : b;
float h, s, l;
h = s = l = (max + min) / 2.0f;
if (max == min)
h = s = 0.0f;
else
{
float d = max - min;
s = (l > 0.5f) ? d / (2.0f - max - min) : d / (max + min);
if (r > g && r > b)
h = (g - b) / d + (g < b ? 6.0f : 0.0f);
else if (g > b)
h = (b - r) / d + 2.0f;
else
h = (r - g) / d + 4.0f;
h /= 6.0f;
}
return new Vector4(h, s, l, rgba.A / 255.0f);
}
一个hsl|的颜色值,设置在javascript,将立即 所有你需要做的是,然后访问 计算样式值
document.body.style.color = 'hsla(44, 100%, 50%, 0.8)';
console.log(window.getComputedStyle(document.body).color);
// displays: rgba(255, 187, 0, 0.8)
从技术上讲,我想,这甚至不是任何一行代码-这是 自动完成。所以,取决于你的环境,你 也许这样就能逃过一劫。并不是说没有 这里有很多深思熟虑的回复。我不知道你的 目标是。
现在,如果你想从rbg|a转换到hsl|a呢?
Mohsen代码的Java实现
注意,所有整数都声明为浮点数(即1f),必须是浮点数,否则您将选择灰色。
HSL到RGB
/**
* Converts an HSL color value to RGB. Conversion formula
* adapted from http://en.wikipedia.org/wiki/HSL_color_space.
* Assumes h, s, and l are contained in the set [0, 1] and
* returns r, g, and b in the set [0, 255].
*
* @param h The hue
* @param s The saturation
* @param l The lightness
* @return int array, the RGB representation
*/
public static int[] hslToRgb(float h, float s, float l){
float r, g, b;
if (s == 0f) {
r = g = b = l; // achromatic
} else {
float q = l < 0.5f ? l * (1 + s) : l + s - l * s;
float p = 2 * l - q;
r = hueToRgb(p, q, h + 1f/3f);
g = hueToRgb(p, q, h);
b = hueToRgb(p, q, h - 1f/3f);
}
int[] rgb = {to255(r), to255(g), to255(b)};
return rgb;
}
public static int to255(float v) { return (int)Math.min(255,256*v); }
/** Helper method that converts hue to rgb */
public static float hueToRgb(float p, float q, float t) {
if (t < 0f)
t += 1f;
if (t > 1f)
t -= 1f;
if (t < 1f/6f)
return p + (q - p) * 6f * t;
if (t < 1f/2f)
return q;
if (t < 2f/3f)
return p + (q - p) * (2f/3f - t) * 6f;
return p;
}
RGB到HSL
/**
* Converts an RGB color value to HSL. Conversion formula
* adapted from http://en.wikipedia.org/wiki/HSL_color_space.
* Assumes pR, pG, and bpBare contained in the set [0, 255] and
* returns h, s, and l in the set [0, 1].
*
* @param pR The red color value
* @param pG The green color value
* @param pB The blue color value
* @return float array, the HSL representation
*/
public static float[] rgbToHsl(int pR, int pG, int pB) {
float r = pR / 255f;
float g = pG / 255f;
float b = pB / 255f;
float max = (r > g && r > b) ? r : (g > b) ? g : b;
float min = (r < g && r < b) ? r : (g < b) ? g : b;
float h, s, l;
l = (max + min) / 2.0f;
if (max == min) {
h = s = 0.0f;
} else {
float d = max - min;
s = (l > 0.5f) ? d / (2.0f - max - min) : d / (max + min);
if (r > g && r > b)
h = (g - b) / d + (g < b ? 6.0f : 0.0f);
else if (g > b)
h = (b - r) / d + 2.0f;
else
h = (r - g) / d + 4.0f;
h /= 6.0f;
}
float[] hsl = {h, s, l};
return hsl;
}
下面是GLSL中快速、超级简单、无分支的版本:
vec3 hsl2rgb( vec3 c ) {
vec3 rgb = clamp(abs(mod(c.x*6.0 + vec3(0.0, 4.0, 2.0), 6.0)-3.0)-1.0, 0.0, 1.0);
return c.z + c.y * (rgb-0.5)*(1.0-abs(2.0*c.z-1.0));
}
没有比这更短的了~
原始概念验证的链接:https://www.shadertoy.com/view/XljGzV
(免责声明:不是我的代码!)