enum Suit: String {
case spades = "♠"
case hearts = "♥"
case diamonds = "♦"
case clubs = "♣"
}
例如,我怎么做这样的事情:
for suit in Suit {
// do something with suit
print(suit.rawValue)
}
结果示例:
♠
♥
♦
♣
enum Suit: String {
case spades = "♠"
case hearts = "♥"
case diamonds = "♦"
case clubs = "♣"
}
例如,我怎么做这样的事情:
for suit in Suit {
// do something with suit
print(suit.rawValue)
}
结果示例:
♠
♥
♦
♣
当前回答
如果你给枚举一个原始的Int值,它将使循环更容易。
例如,你可以使用anyGenerator来获得一个可以枚举你的值的生成器:
enum Suit: Int, CustomStringConvertible {
case Spades, Hearts, Diamonds, Clubs
var description: String {
switch self {
case .Spades: return "Spades"
case .Hearts: return "Hearts"
case .Diamonds: return "Diamonds"
case .Clubs: return "Clubs"
}
}
static func enumerate() -> AnyGenerator<Suit> {
var nextIndex = Spades.rawValue
return anyGenerator { Suit(rawValue: nextIndex++) }
}
}
// You can now use it like this:
for suit in Suit.enumerate() {
suit.description
}
// or like this:
let allSuits: [Suit] = Array(Suit.enumerate())
然而,这看起来像一个相当常见的模式,如果我们可以通过简单地遵循协议使任何枚举类型可枚举,这不是很好吗?有了Swift 2.0和协议扩展,现在我们可以了!
简单地添加到你的项目:
protocol EnumerableEnum {
init?(rawValue: Int)
static func firstValue() -> Int
}
extension EnumerableEnum {
static func enumerate() -> AnyGenerator<Self> {
var nextIndex = firstRawValue()
return anyGenerator { Self(rawValue: nextIndex++) }
}
static func firstRawValue() -> Int { return 0 }
}
现在,任何时候你创建一个枚举(只要它有一个Int原始值),你可以通过遵循协议使它可枚举:
enum Rank: Int, EnumerableEnum {
case Ace, Two, Three, Four, Five, Six, Seven, Eight, Nine, Ten, Jack, Queen, King
}
// ...
for rank in Rank.enumerate() { ... }
如果你的枚举值不以0开头(默认值),重写firstRawValue方法:
enum DeckColor: Int, EnumerableEnum {
case Red = 10, Blue, Black
static func firstRawValue() -> Int { return Red.rawValue }
}
// ...
let colors = Array(DeckColor.enumerate())
最后一个Suit类,包括用更标准的CustomStringConvertible协议替换simpleDescription,看起来像这样:
enum Suit: Int, CustomStringConvertible, EnumerableEnum {
case Spades, Hearts, Diamonds, Clubs
var description: String {
switch self {
case .Spades: return "Spades"
case .Hearts: return "Hearts"
case .Diamonds: return "Diamonds"
case .Clubs: return "Clubs"
}
}
}
// ...
for suit in Suit.enumerate() {
print(suit.description)
}
Swift 3语法:
protocol EnumerableEnum {
init?(rawValue: Int)
static func firstRawValue() -> Int
}
extension EnumerableEnum {
static func enumerate() -> AnyIterator<Self> {
var nextIndex = firstRawValue()
let iterator: AnyIterator<Self> = AnyIterator {
defer { nextIndex = nextIndex + 1 }
return Self(rawValue: nextIndex)
}
return iterator
}
static func firstRawValue() -> Int {
return 0
}
}
其他回答
如果您仍然想为Rank和Suit使用枚举,这里有一个不那么神秘的例子。如果您想使用for-in循环遍历每个对象,只需将它们收集到一个Array中。
标准52张牌的例子:
enum Rank: Int {
case Ace = 1, Two, Three, Four, Five, Six, Seven, Eight, Nine, Ten, Jack, Queen, King
func name() -> String {
switch self {
case .Ace:
return "ace"
case .Jack:
return "jack"
case .Queen:
return "queen"
case .King:
return "king"
default:
return String(self.toRaw())
}
}
}
enum Suit: Int {
case Diamonds = 1, Clubs, Hearts, Spades
func name() -> String {
switch self {
case .Diamonds:
return "diamonds"
case .Clubs:
return "clubs"
case .Hearts:
return "hearts"
case .Spades:
return "spades"
default:
return "NOT A VALID SUIT"
}
}
}
let Ranks = [
Rank.Ace,
Rank.Two,
Rank.Three,
Rank.Four,
Rank.Five,
Rank.Six,
Rank.Seven,
Rank.Eight,
Rank.Nine,
Rank.Ten,
Rank.Jack,
Rank.Queen,
Rank.King
]
let Suits = [
Suit.Diamonds,
Suit.Clubs,
Suit.Hearts,
Suit.Spades
]
class Card {
var rank: Rank
var suit: Suit
init(rank: Rank, suit: Suit) {
self.rank = rank
self.suit = suit
}
}
class Deck {
var cards = Card[]()
init() {
for rank in Ranks {
for suit in Suits {
cards.append(Card(rank: rank, suit: suit))
}
}
}
}
var myDeck = Deck()
myDeck.cards.count // => 52
有时,您可能会处理具有底层原始整数类型的枚举类型,这种类型在整个软件开发生命周期中都会发生变化。下面是一个很适合这种情况的例子:
public class MyClassThatLoadsTexturesEtc
{
//...
// Colors used for gems and sectors.
public enum Color: Int
{
// Colors arranged in order of the spectrum.
case First = 0
case Red, Orange, Yellow, Green, Blue, Purple, Pink
// --> Add more colors here, between the first and last markers.
case Last
}
//...
public func preloadGems()
{
// Preload all gems.
for i in (Color.First.toRaw() + 1) ..< (Color.Last.toRaw())
{
let color = Color.fromRaw(i)!
loadColoredTextures(forKey: color)
}
}
//...
}
以下是我的建议。这不是完全令人满意的(我对Swift和OOP很陌生!),但也许有人可以改进它。这个想法是让每个枚举提供自己的范围信息作为.first和.last属性。它只向每个枚举添加了两行代码:仍然有点硬编码,但至少它没有复制整个集合。它确实需要将Suit enum修改为Int类型,就像Rank enum一样,而不是无类型的。
而不是重复整个解决方案,下面是我添加到。在case语句之后的某个地方(Suit enum类似):
var first: Int { return Ace.toRaw() }
var last: Int { return King.toRaw() }
以及我用来将deck构建为String数组的循环。(问题定义没有说明牌组是如何构造的。)
func createDeck() -> [String] {
var deck: [String] = []
var card: String
for r in Rank.Ace.first...Rank.Ace.last {
for s in Suit.Hearts.first...Suit.Hearts.last {
card = Rank.simpleDescription( Rank.fromRaw(r)!)() + " of " + Suit.simpleDescription( Suit.fromRaw(s)!)()
deck.append( card)
}
}
return deck
}
这并不令人满意,因为属性与元素而不是enum相关联。但它确实为“for”循环增加了清晰度。我希望它是Rank。而不是Rank.Ace.first。它适用于任何元素,但很难看。有人能演示一下如何将其提升到enum级别吗?
为了使它工作,我从Card结构中提取了createDeck方法。我不知道如何从该结构返回一个[String]数组,这似乎是一个糟糕的地方,把这样的方法无论如何。
实验内容是: 实验
在Card中添加一个方法,用于创建一副完整的牌,每一副牌都是rank和花色的组合。
因此,除了添加方法之外,没有修改或增强给定的代码(并且没有使用还没有教过的东西),我想出了这个解决方案:
struct Card {
var rank: Rank
var suit: Suit
func simpleDescription() -> String {
return "The \(rank.simpleDescription()) of \(suit.simpleDescription())"
}
func createDeck() -> [Card] {
var deck: [Card] = []
for rank in Rank.Ace.rawValue...Rank.King.rawValue {
for suit in Suit.Spades.rawValue...Suit.Clubs.rawValue {
let card = Card(rank: Rank(rawValue: rank)!, suit: Suit(rawValue: suit)!)
//println(card.simpleDescription())
deck += [card]
}
}
return deck
}
}
let threeOfSpades = Card(rank: .Three, suit: .Spades)
let threeOfSpadesDescription = threeOfSpades.simpleDescription()
let deck = threeOfSpades.createDeck()
enum Rank: Int {
case Ace = 1
case Two, Three, Four, Five, Six, Seven, Eight, Nine, Ten
case Jack, Queen, King
func simpleDescription() -> String {
switch self {
case .Ace: return "ace"
case .Jack: return "jack"
case .Queen: return "queen"
case .King: return "king"
default: return String(self.toRaw())
}
}
}
enum Suit: Int {
case Spades = 1
case Hearts, Diamonds, Clubs
func simpleDescription() -> String {
switch self {
case .Spades: return "spades"
case .Hearts: return "hearts"
case .Diamonds: return "diamonds"
case .Clubs: return "clubs"
}
}
func color() -> String {
switch self {
case .Spades, .Clubs: return "black"
case .Hearts, .Diamonds: return "red"
}
}
}
struct Card {
var rank: Rank
var suit: Suit
func simpleDescription() -> String {
return "The \(rank.simpleDescription()) of \(suit.simpleDescription())"
}
static func createPokers() -> Card[] {
let ranks = Array(Rank.Ace.toRaw()...Rank.King.toRaw())
let suits = Array(Suit.Spades.toRaw()...Suit.Clubs.toRaw())
let cards = suits.reduce(Card[]()) { (tempCards, suit) in
tempCards + ranks.map { rank in
Card(rank: Rank.fromRaw(rank)!, suit: Suit.fromRaw(suit)!)
}
}
return cards
}
}