我有以下几点:
let mut my_number = 32.90;
如何打印my_number的类型?
使用type和type_of不起作用。有其他方法可以打印数字的类型吗?
我有以下几点:
let mut my_number = 32.90;
如何打印my_number的类型?
使用type和type_of不起作用。有其他方法可以打印数字的类型吗?
当前回答
**更新**最近没有被验证工作。
我把一个小板条箱一起做这个基于vbo的答案。它提供了一个宏来返回或打印类型。
把这个放在你的货物里。toml文件:
[dependencies]
t_bang = "0.1.2"
然后你可以这样使用它:
#[macro_use] extern crate t_bang;
use t_bang::*;
fn main() {
let x = 5;
let x_type = t!(x);
println!("{:?}", x_type); // prints out: "i32"
pt!(x); // prints out: "i32"
pt!(5); // prints out: "i32"
}
其他回答
短篇小说;
fn tyof<T>(_: &T) -> String {
std::any::type_name::<T>().into()
}
很长的故事;
trait Type {
fn type_of(&self) -> String;
}
macro_rules! Type {
($($ty:ty),*) => {
$(
impl Type for $ty {
fn type_of(&self) -> String {
stringify!($ty).into()
}
}
)*
}
}
#[rustfmt::skip]
Type!(
u8, i8, u16, i16, u32, i32, i64, u64, i128, String, [()], (), Vec<()>, &u8, &i8, &u16, &i16, &u32, &i32, &i64, &u64, &i128, &str, &[()], &Vec<()>, &()
// add any struct, enum or type you want
);
macro_rules! tyof {
($var: expr) => {{
$var.type_of()
}};
}
fn main() {
let x = "Hello world!";
println!("{}", tyof!(x));
// or
println!("{}", x.type_of());
let x = 5;
println!("{}", tyof!(x));
// or
println!("{}", x.type_of());
}
我非常喜欢@Coautose之前的回答,但如果有人只想要没有名称空间的类型名称,例如C而不是a::b::C,这里是一个修改后的宏版本,看起来像预期的那样工作:
macro_rules! ty {
($type:ty) => {{
let result = std::any::type_name::<$type>();
match result.rsplit_once(':') {
Some((_, s)) => s,
None => result,
}
}};
}
用法:
debug!("Testing type name: {}", ty!(A));
**更新**最近没有被验证工作。
我把一个小板条箱一起做这个基于vbo的答案。它提供了一个宏来返回或打印类型。
把这个放在你的货物里。toml文件:
[dependencies]
t_bang = "0.1.2"
然后你可以这样使用它:
#[macro_use] extern crate t_bang;
use t_bang::*;
fn main() {
let x = 5;
let x_type = t!(x);
println!("{:?}", x_type); // prints out: "i32"
pt!(x); // prints out: "i32"
pt!(5); // prints out: "i32"
}
更新,原始答案如下
trait函数type_name如何,它对于快速获取类型名称非常有用。
pub trait AnyExt {
fn type_name(&self) -> &'static str;
}
impl<T> AnyExt for T {
fn type_name(&self) -> &'static str {
std::any::type_name::<T>()
}
}
fn main(){
let my_number = 32.90;
println!("{}",my_number.type_name());
}
输出:
f64
原来的答案
我写了一个宏type_of!()来调试,它来自std dbg!()。
pub fn type_of2<T>(v: T) -> (&'static str, T) {
(std::any::type_name::<T>(), v)
}
#[macro_export]
macro_rules! type_of {
// NOTE: We cannot use `concat!` to make a static string as a format argument
// of `eprintln!` because `file!` could contain a `{` or
// `$val` expression could be a block (`{ .. }`), in which case the `eprintln!`
// will be malformed.
() => {
eprintln!("[{}:{}]", file!(), line!());
};
($val:expr $(,)?) => {
// Use of `match` here is intentional because it affects the lifetimes
// of temporaries - https://stackoverflow.com/a/48732525/1063961
match $val {
tmp => {
let (type_,tmp) = $crate::type_of2(tmp);
eprintln!("[{}:{}] {}: {}",
file!(), line!(), stringify!($val), type_);
tmp
}
}
};
($($val:expr),+ $(,)?) => {
($($crate::type_of!($val)),+,)
};
}
fn main(){
let my_number = type_of!(32.90);
type_of!(my_number);
}
输出:
[src/main.rs:32] 32.90: f64
[src/main.rs:33] my_number: f64
其他一些答案不工作,但我发现typename crate工作。
Create a new project: cargo new test_typename Modify the Cargo.toml [dependencies] typename = "0.1.1" Modify your source code use typename::TypeName; fn main() { assert_eq!(String::type_name(), "std::string::String"); assert_eq!(Vec::<i32>::type_name(), "std::vec::Vec<i32>"); assert_eq!([0, 1, 2].type_name_of(), "[i32; 3]"); let a = 65u8; let b = b'A'; let c = 65; let d = 65i8; let e = 65i32; let f = 65u32; let arr = [1,2,3,4,5]; let first = arr[0]; println!("type of a 65u8 {} is {}", a, a.type_name_of()); println!("type of b b'A' {} is {}", b, b.type_name_of()); println!("type of c 65 {} is {}", c, c.type_name_of()); println!("type of d 65i8 {} is {}", d, d.type_name_of()); println!("type of e 65i32 {} is {}", e, e.type_name_of()); println!("type of f 65u32 {} is {}", f, f.type_name_of()); println!("type of arr {:?} is {}", arr, arr.type_name_of()); println!("type of first {} is {}", first, first.type_name_of()); }
输出结果为:
type of a 65u8 65 is u8
type of b b'A' 65 is u8
type of c 65 65 is i32
type of d 65i8 65 is i8
type of e 65i32 65 is i32
type of f 65u32 65 is u32
type of arr [1, 2, 3, 4, 5] is [i32; 5]
type of first 1 is i32