我已经开发了一个随机字符串生成器,但它的行为并不像我所希望的那样。我的目标是能够运行两次,并生成两个不同的四字符随机字符串。但是,它只生成一个四个字符的随机字符串两次。

下面是代码和输出示例:

private string RandomString(int size)
{
    StringBuilder builder = new StringBuilder();
    Random random = new Random();
    char ch;
    for (int i = 0; i < size; i++)
    {
        ch = Convert.ToChar(Convert.ToInt32(Math.Floor(26 * random.NextDouble() + 65)));                 
        builder.Append(ch);
    }

    return builder.ToString();
}

// get 1st random string 
string Rand1 = RandomString(4);

// get 2nd random string 
string Rand2 = RandomString(4);

// create full rand string
string docNum = Rand1 + "-" + Rand2;

...输出如下:UNTE-UNTE ...但它应该看起来像这个UNTE-FWNU

如何确保两个明显随机的字符串?


当前回答

还有另一个版本:我在测试中使用这种方法生成随机的伪股票代码:

Random rand = new Random();
Func<char> randChar = () => (char)rand.Next(65, 91); // upper case ascii codes
Func<int,string> randStr = null;
    randStr = (x) => (x>0) ? randStr(--x)+randChar() : ""; // recursive

用法:

string str4 = randStr(4);// generates a random 4 char string
string strx = randStr(rand.next(1,5)); // random string between 1-4 chars in length

你可以重新定义randChar函数,使用一个“允许的”字符数组,而不是ascii码:

char[] allowedchars = {'A','B','C','1','2','3'};
Func<char> randChar = () => allowedchars[rand.Next(0, allowedchars.Length-1)];

其他回答

只要你使用Asp。Net 2.0或更高版本,也可以使用库调用- System.Web.Security.Membership。生成密码,但它将包括特殊字符。

要获得4个随机字符,其中至少有0个特殊字符-

Membership.GeneratePassword(4, 0)

一个使用Path.GetRandomFileName()的非常简单的实现:

using System.IO;   
public static string RandomStr()
{
    string rStr = Path.GetRandomFileName();
    rStr = rStr.Replace(".", ""); // For Removing the .
    return rStr;
}

现在只需调用RandomStr()。

如果您想为强密码生成一串数字和字符。

private static Random random = new Random();

private static string CreateTempPass(int size)
        {
            var pass = new StringBuilder();
            for (var i=0; i < size; i++)
            {
                var binary = random.Next(0,2);
                switch (binary)
                {
                    case 0:
                    var ch = (Convert.ToChar(Convert.ToInt32(Math.Floor(26*random.NextDouble() + 65))));
                        pass.Append(ch);
                        break;
                    case 1:
                        var num = random.Next(1, 10);
                        pass.Append(num);
                        break;
                }
            }
            return pass.ToString();
        }

您正在该方法中创建Random实例,这将导致它在快速连续调用时返回相同的值。我会这样做:

private static Random random = new Random((int)DateTime.Now.Ticks);//thanks to McAden
private string RandomString(int size)
    {
        StringBuilder builder = new StringBuilder();
        char ch;
        for (int i = 0; i < size; i++)
        {
            ch = Convert.ToChar(Convert.ToInt32(Math.Floor(26 * random.NextDouble() + 65)));                 
            builder.Append(ch);
        }

        return builder.ToString();
    }

// get 1st random string 
string Rand1 = RandomString(4);

// get 2nd random string 
string Rand2 = RandomString(4);

// creat full rand string
string docNum = Rand1 + "-" + Rand2;

(修改后的代码版本)

这里还有一个选择:

public System.String GetRandomString(System.Int32 length)
{
    System.Byte[] seedBuffer = new System.Byte[4];
    using (var rngCryptoServiceProvider = new System.Security.Cryptography.RNGCryptoServiceProvider())
    {
        rngCryptoServiceProvider.GetBytes(seedBuffer);
        System.String chars = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789";
        System.Random random = new System.Random(System.BitConverter.ToInt32(seedBuffer, 0));
        return new System.String(Enumerable.Repeat(chars, length).Select(s => s[random.Next(s.Length)]).ToArray());
    }
}