我经常用这个来表示可为空的数字。我帮助用0,NaN，无穷大…

public static bool IsNullOrDefault<T>(this T? o) 
    where T : struct
{
        return o == null || o.Value.Equals(default(T));
}

我喜欢下面这些方法来处理带有Flags属性集的枚举:

public static bool AnyOf(this object mask, object flags)
{
    return ((int)mask & (int)flags) != 0;
}
public static bool AllOf(this object mask, object flags)
{
    return ((int)mask & (int)flags) == (int)flags;
}
public static object SetOn(this object mask, object flags)
{
    return (int)mask | (int)flags;
}
etc.

使用示例:

var options = SomeOptions.OptionA;
options = options.SetOn(OptionB);
options = options.SetOn(OptionC);

if (options.AnyOf(SomeOptions.OptionA | SomeOptions.OptionB))
{
etc.

原始方法来自本文:http://www.codeproject.com/KB/cs/masksandflags.aspx?display=Print 我只是把它们转换成扩展方法。

但它们的一个问题是对象类型的参数，这意味着所有对象最终都被这些方法扩展，而理想情况下，它们应该只应用于枚举。

更新 根据评论，你可以绕过“签名污染”，以牺牲性能为代价，如下所示:

public static bool AnyOf(this Enum mask, object flags)
{
    return (Convert.ToInt642(mask) & (int)flags) != 0;
}

public static class EnumerableExtensions
{
    [Pure]
    public static U MapReduce<T, U>(this IEnumerable<T> enumerable, Func<T, U> map, Func<U, U, U> reduce)
    {
        CodeContract.RequiresAlways(enumerable != null);
        CodeContract.RequiresAlways(enumerable.Skip(1).Any());
        CodeContract.RequiresAlways(map != null);
        CodeContract.RequiresAlways(reduce != null);
        return enumerable.AsParallel().Select(map).Aggregate(reduce);
    }
    [Pure]
    public static U MapReduce<T, U>(this IList<T> list, Func<T, U> map, Func<U, U, U> reduce)
    {
        CodeContract.RequiresAlways(list != null);
        CodeContract.RequiresAlways(list.Count >= 2);
        CodeContract.RequiresAlways(map != null);
        CodeContract.RequiresAlways(reduce != null);
        U result = map(list[0]);
        for (int i = 1; i < list.Count; i++)
        {
            result = reduce(result,map(list[i]));
        }
        return result;
    }

    //Parallel version; creates garbage
    [Pure]
    public static U MapReduce<T, U>(this IList<T> list, Func<T, U> map, Func<U, U, U> reduce)
    {
        CodeContract.RequiresAlways(list != null);
        CodeContract.RequiresAlways(list.Skip(1).Any());
        CodeContract.RequiresAlways(map != null);
        CodeContract.RequiresAlways(reduce != null);

        U[] mapped = new U[list.Count];
        Parallel.For(0, mapped.Length, i =>
            {
                mapped[i] = map(list[i]);
            });
        U result = mapped[0];
        for (int i = 1; i < list.Count; i++)
        {
            result = reduce(result, mapped[i]);
        }
        return result;
    }

}

相当于Python的Join方法:

/// <summary>
/// same as python 'join'
/// </summary>
/// <typeparam name="T">list type</typeparam>
/// <param name="separator">string separator </param>
/// <param name="list">list of objects to be ToString'd</param>
/// <returns>a concatenated list interleaved with separators</returns>
static public string Join<T>(this string separator, IEnumerable<T> list)
{
    var sb = new StringBuilder();
    bool first = true;

    foreach (T v in list)
    {
        if (!first)
            sb.Append(separator);
        first = false;

        if (v != null)
            sb.Append(v.ToString());
    }

    return sb.ToString();
}

我发现自己一遍又一遍地这样做……

public static bool EqualsIgnoreCase(this string a, string b)
{
    return string.Equals(a, b, StringComparison.OrdinalIgnoreCase);
}

.．.然后是StartsWithIgnoreCase, EndsWithIgnoreCase和ContainsIgnoreCase。

我使用这个扩展方法通常与匿名类型，以获得一个字典ala ruby

public static Dictionary<string, object> ToDictionary(this object o)
{
    var dictionary = new Dictionary<string, object>();

    foreach (var propertyInfo in o.GetType().GetProperties())
    {
        if (propertyInfo.GetIndexParameters().Length == 0)
        {
            dictionary.Add(propertyInfo.Name, propertyInfo.GetValue(o, null));
        }
    }

    return dictionary;
}

你可以使用它

var dummy = new { color = "#000000", width = "100%", id = "myid" };
Dictionary<string, object> dict = dummy.ToDictionary();

用扩展的方法

public static void ForEach<T>(this IEnumerable<T> source, Action<T> action)
{
    foreach (T item in source)
    {
        action(item);
    }
}

你可以做到的

dummy.ToDictionary().ForEach((p) => Console.Write("{0}='{1}' ", p.Key, p.Value));

输出

Color ='#000000' width='100%' id='myid'