enum Suit: String {
case spades = "♠"
case hearts = "♥"
case diamonds = "♦"
case clubs = "♣"
}
例如,我怎么做这样的事情:
for suit in Suit {
// do something with suit
print(suit.rawValue)
}
结果示例:
♠
♥
♦
♣
enum Suit: String {
case spades = "♠"
case hearts = "♥"
case diamonds = "♦"
case clubs = "♣"
}
例如,我怎么做这样的事情:
for suit in Suit {
// do something with suit
print(suit.rawValue)
}
结果示例:
♠
♥
♦
♣
当前回答
这个问题现在简单多了。以下是我的Swift 4.2解决方案:
enum Suit: Int, CaseIterable {
case None
case Spade, Heart, Diamond, Club
static let allNonNullCases = Suit.allCases[Spade.rawValue...]
}
enum Rank: Int, CaseIterable {
case Joker
case Two, Three, Four, Five, Six, Seven, Eight
case Nine, Ten, Jack, Queen, King, Ace
static let allNonNullCases = Rank.allCases[Two.rawValue...]
}
func makeDeck(withJoker: Bool = false) -> [Card] {
var deck = [Card]()
for suit in Suit.allNonNullCases {
for rank in Rank.allNonNullCases {
deck.append(Card(suit: suit, rank: rank))
}
}
if withJoker {
deck.append(Card(suit: .None, rank: .Joker))
}
return deck
}
4。2:
我喜欢这个解决方案,我把找到“列表理解在Swift”。
它使用Int rawws而不是string,但它避免了键入两次,它允许自定义范围,并且不硬编码原始值。
这是我最初解决方案的Swift 4版本,但请参阅上面的4.2改进:
enum Suit: Int {
case None
case Spade, Heart, Diamond, Club
static let allRawValues = Suit.Spade.rawValue...Suit.Club.rawValue
static let allCases = Array(allRawValues.map{ Suit(rawValue: $0)! })
}
enum Rank: Int {
case Joker
case Two, Three, Four, Five, Six
case Seven, Eight, Nine, Ten
case Jack, Queen, King, Ace
static let allRawValues = Rank.Two.rawValue...Rank.Ace.rawValue
static let allCases = Array(allRawValues.map{ Rank(rawValue: $0)! })
}
func makeDeck(withJoker: Bool = false) -> [Card] {
var deck = [Card]()
for suit in Suit.allCases {
for rank in Rank.allCases {
deck.append(Card(suit: suit, rank: rank))
}
}
if withJoker {
deck.append(Card(suit: .None, rank: .Joker))
}
return deck
}
其他回答
枚举有toRaw()和fromRaw()方法。所以如果你的原始值是Int,你可以从第一个枚举迭代到最后一个枚举:
enum Suit: Int {
case Spades = 1
case Hearts, Diamonds, Clubs
func simpleDescription() -> String {
switch self {
case .Spades:
return "spades"
case .Hearts:
return "hearts"
case .Diamonds:
return "diamonds"
case .Clubs:
return "clubs"
}
}
}
for i in Suit.Spades.toRaw()...Suit.Clubs.toRaw() {
if let covertedSuit = Suit.fromRaw(i) {
let description = covertedSuit.simpleDescription()
}
}
一个问题是在运行simpleDescription方法之前需要测试可选值,因此我们首先将convertedSuit设置为我们的值,然后将常量设置为convertedSuit.simpleDescription()
该解决方案在可读性和可维护性之间取得了适当的平衡。
struct Card {
// ...
static func deck() -> Card[] {
var deck = Card[]()
for rank in Rank.Ace.toRaw()...Rank.King.toRaw() {
for suit in [Suit.Spades, .Hearts, .Clubs, .Diamonds] {
let card = Card(rank: Rank.fromRaw(rank)!, suit: suit)
deck.append(card)
}
}
return deck
}
}
let deck = Card.deck()
其他的解决方法都是可行的,但它们都假设了可能的等级和花色的数量,或者第一和最后的等级是什么。的确,在可预见的未来,一副纸牌的布局可能不会有太大变化。然而,一般来说,编写尽可能少假设的代码会更简洁。我的解决方案:
我已经在Suit枚举中添加了一个原始类型,所以我可以使用Suit(rawValue:)来访问Suit案例:
enum Suit: Int {
case Spades = 1
case Hearts, Diamonds, Clubs
func simpleDescription() -> String {
switch self {
case .Spades:
return "spades"
case .Hearts:
return "hearts"
case .Diamonds:
return "diamonds"
case .Clubs:
return "clubs"
}
}
func color() -> String {
switch self {
case .Spades:
return "black"
case .Clubs:
return "black"
case .Diamonds:
return "red"
case .Hearts:
return "red"
}
}
}
enum Rank: Int {
case Ace = 1
case Two, Three, Four, Five, Six, Seven, Eight, Nine, Ten
case Jack, Queen, King
func simpleDescription() -> String {
switch self {
case .Ace:
return "ace"
case .Jack:
return "jack"
case .Queen:
return "queen"
case .King:
return "king"
default:
return String(self.rawValue)
}
}
}
在Card的createDeck()方法实现的下面。init(rawValue:)是一个可失败的初始化式,返回一个可选值。通过在两个while语句中展开并检查它的值,不需要假设Rank或Suit情况的数量:
struct Card {
var rank: Rank
var suit: Suit
func simpleDescription() -> String {
return "The \(rank.simpleDescription()) of \(suit.simpleDescription())"
}
func createDeck() -> [Card] {
var n = 1
var deck = [Card]()
while let rank = Rank(rawValue: n) {
var m = 1
while let suit = Suit(rawValue: m) {
deck.append(Card(rank: rank, suit: suit))
m += 1
}
n += 1
}
return deck
}
}
下面是如何调用createDeck方法:
let card = Card(rank: Rank.Ace, suit: Suit.Clubs)
let deck = card.createDeck()
这篇文章是相关的https://www.swift-studies.com/blog/2014/6/10/enumerating-enums-in-swift
基本上,提议的解决方案是
enum ProductCategory : String {
case Washers = "washers", Dryers = "dryers", Toasters = "toasters"
static let allValues = [Washers, Dryers, Toasters]
}
for category in ProductCategory.allValues{
//Do something
}
这看起来像一个黑客,但如果你使用原始值,你可以这样做
enum Suit: Int {
case Spades = 0, Hearts, Diamonds, Clubs
...
}
var suitIndex = 0
while var suit = Suit.fromRaw(suitIndex++) {
...
}