验证字符串是否是有效的电子邮件地址的最优雅的代码是什么?


当前回答

这是一个老问题,但我在SO上找到的所有答案,包括最近的答案,都与这个问题类似。然而,在。net 4.5 / MVC 4中,你可以通过从System.ComponentModel中添加[EmailAddress]注释来向表单添加电子邮件地址验证。DataAnnotations,所以我想知道为什么我不能只使用。net的内置功能。

这似乎是可行的,而且在我看来是相当优雅的:

using System.ComponentModel.DataAnnotations;

class ValidateSomeEmails
{
    static void Main(string[] args)
    {
        var email = new EmailAddressAttribute();
        email.IsValid("someone@somewhere.com");         //true
        email.IsValid("someone@somewhere.co.uk");       //true
        email.IsValid("someone+tag@somewhere.net");     //true
        email.IsValid("futureTLD@somewhere.fooo");      //true
        
        email.IsValid("fdsa");                          //false
        email.IsValid("fdsa@");                         //false
        email.IsValid("fdsa@fdsa");                     //false
        email.IsValid("fdsa@fdsa.");                    //false

        //one-liner
        if (new EmailAddressAttribute().IsValid("someone@somewhere.com")) 
            return true;
    }
}

其他回答

对@齿轮回答做了一点修改

public static bool IsValidEmail(this string email)
{
  // skip the exception & return early if possible
  if (email.IndexOf("@") <= 0) return false;

  try
  {
    var address = new MailAddress(email);
    return address.Address == email;
  }
  catch
  {
    return false;
  }
}

我将Poyson 1的答案简化如下:

public static bool IsValidEmailAddress(string candidateEmailAddr)
{
    string regexExpresion = "\\w+([-+.']\\w+)*@\\w+([-.]\\w+)*\\.\\w+([-.]\\w+)*";
    return (Regex.IsMatch(candidateEmailAddr, regexExpresion)) && 
           (Regex.Replace(candidateEmailAddr, regexExpresion, string.Empty).Length == 0);
}

There are a lot of strong answers here. However, I recommend that we take a step back. @Cogwheel answers the question https://stackoverflow.com/a/1374644/388267. Nevertheless, it could be costly in a bulk validation scenario, if many of the email address being validated are invalid. I suggest that we employ a bit of logic before we enter into his try-catch block. I know that the following code could be written using RegEx but that could be costly for new developers to understand. This is my twopence worth:

    public static bool IsEmail(this string input)
    {
        if (string.IsNullOrWhiteSpace(input)) return false;

        // MUST CONTAIN ONE AND ONLY ONE @
        var atCount = input.Count(c => c == '@');
        if (atCount != 1) return false;

        // MUST CONTAIN PERIOD
        if (!input.Contains(".")) return false;

        // @ MUST OCCUR BEFORE LAST PERIOD
        var indexOfAt = input.IndexOf("@", StringComparison.Ordinal);
        var lastIndexOfPeriod = input.LastIndexOf(".", StringComparison.Ordinal);
        var atBeforeLastPeriod = lastIndexOfPeriod > indexOfAt;
        if (!atBeforeLastPeriod) return false;

        // CODE FROM COGWHEEL'S ANSWER: https://stackoverflow.com/a/1374644/388267 
        try
        {
            var addr = new System.Net.Mail.MailAddress(input);
            return addr.Address == input;
        }
        catch
        {
            return false;
        }
    }
For the simple email like goerge@xxx.com, below code is sufficient. 

 public static bool ValidateEmail(string email)
        {
            System.Text.RegularExpressions.Regex emailRegex = new System.Text.RegularExpressions.Regex(@"^([\w\.\-]+)@([\w\-]+)((\.(\w){2,3})+)$");
            System.Text.RegularExpressions.Match emailMatch = emailRegex.Match(email);
            return emailMatch.Success;
        }

我经常用这个来验证电子邮件,它就像一个魅力。这验证了电子邮件必须在@之前至少有一个字符,并且在“”之前至少有一个字符。

public static bool ValidateEmail(string value, bool required, int minLength, int maxLength)
        {
           value = value.Trim();
           if (required == false && value == "") return true;
           if (required && value == "") return false;
           if (value.Length < minLength || value.Length > maxLength) return false;

           //Email must have at least one character before an @, and at least one character before the .
           int index = value.IndexOf('@');
           if (index < 1 || value.LastIndexOf('.') < index + 2) return false;
           return true;
        }