让我们把你的优秀和最喜欢的扩展方法列一个列表。
要求是必须发布完整的代码,以及如何使用它的示例和解释。
基于对这个主题的高度兴趣,我在Codeplex上建立了一个名为extensionoverflow的开源项目。
请将您的回答标记为接受,以便将代码放入Codeplex项目。
请张贴完整的源代码,而不是一个链接。
Codeplex上新闻:
24.08.2010 Codeplex页面现在在这里:http://extensionoverflow.codeplex.com/
11.11.2008 XmlSerialize / XmlDeserialize现在是实现和单元测试。
11.11.2008仍有发展空间。;-)现在就加入!
11.11.2008第三位贡献者加入了ExtensionOverflow,欢迎加入BKristensen
11.11.2008 FormatWith现在是实现和单元测试。
09.11.2008第二个贡献者加入ExtensionOverflow。欢迎来到chakrit。
我们需要更多的开发人员。: -)
09.11.2008 ThrowIfArgumentIsNull现已在Codeplex上实现和单元测试。
public static class EnumerableExtensions
{
[Pure]
public static U MapReduce<T, U>(this IEnumerable<T> enumerable, Func<T, U> map, Func<U, U, U> reduce)
{
CodeContract.RequiresAlways(enumerable != null);
CodeContract.RequiresAlways(enumerable.Skip(1).Any());
CodeContract.RequiresAlways(map != null);
CodeContract.RequiresAlways(reduce != null);
return enumerable.AsParallel().Select(map).Aggregate(reduce);
}
[Pure]
public static U MapReduce<T, U>(this IList<T> list, Func<T, U> map, Func<U, U, U> reduce)
{
CodeContract.RequiresAlways(list != null);
CodeContract.RequiresAlways(list.Count >= 2);
CodeContract.RequiresAlways(map != null);
CodeContract.RequiresAlways(reduce != null);
U result = map(list[0]);
for (int i = 1; i < list.Count; i++)
{
result = reduce(result,map(list[i]));
}
return result;
}
//Parallel version; creates garbage
[Pure]
public static U MapReduce<T, U>(this IList<T> list, Func<T, U> map, Func<U, U, U> reduce)
{
CodeContract.RequiresAlways(list != null);
CodeContract.RequiresAlways(list.Skip(1).Any());
CodeContract.RequiresAlways(map != null);
CodeContract.RequiresAlways(reduce != null);
U[] mapped = new U[list.Count];
Parallel.For(0, mapped.Length, i =>
{
mapped[i] = map(list[i]);
});
U result = mapped[0];
for (int i = 1; i < list.Count; i++)
{
result = reduce(result, mapped[i]);
}
return result;
}
}
获取一个camelCaseWord或PascalCaseWord并将其“Word化”,即camelCaseWord => camelCaseWord
public static string Wordify( this string camelCaseWord )
{
// if the word is all upper, just return it
if( !Regex.IsMatch( camelCaseWord, "[a-z]" ) )
return camelCaseWord;
return string.Join( " ", Regex.Split( camelCaseWord, @"(?<!^)(?=[A-Z])" ) );
}
我经常将它与大写字母结合使用
public static string Capitalize( this string word )
{
return word[0].ToString( ).ToUpper( ) + word.Substring( 1 );
}
示例使用
SomeEntityObject entity = DataAccessObject.GetSomeEntityObject( id );
List<PropertyInfo> properties = entity.GetType().GetPublicNonCollectionProperties( );
// wordify the property names to act as column headers for an html table or something
List<string> columns = properties.Select( p => p.Name.Capitalize( ).Wordify( ) ).ToList( );
在codeplex项目中免费使用
字符串。格式的快捷方式:
public static class StringExtensions
{
// Enable quick and more natural string.Format calls
public static string F(this string s, params object[] args)
{
return string.Format(s, args);
}
}
例子:
var s = "The co-ordinate is ({0}, {1})".F(point.X, point.Y);
要快速复制粘贴,请点击这里。
难道你不觉得输入“一些字符串”. f(“param”)而不是字符串更自然吗?格式(“一些字符串”,“参数”)?
想要一个更容易读懂的名字,试试下面的建议:
s = "Hello {0} world {1}!".Fmt("Stack", "Overflow");
s = "Hello {0} world {1}!".FormatBy("Stack", "Overflow");
s = "Hello {0} world {1}!".FormatWith("Stack", "Overflow");
s = "Hello {0} world {1}!".Display("Stack", "Overflow");
s = "Hello {0} world {1}!".With("Stack", "Overflow");
..
For adding multiple elements to a collection that doesn't have AddRange, e.g., collection.Add(item1, item2, itemN);
static void Add<T>(this ICollection<T> coll, params T[] items)
{ foreach (var item in items) coll.Add(item);
}
The following is like string.Format() but with custom string representation of arguments, e.g., "{0} {1} {2}".Format<Custom>(c=>c.Name,"string",new object(),new Custom()) results in "string {System.Object} Custom1Name"
static string Format<T>( this string format
, Func<T,object> select
, params object[] args)
{ for(int i=0; i < args.Length; ++i)
{ var x = args[i] as T;
if (x != null) args[i] = select(x);
}
return string.Format(format, args);
}