在JavaScript中实现堆栈和队列的最佳方法是什么?
我想做调车场算法我需要这些数据结构。
在JavaScript中实现堆栈和队列的最佳方法是什么?
我想做调车场算法我需要这些数据结构。
当前回答
下面是一个队列的链表版本,它也包括最后一个节点,这是@perkins建议的,也是最合适的。
// QUEUE Object Definition
var Queue = function() {
this.first = null;
this.last = null;
this.size = 0;
};
var Node = function(data) {
this.data = data;
this.next = null;
};
Queue.prototype.enqueue = function(data) {
var node = new Node(data);
if (!this.first){ // for empty list first and last are the same
this.first = node;
this.last = node;
} else { // otherwise we stick it on the end
this.last.next=node;
this.last=node;
}
this.size += 1;
return node;
};
Queue.prototype.dequeue = function() {
if (!this.first) //check for empty list
return null;
temp = this.first; // grab top of list
if (this.first==this.last) {
this.last=null; // when we need to pop the last one
}
this.first = this.first.next; // move top of list down
this.size -= 1;
return temp;
};
其他回答
var stack = [];
stack.push(2); // stack is now [2]
stack.push(5); // stack is now [2, 5]
var i = stack.pop(); // stack is now [2]
alert(i); // displays 5
var queue = [];
queue.push(2); // queue is now [2]
queue.push(5); // queue is now [2, 5]
var i = queue.shift(); // queue is now [5]
alert(i); // displays 2
摘自“9个你可能不知道的JavaScript技巧”
Javascript数组shift()很慢,特别是当包含很多元素时。我知道两种方法来实现平摊O(1)复杂度的队列。
首先是使用循环缓冲区和表加倍。我以前实现过这个。你可以在这里看到我的源代码 https://github.com/kevyuu/rapid-queue
第二种方法是使用两个堆栈。这是带有两个堆栈的队列的代码
function createDoubleStackQueue() {
var that = {};
var pushContainer = [];
var popContainer = [];
function moveElementToPopContainer() {
while (pushContainer.length !==0 ) {
var element = pushContainer.pop();
popContainer.push(element);
}
}
that.push = function(element) {
pushContainer.push(element);
};
that.shift = function() {
if (popContainer.length === 0) {
moveElementToPopContainer();
}
if (popContainer.length === 0) {
return null;
} else {
return popContainer.pop();
}
};
that.front = function() {
if (popContainer.length === 0) {
moveElementToPopContainer();
}
if (popContainer.length === 0) {
return null;
}
return popContainer[popContainer.length - 1];
};
that.length = function() {
return pushContainer.length + popContainer.length;
};
that.isEmpty = function() {
return (pushContainer.length + popContainer.length) === 0;
};
return that;}
这是使用jsPerf进行的性能比较
CircularQueue.shift() vs Array.shift()
http://jsperf.com/rapidqueue-shift-vs-array-shift
正如你所看到的,大数据集的速度要快得多
Javascript有push和pop方法,它们操作在普通的Javascript数组对象上。
关于排队,请看这里:
http://safalra.com/web-design/javascript/queues/
Queues can be implemented in JavaScript using either the push and shift methods or unshift and pop methods of the array object. Although this is a simple way to implement queues, it is very inefficient for large queues — because of the methods operate on arrays, the shift and unshift methods move every element in the array each time they are called. Queue.js is a simple and efficient queue implementation for JavaScript whose dequeue function runs in amortized constant time. As a result, for larger queues, it can be significantly faster than using arrays.
下面是一个队列的链表版本,它也包括最后一个节点,这是@perkins建议的,也是最合适的。
// QUEUE Object Definition
var Queue = function() {
this.first = null;
this.last = null;
this.size = 0;
};
var Node = function(data) {
this.data = data;
this.next = null;
};
Queue.prototype.enqueue = function(data) {
var node = new Node(data);
if (!this.first){ // for empty list first and last are the same
this.first = node;
this.last = node;
} else { // otherwise we stick it on the end
this.last.next=node;
this.last=node;
}
this.size += 1;
return node;
};
Queue.prototype.dequeue = function() {
if (!this.first) //check for empty list
return null;
temp = this.first; // grab top of list
if (this.first==this.last) {
this.last=null; // when we need to pop the last one
}
this.first = this.first.next; // move top of list down
this.size -= 1;
return temp;
};
这是我的实现堆栈。
function Stack() {
this.dataStore = [];
this.top = 0;
this.push = push;
this.pop = pop;
this.peek = peek;
this.clear = clear;
this.length = length;
}
function push(element) {
this.dataStore[this.top++] = element;
}
function peek() {
return this.dataStore[this.top-1];
}
function pop() {
return this.dataStore[--this.top];
}
function clear() {
this.top = 0;
}
function length() {
return this.top;
}
var s = new Stack();
s.push("David");
s.push("Raymond");
s.push("Bryan");
console.log("length: " + s.length());
console.log(s.peek());