//change type based on your struct and right JSON file

let quoteData: [DataType] =
    load("file.json")

func load<T: Decodable>(_ filename: String, as type: T.Type = T.self) -> T {
    let data: Data

    guard let file = Bundle.main.url(forResource: filename, withExtension: nil)
        else {
            fatalError("Couldn't find \(filename) in main bundle.")
    }

    do {
        data = try Data(contentsOf: file)
    } catch {
        fatalError("Couldn't load \(filename) from main bundle:\n\(error)")
    }

    do {
        let decoder = JSONDecoder()
        return try decoder.decode(T.self, from: data)
    } catch {
        fatalError("Couldn't parse \(filename) as \(T.self):\n\(error)")
    }
}

对于那些希望在decodedable抛出错误后在调试器/ lldb中打印JSON数据的人，请尝试以下方法。

阿宝试试!JSONSerialization。jsonObject(:数据!，选项:.mutableLeaves) as?字典<字符串,任何>

Swift 4 JSON类与可解码-为那些喜欢类

定义类如下:

class People: Decodable {
  var person: [Person]?

  init(fileName : String){
    // url, data and jsonData should not be nil
    guard let url = Bundle.main.url(forResource: fileName, withExtension: "json") else { return }
    guard let data = try? Data(contentsOf: url) else { return }
    guard let jsonData = try? JSONDecoder().decode(People.self, from: data) else { return }

    // assigns the value to [person]
    person = jsonData.person
  }
}

class Person : Decodable {
  var name: String
  var age: String
  var employed: String
}

用法，非常抽象:

let people = People(fileName: "people")
let personArray = people.person

这允许People类和Person类的方法，如果需要，变量(属性)和方法也可以标记为private。

Swift 5.1, Xcode 11

你可以用这个:

struct Person : Codable {
    let name: String
    let lastName: String
    let age: Int
}

func loadJson(fileName: String) -> Person? {
   let decoder = JSONDecoder()
   guard
        let url = Bundle.main.url(forResource: fileName, withExtension: "json"),
        let data = try? Data(contentsOf: url),
        let person = try? decoder.decode(Person.self, from: data)
   else {
        return nil
   }

   return person
}

下面是我使用SwiftyJSON的解决方案

if let path : String = NSBundle.mainBundle().pathForResource("filename", ofType: "json") {
    if let data = NSData(contentsOfFile: path) {

        let json = JSON(data: data)

    }
}

我使用下面的代码从FAQ-data中获取JSON。Json文件存在于项目目录中。

我在Xcode 7.3中使用Swift实现。

     func fetchJSONContent() {
            if let path = NSBundle.mainBundle().pathForResource("FAQ-data", ofType: "json") {

                if let jsonData = NSData(contentsOfFile: path) {
                    do {
                        if let jsonResult: NSDictionary = try NSJSONSerialization.JSONObjectWithData(jsonData, options: NSJSONReadingOptions.MutableContainers) as? NSDictionary {

                            if let responseParameter : NSDictionary = jsonResult["responseParameter"] as? NSDictionary {

                                if let response : NSArray = responseParameter["FAQ"] as? NSArray {
                                    responseFAQ = response
                                    print("response FAQ : \(response)")
                                }
                            }
                        }
                    }
                    catch { print("Error while parsing: \(error)") }
                }
            }
        }

override func viewWillAppear(animated: Bool) {
        fetchFAQContent()
    }

JSON文件结构:

{
    "status": "00",
    "msg": "FAQ List ",
    "responseParameter": {
        "FAQ": [
            {                
                "question": “Question No.1 here”,
                "answer": “Answer goes here”,  
                "id": 1
            },
            {                
                "question": “Question No.2 here”,
                "answer": “Answer goes here”,
                "id": 2
            }
            . . .
        ]
    }
}