我希望这对某些人有用(使用awk)

  #!/bin/bash

  available_version=1.2.3 # or online version
  this_version=1.2.1

  if [[ "ok" == "$(echo | awk "(${available_version} > ${this_version}) { print \"ok\"; }")" ]]; then
    echo "Notice, new version is available"
  elif [[ "ok" == "$(echo | awk "(${available_version} == ${this_version}) { print \"ok\"; }")" ]]; then
    echo "OK, version is up to date"
  else
    echo "Warning, the current version is ahead of the online version!"
  fi

这里有一个支持修订的纯Bash解决方案(例如。“1.0-r1”)，答案是基于丹尼斯·威廉姆森(Dennis Williamson)发布的答案。可以很容易地修改它以支持'-RC1'之类的东西，或者通过更改正则表达式从更复杂的字符串中提取版本。

有关实现的详细信息，请参考代码内注释和/或启用包含的调试代码:

#!/bin/bash

# Compare two version strings [$1: version string 1 (v1), $2: version string 2 (v2)]
# Return values:
#   0: v1 == v2
#   1: v1 > v2
#   2: v1 < v2
# Based on: https://stackoverflow.com/a/4025065 by Dennis Williamson
function compare_versions() {

    # Trivial v1 == v2 test based on string comparison
    [[ "$1" == "$2" ]] && return 0

    # Local variables
    local regex="^(.*)-r([0-9]*)$" va1=() vr1=0 va2=() vr2=0 len i IFS="."

    # Split version strings into arrays, extract trailing revisions
    if [[ "$1" =~ ${regex} ]]; then
        va1=(${BASH_REMATCH[1]})
        [[ -n "${BASH_REMATCH[2]}" ]] && vr1=${BASH_REMATCH[2]}
    else
        va1=($1)
    fi
    if [[ "$2" =~ ${regex} ]]; then
        va2=(${BASH_REMATCH[1]})
        [[ -n "${BASH_REMATCH[2]}" ]] && vr2=${BASH_REMATCH[2]}
    else
        va2=($2)
    fi

    # Bring va1 and va2 to same length by filling empty fields with zeros
    (( ${#va1[@]} > ${#va2[@]} )) && len=${#va1[@]} || len=${#va2[@]}
    for ((i=0; i < len; ++i)); do
        [[ -z "${va1[i]}" ]] && va1[i]="0"
        [[ -z "${va2[i]}" ]] && va2[i]="0"
    done

    # Append revisions, increment length
    va1+=($vr1)
    va2+=($vr2)
    len=$((len+1))

    # *** DEBUG ***
    #echo "TEST: '${va1[@]} (?) ${va2[@]}'"

    # Compare version elements, check if v1 > v2 or v1 < v2
    for ((i=0; i < len; ++i)); do
        if (( 10#${va1[i]} > 10#${va2[i]} )); then
            return 1
        elif (( 10#${va1[i]} < 10#${va2[i]} )); then
            return 2
        fi
    done

    # All elements are equal, thus v1 == v2
    return 0
}


# ---------- everything below this line is just for testing ----------


# Test compare_versions [$1: version string 1, $2: version string 2, $3: expected result]
function test_compare_versions() {
    local op
    compare_versions "$1" "$2"
    case $? in
        0) op="==" ;;
        1) op=">" ;;
        2) op="<" ;;
    esac
    if [[ "$op" == "$3" ]]; then
        echo -e "\e[1;32mPASS: '$1 $op $2'\e[0m"
    else
        echo -e "\e[1;31mFAIL: '$1 $3 $2' (result: '$1 $op $2')\e[0m"
    fi
}

echo -e "\nThe following tests should pass:"
while read -r test; do
    test_compare_versions $test
done << EOF
1            1            ==
2.1          2.2          <
3.0.4.10     3.0.4.2      >
4.08         4.08.01      <
3.2.1.9.8144 3.2          >
3.2          3.2.1.9.8144 <
1.2          2.1          <
2.1          1.2          >
5.6.7        5.6.7        ==
1.01.1       1.1.1        ==
1.1.1        1.01.1       ==
1            1.0          ==
1.0          1            ==
1.0.2.0      1.0.2        ==
1..0         1.0          ==
1.0          1..0         ==
1.0-r1       1.0-r3       <
1.0-r9       2.0          <
3.0-r15      3.0-r9       >
...-r1       ...-r2       <
2.0-r1       1.9.8.21-r2  >
1.0          3.8.9.32-r   <
-r           -r3          <
-r3          -r           >
-r3          -r3          ==
-r           -r           ==
0.0-r2       0.0.0.0-r2   ==
1.0.0.0-r2   1.0-r2       ==
0.0.0.1-r7   -r9          >
0.0-r0       0            ==
1.002.0-r6   1.2.0-r7     <
001.001-r2   1.1-r2       ==
5.6.1-r0     5.6.1        ==
EOF

echo -e "\nThe following tests should fail:"
while read -r test; do
    test_compare_versions $test
done << EOF
1            1            >
3.0.5-r5     3..5-r5      >
4.9.21-r3    4.8.22-r9    <
1.0-r        1.0-r1       ==
-r           1.0-r        >
-r1          0.0-r1       <
-r2          0-r2         <
EOF

下面是另一个纯bash版本，比公认的答案要小得多。它只检查版本是否小于或等于“最小版本”，并且它将按字典顺序检查字母数字序列，这通常会给出错误的结果(举个常见的例子，“snapshot”不晚于“release”)。它将工作的主要/次要。

is_number() {
    case "$BASH_VERSION" in
        3.1.*)
            PATTERN='\^\[0-9\]+\$'
            ;;
        *)
            PATTERN='^[0-9]+$'
            ;;
    esac

    [[ "$1" =~ $PATTERN ]]
}

min_version() {
    if [[ $# != 2 ]]
    then
        echo "Usage: min_version current minimum"
        return
    fi

    A="${1%%.*}"
    B="${2%%.*}"

    if [[ "$A" != "$1" && "$B" != "$2" && "$A" == "$B" ]]
    then
        min_version "${1#*.}" "${2#*.}"
    else
        if is_number "$A" && is_number "$B"
        then
            [[ "$A" -ge "$B" ]]
        else
            [[ ! "$A" < "$B" ]]
        fi
    fi
}

我使用嵌入式Linux (Yocto)与BusyBox。BusyBox排序没有-V选项(但BusyBox expr匹配可以做正则表达式)。所以我需要一个Bash版本的比较，它适用于这个约束。

我做了以下(类似于Dennis Williamson的回答)来比较使用“自然排序”类型的算法。它将字符串分成数字部分和非数字部分;它以数字方式比较数字部分(因此10大于9)，并以纯ASCII方式比较非数字部分。

ascii_frag() {
    expr match "$1" "\([^[:digit:]]*\)"
}

ascii_remainder() {
    expr match "$1" "[^[:digit:]]*\(.*\)"
}

numeric_frag() {
    expr match "$1" "\([[:digit:]]*\)"
}

numeric_remainder() {
    expr match "$1" "[[:digit:]]*\(.*\)"
}

vercomp_debug() {
    OUT="$1"
    #echo "${OUT}"
}

# return 1 for $1 > $2
# return 2 for $1 < $2
# return 0 for equal
vercomp() {
    local WORK1="$1"
    local WORK2="$2"
    local NUM1="", NUM2="", ASCII1="", ASCII2=""
    while true; do
        vercomp_debug "ASCII compare"
        ASCII1=`ascii_frag "${WORK1}"`
        ASCII2=`ascii_frag "${WORK2}"`
        WORK1=`ascii_remainder "${WORK1}"`
        WORK2=`ascii_remainder "${WORK2}"`
        vercomp_debug "\"${ASCII1}\" remainder \"${WORK1}\""
        vercomp_debug "\"${ASCII2}\" remainder \"${WORK2}\""

        if [ "${ASCII1}" \> "${ASCII2}" ]; then
            vercomp_debug "ascii ${ASCII1} > ${ASCII2}"
            return 1
        elif [ "${ASCII1}" \< "${ASCII2}" ]; then
            vercomp_debug "ascii ${ASCII1} < ${ASCII2}"
            return 2
        fi
        vercomp_debug "--------"

        vercomp_debug "Numeric compare"
        NUM1=`numeric_frag "${WORK1}"`
        NUM2=`numeric_frag "${WORK2}"`
        WORK1=`numeric_remainder "${WORK1}"`
        WORK2=`numeric_remainder "${WORK2}"`
        vercomp_debug "\"${NUM1}\" remainder \"${WORK1}\""
        vercomp_debug "\"${NUM2}\" remainder \"${WORK2}\""

        if [ -z "${NUM1}" -a -z "${NUM2}" ]; then
            vercomp_debug "blank 1 and blank 2 equal"
            return 0
        elif [ -z "${NUM1}" -a -n "${NUM2}" ]; then
            vercomp_debug "blank 1 less than non-blank 2"
            return 2
        elif [ -n "${NUM1}" -a -z "${NUM2}" ]; then
            vercomp_debug "non-blank 1 greater than blank 2"
            return 1
        fi

        if [ "${NUM1}" -gt "${NUM2}" ]; then
            vercomp_debug "num ${NUM1} > ${NUM2}"
            return 1
        elif [ "${NUM1}" -lt "${NUM2}" ]; then
            vercomp_debug "num ${NUM1} < ${NUM2}"
            return 2
        fi
        vercomp_debug "--------"
    done
}

它可以比较更复杂的版本号，例如

1.2-r3和1.2-r4 1.2 r3 vs 1.2r4

请注意，对于Dennis Williamson的回答中的一些极端情况，它不会返回相同的结果。特别是:

1            1.0          <
1.0          1            >
1.0.2.0      1.0.2        >
1..0         1.0          >
1.0          1..0         <

但这些都是极端情况，我认为结果仍然是合理的。

下面是一个不需要任何外部工具的纯Bash版本:

#!/bin/bash
vercomp () {
    if [[ $1 == $2 ]]
    then
        return 0
    fi
    local IFS=.
    local i ver1=($1) ver2=($2)
    # fill empty fields in ver1 with zeros
    for ((i=${#ver1[@]}; i<${#ver2[@]}; i++))
    do
        ver1[i]=0
    done
    for ((i=0; i<${#ver1[@]}; i++))
    do
        if [[ -z ${ver2[i]} ]]
        then
            # fill empty fields in ver2 with zeros
            ver2[i]=0
        fi
        if ((10#${ver1[i]} > 10#${ver2[i]}))
        then
            return 1
        fi
        if ((10#${ver1[i]} < 10#${ver2[i]}))
        then
            return 2
        fi
    done
    return 0
}

testvercomp () {
    vercomp $1 $2
    case $? in
        0) op='=';;
        1) op='>';;
        2) op='<';;
    esac
    if [[ $op != $3 ]]
    then
        echo "FAIL: Expected '$3', Actual '$op', Arg1 '$1', Arg2 '$2'"
    else
        echo "Pass: '$1 $op $2'"
    fi
}

# Run tests
# argument table format:
# testarg1   testarg2     expected_relationship
echo "The following tests should pass"
while read -r test
do
    testvercomp $test
done << EOF
1            1            =
2.1          2.2          <
3.0.4.10     3.0.4.2      >
4.08         4.08.01      <
3.2.1.9.8144 3.2          >
3.2          3.2.1.9.8144 <
1.2          2.1          <
2.1          1.2          >
5.6.7        5.6.7        =
1.01.1       1.1.1        =
1.1.1        1.01.1       =
1            1.0          =
1.0          1            =
1.0.2.0      1.0.2        =
1..0         1.0          =
1.0          1..0         =
EOF

echo "The following test should fail (test the tester)"
testvercomp 1 1 '>'

运行测试:

$ . ./vercomp
The following tests should pass
Pass: '1 = 1'
Pass: '2.1 < 2.2'
Pass: '3.0.4.10 > 3.0.4.2'
Pass: '4.08 < 4.08.01'
Pass: '3.2.1.9.8144 > 3.2'
Pass: '3.2 < 3.2.1.9.8144'
Pass: '1.2 < 2.1'
Pass: '2.1 > 1.2'
Pass: '5.6.7 = 5.6.7'
Pass: '1.01.1 = 1.1.1'
Pass: '1.1.1 = 1.01.1'
Pass: '1 = 1.0'
Pass: '1.0 = 1'
Pass: '1.0.2.0 = 1.0.2'
Pass: '1..0 = 1.0'
Pass: '1.0 = 1..0'
The following test should fail (test the tester)
FAIL: Expected '>', Actual '=', Arg1 '1', Arg2 '1'

可能没有普遍正确的方法来实现这一点。如果您正在尝试比较Debian包系统中的版本，请尝试dpkg——compare-versions <first> <relation> <second>。