我真的在努力把一个JSON文件读入Swift，这样我就可以玩它了。我花了2天的时间重新搜索和尝试不同的方法，但没有运气，所以我已经注册了StackOverFlow，看看是否有人能给我指点正确的方向.....
我的JSON文件叫做test。Json，并包含以下内容:
{
"person":[
{
"name": "Bob",
"age": "16",
"employed": "No"
},
{
"name": "Vinny",
"age": "56",
"employed": "Yes"
}
]
}
该文件直接存储在文档中，我使用以下代码访问它:
let file = "test.json"
let dirs : String[] = NSSearchPathForDirectoriesInDomains(
NSSearchpathDirectory.DocumentDirectory,
NSSearchPathDomainMask.AllDomainMask,
true) as String[]
if (dirs != nil) {
let directories: String[] = dirs
let dir = directories[0]
let path = dir.stringByAppendingPathComponent(file)
}
var jsonData = NSData(contentsOfFile:path, options: nil, error: nil)
println("jsonData \(jsonData)" // This prints what looks to be JSON encoded data.
var jsonDict = NSJSONSerialization.JSONObjectWithData(jsonData, options: nil, error: nil) as? NSDictionary
println("jsonDict \(jsonDict)") - This prints nil.....
如果有人能给我一个正确的方向，我可以反序列化JSON文件，并把它放在一个可访问的Swift对象，我会永远感激!
亲切的问候,
Krivvenz。
遵循以下代码:
if let path = NSBundle.mainBundle().pathForResource("test", ofType: "json")
{
if let jsonData = NSData(contentsOfFile: path, options: .DataReadingMappedIfSafe, error: nil)
{
if let jsonResult: NSDictionary = NSJSONSerialization.JSONObjectWithData(jsonData, options: NSJSONReadingOptions.MutableContainers, error: nil) as? NSDictionary
{
if let persons : NSArray = jsonResult["person"] as? NSArray
{
// Do stuff
}
}
}
}
数组“persons”将包含关键人物的所有数据。遍历获取它。
斯威夫特4.0:
if let path = Bundle.main.path(forResource: "test", ofType: "json") {
do {
let data = try Data(contentsOf: URL(fileURLWithPath: path), options: .mappedIfSafe)
let jsonResult = try JSONSerialization.jsonObject(with: data, options: .mutableLeaves)
if let jsonResult = jsonResult as? Dictionary<String, AnyObject>, let person = jsonResult["person"] as? [Any] {
// do stuff
}
} catch {
// handle error
}
}
斯威夫特4。X和5。x使用可解码
struct ResponseData: Decodable {
var person: [Person]
}
struct Person : Decodable {
var name: String
var age: String
var employed: String
}
func loadJson(filename fileName: String) -> [Person]? {
if let url = Bundle.main.url(forResource: fileName, withExtension: "json") {
do {
let data = try Data(contentsOf: url)
let decoder = JSONDecoder()
let jsonData = try decoder.decode(ResponseData.self, from: data)
return jsonData.person
} catch {
print("error:\(error)")
}
}
return nil
}
斯威夫特3
func loadJson(filename fileName: String) -> [String: AnyObject]? {
if let url = Bundle.main.url(forResource: fileName, withExtension: "json") {
do {
let data = try Data(contentsOf: url)
let object = try JSONSerialization.jsonObject(with: data, options: .allowFragments)
if let dictionary = object as? [String: AnyObject] {
return dictionary
}
} catch {
print("Error!! Unable to parse \(fileName).json")
}
}
return nil
}
我使用下面的代码从FAQ-data中获取JSON。Json文件存在于项目目录中。
我在Xcode 7.3中使用Swift实现。
func fetchJSONContent() {
if let path = NSBundle.mainBundle().pathForResource("FAQ-data", ofType: "json") {
if let jsonData = NSData(contentsOfFile: path) {
do {
if let jsonResult: NSDictionary = try NSJSONSerialization.JSONObjectWithData(jsonData, options: NSJSONReadingOptions.MutableContainers) as? NSDictionary {
if let responseParameter : NSDictionary = jsonResult["responseParameter"] as? NSDictionary {
if let response : NSArray = responseParameter["FAQ"] as? NSArray {
responseFAQ = response
print("response FAQ : \(response)")
}
}
}
}
catch { print("Error while parsing: \(error)") }
}
}
}
override func viewWillAppear(animated: Bool) {
fetchFAQContent()
}
JSON文件结构:
{
"status": "00",
"msg": "FAQ List ",
"responseParameter": {
"FAQ": [
{
"question": “Question No.1 here”,
"answer": “Answer goes here”,
"id": 1
},
{
"question": “Question No.2 here”,
"answer": “Answer goes here”,
"id": 2
}
. . .
]
}
}
我可能还会推荐Ray Wenderlich的Swift JSON教程(它还涵盖了很棒的SwiftyJSON替代品，Gloss)。一段摘录(它本身并不能完全回答海报上的问题，但这个答案的附加价值是链接，所以请不要给它加-1):
在Objective-C中，解析和反序列化JSON相当简单:
NSArray *json = [NSJSONSerialization JSONObjectWithData:JSONData
options:kNilOptions error:nil];
NSString *age = json[0][@"person"][@"age"];
NSLog(@"Dani's age is %@", age);
在Swift中，由于Swift的可选选项和类型安全，解析和反序列化JSON有点繁琐，但作为Swift 2.0的一部分，guard语句被引入，以帮助摆脱嵌套的if语句:
var json: Array!
do {
json = try NSJSONSerialization.JSONObjectWithData(JSONData, options: NSJSONReadingOptions()) as? Array
} catch {
print(error)
}
guard let item = json[0] as? [String: AnyObject],
let person = item["person"] as? [String: AnyObject],
let age = person["age"] as? Int else {
return;
}
print("Dani's age is \(age)")
当然，在XCode 8中。x，你只需双击空格键，然后说“嘿，Siri，请在Swift 3.0中用空格/制表符缩进为我反序列化这个JSON。”
Swift 3.0, Xcode 8, iOS 10
if let path = Bundle.main.url(forResource: "person", withExtension: "json") {
do {
let jsonData = try Data(contentsOf: path, options: .mappedIfSafe)
do {
if let jsonResult = try JSONSerialization.jsonObject(with: jsonData, options: JSONSerialization.ReadingOptions(rawValue: 0)) as? NSDictionary {
if let personArray = jsonResult.value(forKey: "person") as? NSArray {
for (_, element) in personArray.enumerated() {
if let element = element as? NSDictionary {
let name = element.value(forKey: "name") as! String
let age = element.value(forKey: "age") as! String
let employed = element.value(forKey: "employed") as! String
print("Name: \(name), age: \(age), employed: \(employed)")
}
}
}
}
} catch let error as NSError {
print("Error: \(error)")
}
} catch let error as NSError {
print("Error: \(error)")
}
}
输出:
Name: Bob, age: 16, employed: No
Name: Vinny, age: 56, employed: Yes
首先像这样创建一个可编码的Struc:
struct JuzgadosList : Codable {
var CP : Int
var TEL : String
var LOCAL : String
var ORGANO : String
var DIR : String
}
现在声明变量
var jzdosList = [JuzgadosList]()
从主目录读取
func getJsonFromDirectory() {
if let path = Bundle.main.path(forResource: "juzgados", ofType: "json") {
do {
let data = try Data(contentsOf: URL(fileURLWithPath: path), options: .alwaysMapped)
let jList = try JSONDecoder().decode([JuzgadosList].self, from: data)
self.jzdosList = jList
DispatchQueue.main.async() { () -> Void in
self.tableView.reloadData()
}
} catch let error {
print("parse error: \(error.localizedDescription)")
}
} else {
print("Invalid filename/path.")
}
}
网上阅读
func getJsonFromUrl(){
self.jzdosList.removeAll(keepingCapacity: false)
print("Internet Connection Available!")
guard let url = URL(string: "yourURL") else { return }
let request = URLRequest(url: url, cachePolicy: URLRequest.CachePolicy.reloadIgnoringLocalCacheData, timeoutInterval: 60.0)
URLSession.shared.dataTask(with: request) { (data, response, err) in
guard let data = data else { return }
do {
let jList = try JSONDecoder().decode([JuzgadosList].self, from: data)
self.jzdosList = jList
DispatchQueue.main.async() { () -> Void in
self.tableView.reloadData()
}
} catch let jsonErr {
print("Error serializing json:", jsonErr)
}
}.resume()
}
Swift 4:试试我的解决方案:
test.json
{
"person":[
{
"name": "Bob",
"age": "16",
"employed": "No"
},
{
"name": "Vinny",
"age": "56",
"employed": "Yes"
}
]
}
RequestCodable.swift
import Foundation
struct RequestCodable:Codable {
let person:[PersonCodable]
}
PersonCodable.swift
import Foundation
struct PersonCodable:Codable {
let name:String
let age:String
let employed:String
}
可解码+ FromJSON.swift
import Foundation
extension Decodable {
static func fromJSON<T:Decodable>(_ fileName: String, fileExtension: String="json", bundle: Bundle = .main) throws -> T {
guard let url = bundle.url(forResource: fileName, withExtension: fileExtension) else {
throw NSError(domain: NSURLErrorDomain, code: NSURLErrorResourceUnavailable)
}
let data = try Data(contentsOf: url)
return try JSONDecoder().decode(T.self, from: data)
}
}
例子:
let result = RequestCodable.fromJSON("test") as RequestCodable?
result?.person.compactMap({ print($0) })
/*
PersonCodable(name: "Bob", age: "16", employed: "No")
PersonCodable(name: "Vinny", age: "56", employed: "Yes")
*/
简化Peter Kreinz提供的例子。适用于Swift 4.2。
扩展函数:
extension Decodable {
static func parse(jsonFile: String) -> Self? {
guard let url = Bundle.main.url(forResource: jsonFile, withExtension: "json"),
let data = try? Data(contentsOf: url),
let output = try? JSONDecoder().decode(self, from: data)
else {
return nil
}
return output
}
}
示例模型:
struct Service: Decodable {
let name: String
}
示例用法:
/// service.json
/// { "name": "Home & Garden" }
guard let output = Service.parse(jsonFile: "service") else {
// do something if parsing failed
return
}
// use output if all good
这个例子也适用于数组:
/// services.json
/// [ { "name": "Home & Garden" } ]
guard let output = [Service].parse(jsonFile: "services") else {
// do something if parsing failed
return
}
// use output if all good
注意，我们没有提供任何不必要的泛型，因此不需要强制转换parse的结果。
使用这个泛型函数
func readJSONFromFile<T: Decodable>(fileName: String, type: T.Type) -> T? {
if let url = Bundle.main.url(forResource: fileName, withExtension: "json") {
do {
let data = try Data(contentsOf: url)
let decoder = JSONDecoder()
let jsonData = try decoder.decode(T.self, from: data)
return jsonData
} catch {
print("error:\(error)")
}
}
return nil
}
下面这行代码:
let model = readJSONFromFile(fileName: "Model", type: Model.self)
对于这种类型:
struct Model: Codable {
let tall: Int
}
在清理和抛光我的代码之后，我来到了这两个函数，你可以添加到你的项目中，并使用它们非常整洁和快速地从json文件读取数据，并将数据转换为你想要的任何类型!
public func readDataRepresentationFromFile(resource: String, type: String) -> Data? {
let filePath = Bundle.main.path(forResource: resource, ofType: type)
if let path = filePath {
let result = FileManager.default.contents(atPath: path)
return result
}
return nil
}
然后在这个函数的帮助下，你可以将你的数据转换为任何你想要的类型:
public func getObject<T: Codable>(of type: T.Type, from file: String) -> T? {
guard let data = readDataRepresentationFromFile(resource: file, type: "json") else {
return nil
}
if let object = try? JSONDecoder().decode(type, from: data) {
return object
}
return nil
}
此代码的应用示例:
在你的代码中调用这个函数，给它你的json文件的名字，这就是你所需要的!
func getInputDataFromSomeJson(jsonFileName: String) -> YourReqiuredOutputType? {
return getObject(of: YourReqiuredOutputType.self, from: jsonFileName)
}
斯威夫特 5+
用Struct解码jsonData
if let jsonData = readFile(forName: <your file name>) {
do {
let decodedData = try JSONDecoder().decode(<your struct name>.self, from: jsonData)
return decodedData.<what you expect>
} catch { print("JSON decode error") }
}
这将读取文件并返回jsonData
如果你实际上在另一个bundle中(例如test)，使用:
let bundlePath = Bundle(for: type(of: self))。路径(forResource: name, ofType: "json")
private func readFile(forName name: String) -> Data? {
do {
if let bundlePath = Bundle.main.path(forResource: name, ofType: "json"),
let jsonData = try String(contentsOfFile: bundlePath).data(using: .utf8) {
return jsonData
}
} catch {
print(error)
}
return nil
}
这里还有一个答案??
好的。坚持住!之前所有的答案都是关于使用JSONSerialization，或返回nil，或忽略错误。
有什么不同
“我的解决方案”(不是真的我的解决方案，这是上述解决方案的混合)包含:
返回值的现代方法:Result<Value,Error>(返回值或错误)
避免使用空值
包含一个稍微详细的错误
使用扩展有漂亮/直观的界面:
提供了选择包的可能性
细节
Xcode 14
斯威夫特5.6.1
解决方案1。JSON文件->可解码
enum JSONParseError: Error {
case fileNotFound
case dataInitialisation(error: Error)
case decoding(error: Error)
}
extension Decodable {
static func from(localJSON filename: String,
bundle: Bundle = .main) -> Result<Self, JSONParseError> {
guard let url = bundle.url(forResource: filename, withExtension: "json") else {
return .failure(.fileNotFound)
}
let data: Data
do {
data = try Data(contentsOf: url)
} catch let error {
return .failure(.dataInitialisation(error: error))
}
do {
return .success(try JSONDecoder().decode(self, from: data))
} catch let error {
return .failure(.decoding(error: error))
}
}
}
方案一用途
struct Model: Decodable {
let uuid: String
let name: String
}
switch Model.from(localJSON: "myjsonfile") {
case .success(let value):
print(value)
case .failure(let error):
print(error)
}
解决方案2。JSON文件->字典
extension Dictionary where Key == String, Value == Any {
enum JSONParseError: Error {
case fileNotFound(filename: String)
case dataInitialisation(Error)
case jsonSerialization(Error)
case mappingFail(value: Any, toType: Any)
}
static func from(JSONfile url: URL) -> Result<Self, JSONParseError> {
let data: Data
do {
data = try Data(contentsOf: url)
} catch let error {
return .failure(.dataInitialisation(error))
}
let jsonObject: Any
do {
jsonObject = try JSONSerialization.jsonObject(with: data, options: .mutableLeaves)
} catch let error {
return .failure(.jsonSerialization(error))
}
guard let jsonResult = jsonObject as? Self else {
return .failure(.mappingFail(value: jsonObject, toType: Self.Type.self))
}
return .success(jsonResult)
}
static func from(localJSONfile name: String) -> Result<Self, JSONParseError> {
let fileType = "json"
let fullFileName = name + (name.contains(fileType) ? "" : ".\(fileType)")
guard let path = Bundle.main.path(forResource: fullFileName, ofType: "") else {
return .failure(.fileNotFound(filename: fullFileName))
}
return from(JSONfile: URL(fileURLWithPath: path))
}
}
方案二使用
switch [String: Any].from(localJSONfile: "file.json") {
// OR switch [String: Any].from(localJSONfile: "file.json") {
// OR switch [String: Any].from(JSONfile: url) {
case let .success(dictionary):
print(dictionary)
case let .failure(error):
print("ERROR: \(error)")
}
