有没有一种方法可以以平台无关的方式确定一台机器有多少个C/ c++内核?如果不存在这样的东西,如何确定每个平台(Windows/*nix/Mac)?


当前回答

还有一个Windows秘方:使用系统范围的环境变量NUMBER_OF_PROCESSORS:

printf("%d\n", atoi(getenv("NUMBER_OF_PROCESSORS")));

其他回答

(几乎)c代码中的平台独立函数

#ifdef _WIN32
#include <windows.h>
#elif MACOS
#include <sys/param.h>
#include <sys/sysctl.h>
#else
#include <unistd.h>
#endif

int getNumCores() {
#ifdef WIN32
    SYSTEM_INFO sysinfo;
    GetSystemInfo(&sysinfo);
    return sysinfo.dwNumberOfProcessors;
#elif MACOS
    int nm[2];
    size_t len = 4;
    uint32_t count;

    nm[0] = CTL_HW; nm[1] = HW_AVAILCPU;
    sysctl(nm, 2, &count, &len, NULL, 0);

    if(count < 1) {
        nm[1] = HW_NCPU;
        sysctl(nm, 2, &count, &len, NULL, 0);
        if(count < 1) { count = 1; }
    }
    return count;
#else
    return sysconf(_SC_NPROCESSORS_ONLN);
#endif
}

Note that "number of cores" might not be a particularly useful number, you might have to qualify it a bit more. How do you want to count multi-threaded CPUs such as Intel HT, IBM Power5 and Power6, and most famously, Sun's Niagara/UltraSparc T1 and T2? Or even more interesting, the MIPS 1004k with its two levels of hardware threading (supervisor AND user-level)... Not to mention what happens when you move into hypervisor-supported systems where the hardware might have tens of CPUs but your particular OS only sees a few.

最好的情况是告诉您在本地OS分区中拥有的逻辑处理单元的数量。除非您是管理程序,否则不要考虑看到真正的机器。今天这个规则唯一的例外是在x86领域,但非虚拟机的末日很快就会到来……

在Linux上,使用_SC_NPROCESSORS_ONLN可能是不安全的,因为它不是POSIX标准的一部分,sysconf手册也有同样的说明。所以有可能_SC_NPROCESSORS_ONLN不存在:

 These values also exist, but may not be standard.

     [...]     

     - _SC_NPROCESSORS_CONF
              The number of processors configured.   
     - _SC_NPROCESSORS_ONLN
              The number of processors currently online (available).

一个简单的方法是读取/proc/stat或/proc/cpuinfo并计算它们:

#include<unistd.h>
#include<stdio.h>

int main(void)
{
char str[256];
int procCount = -1; // to offset for the first entry
FILE *fp;

if( (fp = fopen("/proc/stat", "r")) )
{
  while(fgets(str, sizeof str, fp))
  if( !memcmp(str, "cpu", 3) ) procCount++;
}

if ( procCount == -1) 
{ 
printf("Unable to get proc count. Defaulting to 2");
procCount=2;
}

printf("Proc Count:%d\n", procCount);
return 0;
}

使用 /proc/cpuinfo:

#include<unistd.h>
#include<stdio.h>

int main(void)
{
char str[256];
int procCount = 0;
FILE *fp;

if( (fp = fopen("/proc/cpuinfo", "r")) )
{
  while(fgets(str, sizeof str, fp))
  if( !memcmp(str, "processor", 9) ) procCount++;
}

if ( !procCount ) 
{ 
printf("Unable to get proc count. Defaulting to 2");
procCount=2;
}

printf("Proc Count:%d\n", procCount);
return 0;
}

同样的方法在shell中使用grep:

grep -c ^processor /proc/cpuinfo

Or

grep -c ^cpu /proc/stat # subtract 1 from the result

Windows Server 2003及以后版本允许您利用GetLogicalProcessorInformation函数

http://msdn.microsoft.com/en-us/library/ms683194.aspx

关于OS X的更多信息:sysconf(_SC_NPROCESSORS_ONLN)仅在>= 10.5版本可用,而不是10.4版本。

另一种方法是HW_AVAILCPU/sysctl() BSD代码,在>= 10.2版本中可用。