我有以下几点:
let mut my_number = 32.90;
如何打印my_number的类型?
使用type和type_of不起作用。有其他方法可以打印数字的类型吗?
我有以下几点:
let mut my_number = 32.90;
如何打印my_number的类型?
使用type和type_of不起作用。有其他方法可以打印数字的类型吗?
当前回答
1.38版新增std::any::type_name
use std::any::type_name;
fn type_of<T>(_: T) -> &'static str {
type_name::<T>()
}
fn main() {
let x = 21;
let y = 2.5;
println!("{}", type_of(&y));
println!("{}", type_of(x));
}
其他回答
更新,原始答案如下
trait函数type_name如何,它对于快速获取类型名称非常有用。
pub trait AnyExt {
fn type_name(&self) -> &'static str;
}
impl<T> AnyExt for T {
fn type_name(&self) -> &'static str {
std::any::type_name::<T>()
}
}
fn main(){
let my_number = 32.90;
println!("{}",my_number.type_name());
}
输出:
f64
原来的答案
我写了一个宏type_of!()来调试,它来自std dbg!()。
pub fn type_of2<T>(v: T) -> (&'static str, T) {
(std::any::type_name::<T>(), v)
}
#[macro_export]
macro_rules! type_of {
// NOTE: We cannot use `concat!` to make a static string as a format argument
// of `eprintln!` because `file!` could contain a `{` or
// `$val` expression could be a block (`{ .. }`), in which case the `eprintln!`
// will be malformed.
() => {
eprintln!("[{}:{}]", file!(), line!());
};
($val:expr $(,)?) => {
// Use of `match` here is intentional because it affects the lifetimes
// of temporaries - https://stackoverflow.com/a/48732525/1063961
match $val {
tmp => {
let (type_,tmp) = $crate::type_of2(tmp);
eprintln!("[{}:{}] {}: {}",
file!(), line!(), stringify!($val), type_);
tmp
}
}
};
($($val:expr),+ $(,)?) => {
($($crate::type_of!($val)),+,)
};
}
fn main(){
let my_number = type_of!(32.90);
type_of!(my_number);
}
输出:
[src/main.rs:32] 32.90: f64
[src/main.rs:33] my_number: f64
在稳定rust中有一个@ChrisMorgan答案可以获得近似类型(“float”),在夜间rust中有一个@ShubhamJain答案可以通过不稳定函数获得精确类型(“f64”)。
现在有一种方法可以得到精确的类型(即在f32和f64之间决定)在稳定的rust:
fn main() {
let a = 5.;
let _: () = unsafe { std::mem::transmute(a) };
}
结果
error[E0512]: cannot transmute between types of different sizes, or dependently-sized types
--> main.rs:3:27
|
3 | let _: () = unsafe { std::mem::transmute(a) };
| ^^^^^^^^^^^^^^^^^^^
|
= note: source type: `f64` (64 bits)
= note: target type: `()` (0 bits)
更新
涡轮鱼的变异
fn main() {
let a = 5.;
unsafe { std::mem::transmute::<_, ()>(a) }
}
略短,但可读性稍差。
这是@Boiethios回答的简化版。我已经从原始解决方案中删除了一些“&”符号。
fn print_type_of<T>(_: T) {
println!("{}", std::any::type_name::<T>())
}
fn main() {
let s = "Hello";
let i = 42;
print_type_of(s); // &str
print_type_of(i); // i32
print_type_of(main); // playground::main
print_type_of(print_type_of::<i32>); // playground::print_type_of<i32>
print_type_of(|| "Hi!" ); // playground::main::{{closure}}
}
Rust游乐场的景观
**更新**最近没有被验证工作。
我把一个小板条箱一起做这个基于vbo的答案。它提供了一个宏来返回或打印类型。
把这个放在你的货物里。toml文件:
[dependencies]
t_bang = "0.1.2"
然后你可以这样使用它:
#[macro_use] extern crate t_bang;
use t_bang::*;
fn main() {
let x = 5;
let x_type = t!(x);
println!("{:?}", x_type); // prints out: "i32"
pt!(x); // prints out: "i32"
pt!(5); // prints out: "i32"
}
如果你只是想找出一个变量的类型,并愿意在编译时执行,你可能会导致一个错误,并让编译器拾取它。
例如,将变量设置为一个无效的类型:
let mut my_number: () = 32.90;
// let () = x; would work too
error[E0308]: mismatched types
--> src/main.rs:2:29
|
2 | let mut my_number: () = 32.90;
| ^^^^^ expected (), found floating-point number
|
= note: expected type `()`
found type `{float}`
或者调用无效的方法:
let mut my_number = 32.90;
my_number.what_is_this();
error[E0599]: no method named `what_is_this` found for type `{float}` in the current scope
--> src/main.rs:3:15
|
3 | my_number.what_is_this();
| ^^^^^^^^^^^^
或访问无效字段:
let mut my_number = 32.90;
my_number.what_is_this
error[E0610]: `{float}` is a primitive type and therefore doesn't have fields
--> src/main.rs:3:15
|
3 | my_number.what_is_this
| ^^^^^^^^^^^^
These reveal the type, which in this case is actually not fully resolved. It’s called “floating-point variable” in the first example, and “{float}” in all three examples; this is a partially resolved type which could end up f32 or f64, depending on how you use it. “{float}” is not a legal type name, it’s a placeholder meaning “I’m not completely sure what this is”, but it is a floating-point number. In the case of floating-point variables, if you don't constrain it, it will default to f64¹. (An unqualified integer literal will default to i32.)
参见:
编译器错误消息中的{integer}或{float}是什么?
¹可能仍然有一些让编译器困惑的方法,使它无法在f32和f64之间做出决定;我不确定。它曾经像32.90.eq(&32.90)一样简单,但现在两者都被视为f64,并且可以愉快地进行,所以我不知道。