用@staticmethod修饰的方法和用@classmethod修饰的方法有什么区别?


当前回答

要决定是使用@staticmethod还是@classmethod,必须查看方法内部。如果您的方法访问类中的其他变量/方法,请使用@classmethod。另一方面,如果您的方法不涉及类的任何其他部分,则使用@staticmethod。

class Apple:

    _counter = 0

    @staticmethod
    def about_apple():
        print('Apple is good for you.')

        # note you can still access other member of the class
        # but you have to use the class instance 
        # which is not very nice, because you have repeat yourself
        # 
        # For example:
        # @staticmethod
        #    print('Number of apples have been juiced: %s' % Apple._counter)
        #
        # @classmethod
        #    print('Number of apples have been juiced: %s' % cls._counter)
        #
        #    @classmethod is especially useful when you move your function to another class,
        #       you don't have to rename the referenced class 

    @classmethod
    def make_apple_juice(cls, number_of_apples):
        print('Making juice:')
        for i in range(number_of_apples):
            cls._juice_this(i)

    @classmethod
    def _juice_this(cls, apple):
        print('Juicing apple %d...' % apple)
        cls._counter += 1

其他回答

@classmethod:可用于创建对该类创建的所有实例的共享全局访问。。。。。比如由多个用户更新记录。。。。我特别发现它在创建单件时也很有用。:)

@静态方法:与关联的类或实例无关。。。但为了可读性,可以使用静态方法

顾名思义,类方法用于更改类而不是对象。要对类进行更改,它们将修改类属性(而不是对象属性),因为这就是更新类的方式。这就是类方法将类(通常用“cls”表示)作为第一个参数的原因。

class A(object):
    m=54

    @classmethod
    def class_method(cls):
        print "m is %d" % cls.m

另一方面,静态方法用于执行未绑定到类的功能,即它们不会读取或写入类变量。因此,静态方法不将类作为参数。使用它们是为了使类可以执行与类的目的不直接相关的功能。

class X(object):
    m=54 #will not be referenced

    @staticmethod
    def static_method():
        print "Referencing/calling a variable or function outside this class. E.g. Some global variable/function."

让我先告诉一下用@classmethod修饰的方法和@staticmethod修饰的方法之间的相似性。

相似性:它们都可以在类本身上调用,而不仅仅是类的实例。所以,在某种意义上,这两种方法都是Class的方法。

区别:类方法将接收类本身作为第一个参数,而静态方法不接收。

因此,在某种意义上,静态方法并不绑定到类本身,只是因为它可能具有相关功能而挂在那里。

>>> class Klaus:
        @classmethod
        def classmthd(*args):
            return args

        @staticmethod
        def staticmthd(*args):
            return args

# 1. Call classmethod without any arg
>>> Klaus.classmthd()  
(__main__.Klaus,)  # the class gets passed as the first argument

# 2. Call classmethod with 1 arg
>>> Klaus.classmthd('chumma')
(__main__.Klaus, 'chumma')

# 3. Call staticmethod without any arg
>>> Klaus.staticmthd()  
()

# 4. Call staticmethod with 1 arg
>>> Klaus.staticmthd('chumma')
('chumma',)

实例方法:

+可以修改对象实例状态

+可以修改类状态

类方法:

-无法修改对象实例状态

+可以修改类状态

静态方法:

-无法修改对象实例状态

-无法修改类状态

class MyClass:
    ''' 
    Instance method has a mandatory first attribute self which represent the instance itself. 
    Instance method must be called by a instantiated instance.
    '''
    def method(self):
        return 'instance method called', self
    
    '''
    Class method has a mandatory first attribute cls which represent the class itself. 
    Class method can be called by an instance or by the class directly. 
    Its most common using scenario is to define a factory method.
    '''
    @classmethod
    def class_method(cls):
        return 'class method called', cls
    
    '''
    Static method doesn’t have any attributes of instances or the class. 
    It also can be called by an instance or by the class directly. 
    Its most common using scenario is to define some helper or utility functions which are closely relative to the class.
    '''
    @staticmethod
    def static_method():
        return 'static method called'


obj = MyClass()
print(obj.method())
print(obj.class_method()) # MyClass.class_method()
print(obj.static_method()) # MyClass.static_method()

输出:

('instance method called', <__main__.MyClass object at 0x100fb3940>)
('class method called', <class '__main__.MyClass'>)
static method called

实例方法实际上可以访问对象实例,所以这是我的类对象的一个实例,而使用类方法,我们可以访问类本身。但不适用于任何对象,因为类方法并不真正关心现有的对象。但是,您可以同时调用对象实例上的类方法和静态方法。这将起作用,但实际上并没有什么不同,所以当你在这里调用静态方法时,它会起作用,它会知道你要调用哪个方法。

静态方法用于执行一些实用程序任务,类方法用于工厂方法。工厂方法可以为不同的用例返回类对象。

最后,举一个简短的例子来更好地理解:

class Student:
    def __init__(self, first_name, last_name):
        self.first_name = first_name
        self.last_name = last_name

    @classmethod
    def get_from_string(cls, name_string: str):
        first_name, last_name = name_string.split()
        if Student.validate_name(first_name) and Student.validate_name(last_name):
            return cls(first_name, last_name)
        else:
            print('Invalid Names')

    @staticmethod
    def validate_name(name):
        return len(name) <= 10


stackoverflow_student = Student.get_from_string('Name Surname')
print(stackoverflow_student.first_name) # Name
print(stackoverflow_student.last_name) # Surname

这是一篇关于这个问题的短文

@staticmethod函数只不过是在类中定义的函数。它可以在不首先实例化类的情况下调用。它的定义通过继承是不可变的。@classmethod函数也可以在不实例化类的情况下调用,但它的定义通过继承遵循子类,而不是父类。这是因为@classmethod函数的第一个参数必须始终是cls(class)。