验证字符串是否是有效的电子邮件地址的最优雅的代码是什么?
当前回答
以前,我写了一个EmailAddressValidationAttribute,它应该正确地验证表单中几乎任何相对正常的电子邮件地址
local-part@domain
它是System.ComponentModel.DataAnnotations。ValidationAttribute,所以使用非常简单。
而且,由于挖掘所有rfc和勘误表,并组装所需的所有位来正确枚举所有规则……太乏味了!-我在回答c#电子邮件地址验证源代码的问题时发布了验证器的源代码。
我的验证器无论怎么想象都不是完美的,只是对于初学者来说,它没有任何内置的对发出客户端javascript验证的支持,尽管将其添加进来并不太难。从我上面的回答来看:
Here's the validation attribute I wrote. It validates pretty much every "raw" email address, that is those of the form local-part@domain. It doesn't support any of the other, more...creative constructs that the RFCs allow (this list is not comprehensive by any means): comments (e.g., jsmith@whizbang.com (work)) quoted strings (escaped text, to allow characters not allowed in an atom) domain literals (e.g. foo@[123.45.67.012]) bang-paths (aka source routing) angle addresses (e.g. John Smith <jsmith@whizbang.com>) folding whitespace double-byte characters in either local-part or domain (7-bit ASCII only). etc. It should accept almost any email address that can be expressed thusly foo.bar@bazbat.com without requiring the use of quotes ("), angle brackets ('<>') or square brackets ([]). No attempt is made to validate that the rightmost dns label in the domain is a valid TLD (top-level domain). That is because the list of TLDs is far larger now than the "big 6" (.com, .edu, .gov, .mil, .net, .org) plus 2-letter ISO country codes. ICANN actually updates the TLD list daily, though I suspect that the list doesn't actually change daily. Further, [ICANN just approved a big expansion of the generic TLD namespace][2]). And some email addresses don't have what you'd recognize as a TLD (did you know that postmaster@. is theoretically valid and mailable? Mail to that address should get delivered to the postmaster of the DNS root zone.) Extending the regular expression to support domain literals shouldn't be too difficult.
其他回答
如果你正在使用FluentValidation,你可以写一些像这样简单的东西:
public cass User
{
public string Email { get; set; }
}
public class UserValidator : AbstractValidator<User>
{
public UserValidator()
{
RuleFor(x => x.Email).EmailAddress().WithMessage("The text entered is not a valid email address.");
}
}
// Validates an user.
var validationResult = new UserValidator().Validate(new User { Email = "açflkdj" });
// This will return false, since the user email is not valid.
bool userIsValid = validationResult.IsValid;
/// <summary>
/// Validates the email if it follows the valid email format
/// </summary>
/// <param name="emailAddress"></param>
/// <returns></returns>
public static bool EmailIsValid(string emailAddress)
{
//if string is not null and empty then check for email follow the format
return string.IsNullOrEmpty(emailAddress)?false : new Regex(@"^(?!\.)(""([^""\r\\]|\\[""\r\\])*""|([-a-z0-9!#$%&'*+/=?^_`{|}~]|(?<!\.)\.)*)(?<!\.)@[a-z0-9][\w\.-]*[a-z0-9]\.[a-z][a-z\.]*[a-z]$", RegexOptions.IgnoreCase).IsMatch(emailAddress);
}
我从第1条中得到Phil的答案,并创建了这个类。 这样调用它:bool isValid = Validator.EmailIsValid(emailString);
下面是这个类:
using System.Text.RegularExpressions;
public static class Validator
{
static Regex ValidEmailRegex = CreateValidEmailRegex();
/// <summary>
/// Taken from http://haacked.com/archive/2007/08/21/i-knew-how-to-validate-an-email-address-until-i.aspx
/// </summary>
/// <returns></returns>
private static Regex CreateValidEmailRegex()
{
string validEmailPattern = @"^(?!\.)(""([^""\r\\]|\\[""\r\\])*""|"
+ @"([-a-z0-9!#$%&'*+/=?^_`{|}~]|(?<!\.)\.)*)(?<!\.)"
+ @"@[a-z0-9][\w\.-]*[a-z0-9]\.[a-z][a-z\.]*[a-z]$";
return new Regex(validEmailPattern, RegexOptions.IgnoreCase);
}
internal static bool EmailIsValid(string emailAddress)
{
bool isValid = ValidEmailRegex.IsMatch(emailAddress);
return isValid;
}
}
我发现这个正则表达式在检查@标记以外的东西和接受奇怪的边缘情况之间是一个很好的权衡:
^[^@\s]+@[^@\s]+(\.[^@\s]+)+$
它至少会让你在@标记周围放一些东西,并且至少放一个正常的域。
这可能是对文本框进行电子邮件验证的最佳方式。
string pattern = null;
pattern = "^([0-9a-zA-Z]([-\\.\\w]*[0-9a-zA-Z])*@([0-9a-zA-Z][-\\w]*[0-9a-zA-Z]\\.)+[a-zA-Z]{2,9})$";
if (Regex.IsMatch("txtemail.Text", pattern))
{
MessageBox.Show ("Valid Email address ");
}
else
{
MessageBox.Show("Invalid Email Email");
}
只要在任何你想要的函数中包含。
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