如果你理解栈的push()和pop()函数，那么queue只是在相反的意义上进行这些操作之一。push()的对边是unshift()， pop()的对边是shift()。 然后:

//classic stack
var stack = [];
stack.push("first"); // push inserts at the end
stack.push("second");
stack.push("last");
stack.pop(); //pop takes the "last" element

//One way to implement queue is to insert elements in the oposite sense than a stack
var queue = [];
queue.unshift("first"); //unshift inserts at the beginning
queue.unshift("second");
queue.unshift("last");
queue.pop(); //"first"

//other way to do queues is to take the elements in the oposite sense than stack
var queue = [];
queue.push("first"); //push, as in the stack inserts at the end
queue.push("second");
queue.push("last");
queue.shift(); //but shift takes the "first" element

如果有人需要它，你可以使用这个NPM包https://www.npmjs.com/package/data-structures-typescript，它有一个队列和堆栈，它支持javascript和typescript，它是通用的，所以你可以用你自己的值类型;)

我认为实现堆栈和队列的最干净的方法应该是使用一个允许从两端添加和删除的容器，然后限制其在一端的功能，这可以通过Javascript中的一个简单数组来完成。

//堆栈容器在封装时使用的语句

// Allow push and pop from the same end
array.push(element);
array.pop();

//封装时在队列容器中使用的语句

// Allow push and pop from different ends
array.push(element);
array.shift();

As many have said: native array using push and pop is fine for a stack, but using shift for taking elements from a queue means that the remaining elements need to move, which is potentially slow. The idea of using two stacks to make a queue in kevinyu's answer is a nice idea to fix it, and of course that can be done with native-array-stacks as well. (Edit: there was actually already an answer by Yuki-Dreamer that does this, albeit less compactly. I didn't notice it until now because it was unfairly downvoted.)

下面是一个使用ES5/ES6特性的紧凑实现，它使队列对象的行为尽可能接近本机的push/shift变体，除了每次操作花费O(1)平摊时间:

const queue = () => {
    const a = [], b = [];
    return {
        push: (...elts) => a.push(...elts),
        shift: () => {
            if (b.length === 0) {
                while (a.length > 0) { b.push(a.pop()) }
            }
            return b.pop();
        },
        get length() { return a.length + b.length }
    }
}

现在你可以做:

const q = queue();
q.push(8);
q.push(9);
q.push(10);
console.log(q.length);          // outputs 3
console.log(q.shift());         // outputs 8
q.push(11);
console.log(q.shift());         // outputs 9
console.log(q.shift());         // outputs 10
console.log(q.shift());         // outputs 11
console.log(q.shift());         // outputs undefined

队列实现对长度使用getter语法，使其看起来像一个属性，并对push使用rest参数语法，以允许一次推送多个内容。如果你不想这样做，你可以用push: elt => a.push(elt)，替换第4行。(但是请注意，你不能用push: a.push替换它，就像我自己第一次尝试的那样，结果非常奇怪:这是因为它导致本机push方法被调用，并设置为队列对象。)

下面是一个相当简单的队列实现，有两个目标:

与array.shift()不同，您知道这个出队列方法需要常数时间(O(1))。 为了提高速度，这种方法使用的分配比链表方法少得多。

堆栈实现只共享第二个目标。

// Queue
function Queue() {
        this.q = new Array(5);
        this.first = 0;
        this.size = 0;
}
Queue.prototype.enqueue = function(a) {
        var other;
        if (this.size == this.q.length) {
                other = new Array(this.size*2);
                for (var i = 0; i < this.size; i++) {
                        other[i] = this.q[(this.first+i)%this.size];
                }
                this.first = 0;
                this.q = other;
        }
        this.q[(this.first+this.size)%this.q.length] = a;
        this.size++;
};
Queue.prototype.dequeue = function() {
        if (this.size == 0) return undefined;
        this.size--;
        var ret = this.q[this.first];
        this.first = (this.first+1)%this.q.length;
        return ret;
};
Queue.prototype.peek = function() { return this.size > 0 ? this.q[this.first] : undefined; };
Queue.prototype.isEmpty = function() { return this.size == 0; };

// Stack
function Stack() {
        this.s = new Array(5);
        this.size = 0;
}
Stack.prototype.push = function(a) {
        var other;
    if (this.size == this.s.length) {
            other = new Array(this.s.length*2);
            for (var i = 0; i < this.s.length; i++) other[i] = this.s[i];
            this.s = other;
    }
    this.s[this.size++] = a;
};
Stack.prototype.pop = function() {
        if (this.size == 0) return undefined;
        return this.s[--this.size];
};
Stack.prototype.peek = function() { return this.size > 0 ? this.s[this.size-1] : undefined; };

下面是一个队列的链表版本，它也包括最后一个节点，这是@perkins建议的，也是最合适的。

// QUEUE Object Definition

var Queue = function() {
  this.first = null;
  this.last = null;
  this.size = 0;
};

var Node = function(data) {
  this.data = data;
  this.next = null;
};

Queue.prototype.enqueue = function(data) {
  var node = new Node(data);

  if (!this.first){ // for empty list first and last are the same
    this.first = node;
    this.last = node;
  } else { // otherwise we stick it on the end
    this.last.next=node;
    this.last=node;
  }

  this.size += 1;
  return node;
};

Queue.prototype.dequeue = function() {
  if (!this.first) //check for empty list
    return null;

  temp = this.first; // grab top of list
  if (this.first==this.last) {
    this.last=null;  // when we need to pop the last one
  }
  this.first = this.first.next; // move top of list down
  this.size -= 1;
  return temp;
};