我真的在努力把一个JSON文件读入Swift,这样我就可以玩它了。我花了2天的时间重新搜索和尝试不同的方法,但没有运气,所以我已经注册了StackOverFlow,看看是否有人能给我指点正确的方向.....

我的JSON文件叫做test。Json,并包含以下内容:

{
  "person":[
     {
       "name": "Bob",
       "age": "16",
       "employed": "No"
     },
     {
       "name": "Vinny",
       "age": "56",
       "employed": "Yes"
     }
  ]
}    

该文件直接存储在文档中,我使用以下代码访问它:

let file = "test.json"
let dirs : String[] = NSSearchPathForDirectoriesInDomains(
                                                          NSSearchpathDirectory.DocumentDirectory,
                                                          NSSearchPathDomainMask.AllDomainMask,
                                                          true) as String[]

if (dirs != nil) {
    let directories: String[] = dirs
    let dir = directories[0]
    let path = dir.stringByAppendingPathComponent(file)
}

var jsonData = NSData(contentsOfFile:path, options: nil, error: nil)
println("jsonData \(jsonData)" // This prints what looks to be JSON encoded data.

var jsonDict = NSJSONSerialization.JSONObjectWithData(jsonData, options: nil, error: nil) as? NSDictionary

println("jsonDict \(jsonDict)") - This prints nil..... 

如果有人能给我一个正确的方向,我可以反序列化JSON文件,并把它放在一个可访问的Swift对象,我会永远感激!

亲切的问候,

Krivvenz。


当前回答

Swift 5.1, Xcode 11

你可以用这个:


struct Person : Codable {
    let name: String
    let lastName: String
    let age: Int
}

func loadJson(fileName: String) -> Person? {
   let decoder = JSONDecoder()
   guard
        let url = Bundle.main.url(forResource: fileName, withExtension: "json"),
        let data = try? Data(contentsOf: url),
        let person = try? decoder.decode(Person.self, from: data)
   else {
        return nil
   }

   return person
}

其他回答

如果有人正在寻找SwiftyJSON答案: 更新: 对于Swift 3/4:

if let path = Bundle.main.path(forResource: "assets/test", ofType: "json") {
    do {
        let data = try Data(contentsOf: URL(fileURLWithPath: path), options: .alwaysMapped)
        let jsonObj = try JSON(data: data)
        print("jsonData:\(jsonObj)")
    } catch let error {
        print("parse error: \(error.localizedDescription)")
    }
} else {
    print("Invalid filename/path.")
}

遵循以下代码:

if let path = NSBundle.mainBundle().pathForResource("test", ofType: "json")
{
    if let jsonData = NSData(contentsOfFile: path, options: .DataReadingMappedIfSafe, error: nil)
    {
        if let jsonResult: NSDictionary = NSJSONSerialization.JSONObjectWithData(jsonData, options: NSJSONReadingOptions.MutableContainers, error: nil) as? NSDictionary
        {
            if let persons : NSArray = jsonResult["person"] as? NSArray
            {
                // Do stuff
            }
        }
     }
}

数组“persons”将包含关键人物的所有数据。遍历获取它。

斯威夫特4.0:

if let path = Bundle.main.path(forResource: "test", ofType: "json") {
    do {
          let data = try Data(contentsOf: URL(fileURLWithPath: path), options: .mappedIfSafe)
          let jsonResult = try JSONSerialization.jsonObject(with: data, options: .mutableLeaves)
          if let jsonResult = jsonResult as? Dictionary<String, AnyObject>, let person = jsonResult["person"] as? [Any] {
                    // do stuff
          }
      } catch {
           // handle error
      }
}

首先像这样创建一个可编码的Struc:

  struct JuzgadosList : Codable {
    var CP : Int
    var TEL : String
    var LOCAL : String
    var ORGANO : String
    var DIR : String
}

现在声明变量

 var jzdosList = [JuzgadosList]()

从主目录读取

func getJsonFromDirectory() {

        if let path = Bundle.main.path(forResource: "juzgados", ofType: "json") {
            do {
                let data = try Data(contentsOf: URL(fileURLWithPath: path), options: .alwaysMapped)
                let jList = try JSONDecoder().decode([JuzgadosList].self, from: data)
                self.jzdosList = jList

                DispatchQueue.main.async() { () -> Void in
                    self.tableView.reloadData()
                }

            } catch let error {
                print("parse error: \(error.localizedDescription)")
            }
        } else {
            print("Invalid filename/path.")
        }
    }

网上阅读

func getJsonFromUrl(){

        self.jzdosList.removeAll(keepingCapacity: false)

        print("Internet Connection Available!")

        guard let url = URL(string: "yourURL")  else { return }

        let request = URLRequest(url: url, cachePolicy: URLRequest.CachePolicy.reloadIgnoringLocalCacheData, timeoutInterval: 60.0)
        URLSession.shared.dataTask(with: request) { (data, response, err) in
            guard let data = data else { return }
            do {
                let jList = try JSONDecoder().decode([JuzgadosList].self, from: data)
                self.jzdosList = jList

                DispatchQueue.main.async() { () -> Void in
                    self.tableView.reloadData()
                }
            } catch let jsonErr {
                print("Error serializing json:", jsonErr)
            }
        }.resume()
    }

这在XCode 8.3.3中是可行的

func fetchPersons(){

    if let pathURL = Bundle.main.url(forResource: "Person", withExtension: "json"){

        do {

            let jsonData = try Data(contentsOf: pathURL, options: .mappedIfSafe)

            let jsonResult = try JSONSerialization.jsonObject(with: jsonData, options: .mutableContainers) as! [String: Any]
            if let persons = jsonResult["person"] as? [Any]{

                print(persons)
            }

        }catch(let error){
            print (error.localizedDescription)
        }
    }
}

这里还有一个答案??

好的。坚持住!之前所有的答案都是关于使用JSONSerialization,或返回nil,或忽略错误。

有什么不同

“我的解决方案”(不是真的我的解决方案,这是上述解决方案的混合)包含:

返回值的现代方法:Result<Value,Error>(返回值或错误) 避免使用空值 包含一个稍微详细的错误 使用扩展有漂亮/直观的界面: 提供了选择包的可能性

细节

Xcode 14 斯威夫特5.6.1

解决方案1。JSON文件->可解码

enum JSONParseError: Error {
    case fileNotFound
    case dataInitialisation(error: Error)
    case decoding(error: Error)
}

extension Decodable {
    static func from(localJSON filename: String,
                     bundle: Bundle = .main) -> Result<Self, JSONParseError> {
        guard let url = bundle.url(forResource: filename, withExtension: "json") else {
            return .failure(.fileNotFound)
        }
        let data: Data
        do {
            data = try Data(contentsOf: url)
        } catch let error {
            return .failure(.dataInitialisation(error: error))
        }

        do {
            return .success(try JSONDecoder().decode(self, from: data))
        } catch let error {
            return .failure(.decoding(error: error))
        }
    }
}

方案一用途

 struct Model: Decodable {
    let uuid: String
    let name: String
}

switch Model.from(localJSON: "myjsonfile") {
case .success(let value):
    print(value)
case .failure(let error):
    print(error)
}

解决方案2。JSON文件->字典

extension Dictionary where Key == String, Value == Any {

    enum JSONParseError: Error {
        case fileNotFound(filename: String)
        case dataInitialisation(Error)
        case jsonSerialization(Error)
        case mappingFail(value: Any, toType: Any)
    }

    static func from(JSONfile url: URL) -> Result<Self, JSONParseError> {
        let data: Data
        do {
            data = try Data(contentsOf: url)
        } catch let error {
            return .failure(.dataInitialisation(error))
        }

        let jsonObject: Any
        do {
            jsonObject = try JSONSerialization.jsonObject(with: data, options: .mutableLeaves)
        } catch let error {
            return .failure(.jsonSerialization(error))
        }

        guard let jsonResult = jsonObject as? Self else {
            return .failure(.mappingFail(value: jsonObject, toType: Self.Type.self))
        }

        return .success(jsonResult)
    }

    static func from(localJSONfile name: String) -> Result<Self, JSONParseError> {
        let fileType = "json"
        let fullFileName = name + (name.contains(fileType) ? "" : ".\(fileType)")
        guard let path = Bundle.main.path(forResource: fullFileName, ofType: "") else {
            return .failure(.fileNotFound(filename: fullFileName))
        }
        return from(JSONfile: URL(fileURLWithPath: path))
    }
}

方案二使用

switch [String: Any].from(localJSONfile: "file.json") {
// OR switch [String: Any].from(localJSONfile: "file.json") {
// OR switch [String: Any].from(JSONfile: url) {
case let .success(dictionary):
    print(dictionary)
case let .failure(error):
    print("ERROR: \(error)")
}