找到了最简单的方法，蟒蛇来拯救:D

colorsys。Hls_to_rgb (h, l, s) 将颜色从HLS坐标转换为RGB坐标。

来自Mohsen回答的c#代码。

下面是Mohsen用c#编写的答案代码，如果有人想要的话。注意:Color是自定义类，Vector4来自OpenTK。两者都很容易被你选择的其他东西取代。

Hsl到Rgba

/// <summary>
/// Converts an HSL color value to RGB.
/// Input: Vector4 ( X: [0.0, 1.0], Y: [0.0, 1.0], Z: [0.0, 1.0], W: [0.0, 1.0] )
/// Output: Color ( R: [0, 255], G: [0, 255], B: [0, 255], A: [0, 255] )
/// </summary>
/// <param name="hsl">Vector4 defining X = h, Y = s, Z = l, W = a. Ranges [0, 1.0]</param>
/// <returns>RGBA Color. Ranges [0, 255]</returns>
public static Color HslToRgba(Vector4 hsl)
{
    float r, g, b;

    if (hsl.Y == 0.0f)
        r = g = b = hsl.Z;

    else
    {
        var q = hsl.Z < 0.5f ? hsl.Z * (1.0f + hsl.Y) : hsl.Z + hsl.Y - hsl.Z * hsl.Y;
        var p = 2.0f * hsl.Z - q;
        r = HueToRgb(p, q, hsl.X + 1.0f / 3.0f);
        g = HueToRgb(p, q, hsl.X);
        b = HueToRgb(p, q, hsl.X - 1.0f / 3.0f);
    }

    return new Color((int)(r * 255), (int)(g * 255), (int)(b * 255), (int)(hsl.W * 255));
}

// Helper for HslToRgba
private static float HueToRgb(float p, float q, float t)
{
    if (t < 0.0f) t += 1.0f;
    if (t > 1.0f) t -= 1.0f;
    if (t < 1.0f / 6.0f) return p + (q - p) * 6.0f * t;
    if (t < 1.0f / 2.0f) return q;
    if (t < 2.0f / 3.0f) return p + (q - p) * (2.0f / 3.0f - t) * 6.0f;
    return p;
}

Rgba到Hsl

/// <summary>
/// Converts an RGB color value to HSL.
/// Input: Color ( R: [0, 255], G: [0, 255], B: [0, 255], A: [0, 255] )
/// Output: Vector4 ( X: [0.0, 1.0], Y: [0.0, 1.0], Z: [0.0, 1.0], W: [0.0, 1.0] )
/// </summary>
/// <param name="rgba"></param>
/// <returns></returns>
public static Vector4 RgbaToHsl(Color rgba)
{
    float r = rgba.R / 255.0f;
    float g = rgba.G / 255.0f;
    float b = rgba.B / 255.0f;

    float max = (r > g && r > b) ? r : (g > b) ? g : b;
    float min = (r < g && r < b) ? r : (g < b) ? g : b;

    float h, s, l;
    h = s = l = (max + min) / 2.0f;

    if (max == min)
        h = s = 0.0f;

    else
    {
        float d = max - min;
        s = (l > 0.5f) ? d / (2.0f - max - min) : d / (max + min);

        if (r > g && r > b)
            h = (g - b) / d + (g < b ? 6.0f : 0.0f);

        else if (g > b)
            h = (b - r) / d + 2.0f;

        else
            h = (r - g) / d + 4.0f;

        h /= 6.0f;
    }

    return new Vector4(h, s, l, rgba.A / 255.0f);
}

下面是GLSL中快速、超级简单、无分支的版本:

vec3 hsl2rgb( vec3 c ) {
    vec3 rgb = clamp(abs(mod(c.x*6.0 + vec3(0.0, 4.0, 2.0), 6.0)-3.0)-1.0, 0.0, 1.0);
    return c.z + c.y * (rgb-0.5)*(1.0-abs(2.0*c.z-1.0));
}

没有比这更短的了~

原始概念验证的链接:https://www.shadertoy.com/view/XljGzV

(免责声明:不是我的代码!)

Java版本:

/*
Converts color from HSL/A format to RGB/A format
0 <= h <= 360
0 <= s, l, a <= 1
Based on: https://en.wikipedia.org/wiki/HSL_and_HSV#:~:text=%5Bedit%5D-,HSL%20to%20RGB%5Bedit%5D,-Given%20a%20color
 */
public RGB toRGB(double h, double s, double l, Double a) {
    double c = (1 - Math.abs(2 * l - 1)) * s;
    double x = c * (1 - Math.abs((h / 60) % 2 - 1));
    double m = l - c / 2;
    int[] RGBTag = Arrays.stream(getRGBTag(c, x)).mapToInt(e -> (int)Math.round((e + m) * 255)).toArray();
    return RGB(RGBTag[0], RGBTag[1], RGBTag[2], a);

}

private double[] getRGBTag(double c, double x) {
    if (h < 60) {
        return new double[] {c, x, 0};
    } else if (h < 120) {
        return new double[] {x, c, 0};
    } else if (h < 180) {
        return new double[] {0, c, x};
    } else if (h < 240) {
        return new double[] {0, x, c};
    } else if (h < 300) {
        return new double[] {x, 0, c};
    }
    return new double[] {c, 0, x};
}

如果你正在寻找一些完全符合HSL和RGB的CSS语义的东西，你可以使用css3规范中指定的算法，它如下:

HOW TO RETURN hsl.to.rgb(h, s, l): 
   SELECT: 
      l<=0.5: PUT l*(s+1) IN m2
      ELSE: PUT l+s-l*s IN m2
   PUT l*2-m2 IN m1
   PUT hue.to.rgb(m1, m2, h+1/3) IN r
   PUT hue.to.rgb(m1, m2, h    ) IN g
   PUT hue.to.rgb(m1, m2, h-1/3) IN b
   RETURN (r, g, b)

HOW TO RETURN hue.to.rgb(m1, m2, h): 
   IF h<0: PUT h+1 IN h
   IF h>1: PUT h-1 IN h
   IF h*6<1: RETURN m1+(m2-m1)*h*6
   IF h*2<1: RETURN m2
   IF h*3<2: RETURN m1+(m2-m1)*(2/3-h)*6
   RETURN m1

我相信这是这里其他一些答案的来源。

这里是修改后的javascript函数，它在0-360度集输出Hue。

function rgbToHsl(r, g, b) {
      r /= 255, g /= 255, b /= 255;
      var max = Math.max(r, g, b), min = Math.min(r, g, b);
      var h, s, l = (max + min) / 2;

      if(max == min){
          h = s = 0; // achromatic
      } else {
          var d = max - min;
          s = l > 0.5 ? d / (2 - max - min) : d / (max + min);
          switch(max){
              case r: h = (g - b) / d ; break;
              case g: h = 2 + ( (b - r) / d); break;
              case b: h = 4 + ( (r - g) / d); break;
          }
          h*=60;
          if (h < 0) h +=360;
      }
     return([h, s, l]);
  }  
alert(rgbToHsl(125,115,145));