在ruby/python/c中，你可以像这样连接字符串:

a = "foo" "bar"
print a # => "foobar"

INTERCAL可能是最奇怪的语言特征的最佳汇编。我个人最喜欢的是COMEFROM语句，它(几乎)与GOTO相反。

COMEFROM is roughly the opposite of GOTO in that it can take the execution state from any arbitrary point in code to a COMEFROM statement. The point in code where the state transfer happens is usually given as a parameter to COMEFROM. Whether the transfer happens before or after the instruction at the specified transfer point depends on the language used. Depending on the language used, multiple COMEFROMs referencing the same departure point may be invalid, be non-deterministic, be executed in some sort of defined priority, or even induce parallel or otherwise concurrent execution as seen in Threaded Intercal. A simple example of a "COMEFROM x" statement is a label x (which does not need to be physically located anywhere near its corresponding COMEFROM) that acts as a "trap door". When code execution reaches the label, control gets passed to the statement following the COMEFROM. The effect of this is primarily to make debugging (and understanding the control flow of the program) extremely difficult, since there is no indication near the label that control will mysteriously jump to another point of the program.

哈哈！

整个语言本身。虽然不完全是WTF的事情，但我从来没有遇到过一种语言在我的脑海中以一种刺耳的卡通声音播放。我以前也从来没有看过代码并想要惊呼“啊啊啊啊可爱!”

这个程序显示数字1-10并终止

HAI
CAN HAS STDIO?
IM IN YR LOOP UPPIN YR VAR TIL BOTHSAEM VAR AN 10
    VISIBLE SUM OF VAR AN 1
IM OUTTA YR LOOP
KTHXBYE

PHP

$ php -r '::'
Parse error: syntax error, unexpected T_PAAMAYIM_NEKUDOTAYIM

WTF ? http://en.wikipedia.org/wiki/Scope_resolution_operator

为什么不说意外的T_SCOPE_RESOLUTION_OPERATOR ?

特点:Bash, Korn shell (ksh93)和Z shell都允许使用带或不带美元符号的变量下标数组:

array[index]=$value
array[$index]=$value

加上美元符号，会得到10000的期望值:

unset array
for i in {1..10000}
do
    ((array[$RANDOM%6+1]++))
done
unset total
for count in ${array[@]}
do
    ((total += count))
done
echo $total

陌陌性:如果你从RANDOM中移除美元符号，总数将随机变化，甚至大于10000。

类似地，这将产生3而不是2:

a=1; ((r[a++]++)); echo $a

你不能在这里用美元符号，因为这是赋值运算(a在lhs上)虽然你可以用间接的方法，但是双重求值还是会发生。

原因:对于美元符号，变量展开在算术求值之前执行，因此只执行一次。如果没有美元符号，它将执行两次，一次是计算查找的索引，另一次是计算赋值的索引(因此，实际上，循环中第一步的赋值可能看起来像array[4] = $array[6] + 1，这完全打乱了数组)。

Haskell's use of Maybe and Just. Maybe a is a type constructor that returns a type of Just a, but Maybe Int won't accept just an Int, it requires it to be a Just Int or Nothing. So in essence in haskell parlance Just Int is about as much of an Int as an apple is an orange. The only connection is that Just 5 returns a type of Maybe Interger, which can be constructed with the function Just and an Integer argument. This makes sense but is about as hard to explain as it can theoretically be, which is the purpose of haskell right? So is Just really JustKindaLikeButNotAtAll yea sorta, and is Maybe really a KindaLooksLikeOrIsNothing, yea sorta again.

-- Create a function that returns a Maybe Int, and return a 5, which know is definitly Int'able
>  let x :: Maybe Int; x = 5;
<interactive>:1:24:
    No instance for (Num (Maybe Int))
      arising from the literal `5' at <interactive>:1:24
    Possible fix: add an instance declaration for (Num (Maybe Int))
    In the expression: 5
    In the definition of `x': x = 5

>  Just 5  
Just 5
it :: Maybe Integer

    -- Create a function x which takes an Int
>  let x :: Int -> Int; x _ = 0;
x :: Int -> Int
-- Try to give it a Just Int
>  x $ Just 5                   

<interactive>:1:4:
    Couldn't match expected type `Int' against inferred type `Maybe t'
    In the second argument of `($)', namely `Just 5'
    In the expression: x $ Just 5
    In the definition of `it': it = x $ Just 5

祝你好运读到这篇文章，我希望它是正确的。