是否有办法在bash上比较这些字符串,例如:2.4.5和2.8和2.4.5.1?


当前回答

下面是一个不使用外部命令的简单Bash函数。它适用于包含最多三个数字部分的版本字符串-小于3也是可以的。它可以很容易地扩展为更多。它实现了=、<、<=、>、>=和!=条件。

#!/bin/bash
vercmp() {
    version1=$1 version2=$2 condition=$3

    IFS=. v1_array=($version1) v2_array=($version2)
    v1=$((v1_array[0] * 100 + v1_array[1] * 10 + v1_array[2]))
    v2=$((v2_array[0] * 100 + v2_array[1] * 10 + v2_array[2]))
    diff=$((v2 - v1))
    [[ $condition = '='  ]] && ((diff == 0)) && return 0
    [[ $condition = '!=' ]] && ((diff != 0)) && return 0
    [[ $condition = '<'  ]] && ((diff >  0)) && return 0
    [[ $condition = '<=' ]] && ((diff >= 0)) && return 0
    [[ $condition = '>'  ]] && ((diff <  0)) && return 0
    [[ $condition = '>=' ]] && ((diff <= 0)) && return 0
    return 1
}

下面是测试:

for tv1 in '*' 1.1.1 2.5.3 7.3.0 0.5.7 10.3.9 8.55.32 0.0.1; do
    for tv2 in 3.1.1 1.5.3 4.3.0 0.0.7 0.3.9 11.55.32 10.0.0 '*'; do
      for c in '=' '>' '<' '>=' '<=' '!='; do
        vercmp "$tv1" "$tv2" "$c" && printf '%s\n' "$tv1 $c $tv2 is true" || printf '%s\n' "$tv1 $c $tv2 is false"
      done
    done
done

测试输出的子集:

<snip>

* >= * is true
* <= * is true
* != * is true
1.1.1 = 3.1.1 is false
1.1.1 > 3.1.1 is false
1.1.1 < 3.1.1 is true
1.1.1 >= 3.1.1 is false
1.1.1 <= 3.1.1 is true
1.1.1 != 3.1.1 is true
1.1.1 = 1.5.3 is false
1.1.1 > 1.5.3 is false
1.1.1 < 1.5.3 is true
1.1.1 >= 1.5.3 is false
1.1.1 <= 1.5.3 is true
1.1.1 != 1.5.3 is true
1.1.1 = 4.3.0 is false
1.1.1 > 4.3.0 is false

<snip>

其他回答

你可以递归地拆分。和下面的算法进行比较,从这里开始。如果版本相同则返回10,如果版本1大于版本2则返回11,否则返回9。

#!/bin/bash
do_version_check() {

   [ "$1" == "$2" ] && return 10

   ver1front=`echo $1 | cut -d "." -f -1`
   ver1back=`echo $1 | cut -d "." -f 2-`

   ver2front=`echo $2 | cut -d "." -f -1`
   ver2back=`echo $2 | cut -d "." -f 2-`

   if [ "$ver1front" != "$1" ] || [ "$ver2front" != "$2" ]; then
       [ "$ver1front" -gt "$ver2front" ] && return 11
       [ "$ver1front" -lt "$ver2front" ] && return 9

       [ "$ver1front" == "$1" ] || [ -z "$ver1back" ] && ver1back=0
       [ "$ver2front" == "$2" ] || [ -z "$ver2back" ] && ver2back=0
       do_version_check "$ver1back" "$ver2back"
       return $?
   else
           [ "$1" -gt "$2" ] && return 11 || return 9
   fi
}    

do_version_check "$1" "$2"

function version_compare () {
  function sub_ver () {
    local len=${#1}
    temp=${1%%"."*} && indexOf=`echo ${1%%"."*} | echo ${#temp}`
    echo -e "${1:0:indexOf}"
  }
  function cut_dot () {
    local offset=${#1}
    local length=${#2}
    echo -e "${2:((++offset)):length}"
  }
  if [ -z "$1" ] || [ -z "$2" ]; then
    echo "=" && exit 0
  fi
  local v1=`echo -e "${1}" | tr -d '[[:space:]]'`
  local v2=`echo -e "${2}" | tr -d '[[:space:]]'`
  local v1_sub=`sub_ver $v1`
  local v2_sub=`sub_ver $v2`
  if (( v1_sub > v2_sub )); then
    echo ">"
  elif (( v1_sub < v2_sub )); then
    echo "<"
  else
    version_compare `cut_dot $v1_sub $v1` `cut_dot $v2_sub $v2`
  fi
}

### Usage:

version_compare "1.2.3" "1.2.4"
# Output: <

功劳归于@Shellman

function version { echo "$@" | awk -F. '{ printf("%d%03d%03d%03d\n", $1,$2,$3,$4); }'; }

这样用:

if [ $(version $VAR) -ge $(version "6.2.0") ]; then
    echo "Version is up to date"
fi

(来自https://apple.stackexchange.com/a/123408/11374)

下面是一个不需要任何外部工具的纯Bash版本:

#!/bin/bash
vercomp () {
    if [[ $1 == $2 ]]
    then
        return 0
    fi
    local IFS=.
    local i ver1=($1) ver2=($2)
    # fill empty fields in ver1 with zeros
    for ((i=${#ver1[@]}; i<${#ver2[@]}; i++))
    do
        ver1[i]=0
    done
    for ((i=0; i<${#ver1[@]}; i++))
    do
        if [[ -z ${ver2[i]} ]]
        then
            # fill empty fields in ver2 with zeros
            ver2[i]=0
        fi
        if ((10#${ver1[i]} > 10#${ver2[i]}))
        then
            return 1
        fi
        if ((10#${ver1[i]} < 10#${ver2[i]}))
        then
            return 2
        fi
    done
    return 0
}

testvercomp () {
    vercomp $1 $2
    case $? in
        0) op='=';;
        1) op='>';;
        2) op='<';;
    esac
    if [[ $op != $3 ]]
    then
        echo "FAIL: Expected '$3', Actual '$op', Arg1 '$1', Arg2 '$2'"
    else
        echo "Pass: '$1 $op $2'"
    fi
}

# Run tests
# argument table format:
# testarg1   testarg2     expected_relationship
echo "The following tests should pass"
while read -r test
do
    testvercomp $test
done << EOF
1            1            =
2.1          2.2          <
3.0.4.10     3.0.4.2      >
4.08         4.08.01      <
3.2.1.9.8144 3.2          >
3.2          3.2.1.9.8144 <
1.2          2.1          <
2.1          1.2          >
5.6.7        5.6.7        =
1.01.1       1.1.1        =
1.1.1        1.01.1       =
1            1.0          =
1.0          1            =
1.0.2.0      1.0.2        =
1..0         1.0          =
1.0          1..0         =
EOF

echo "The following test should fail (test the tester)"
testvercomp 1 1 '>'

运行测试:

$ . ./vercomp
The following tests should pass
Pass: '1 = 1'
Pass: '2.1 < 2.2'
Pass: '3.0.4.10 > 3.0.4.2'
Pass: '4.08 < 4.08.01'
Pass: '3.2.1.9.8144 > 3.2'
Pass: '3.2 < 3.2.1.9.8144'
Pass: '1.2 < 2.1'
Pass: '2.1 > 1.2'
Pass: '5.6.7 = 5.6.7'
Pass: '1.01.1 = 1.1.1'
Pass: '1.1.1 = 1.01.1'
Pass: '1 = 1.0'
Pass: '1.0 = 1'
Pass: '1.0.2.0 = 1.0.2'
Pass: '1..0 = 1.0'
Pass: '1.0 = 1..0'
The following test should fail (test the tester)
FAIL: Expected '>', Actual '=', Arg1 '1', Arg2 '1'

我实现了另一个比较器函数。这一个有两个特定的要求:(i)我不希望函数失败使用返回1,但echo代替;(ii)当我们从git存储库中检索版本时,版本“1.0”应该大于“1.0.2”,这意味着“1.0”来自trunk。

function version_compare {
  IFS="." read -a v_a <<< "$1"
  IFS="." read -a v_b <<< "$2"

  while [[ -n "$v_a" || -n "$v_b" ]]; do
    [[ -z "$v_a" || "$v_a" -gt "$v_b" ]] && echo 1 && return
    [[ -z "$v_b" || "$v_b" -gt "$v_a" ]] && echo -1 && return

    v_a=("${v_a[@]:1}")
    v_b=("${v_b[@]:1}")
  done

  echo 0
}

请随意评论并提出改进建议。