验证字符串是否是有效的电子邮件地址的最优雅的代码是什么?
当前回答
一个简单的没有使用Regex(我不喜欢它的可读性差):
bool IsValidEmail(string email)
{
string emailTrimed = email.Trim();
if (!string.IsNullOrEmpty(emailTrimed))
{
bool hasWhitespace = emailTrimed.Contains(" ");
int indexOfAtSign = emailTrimed.LastIndexOf('@');
if (indexOfAtSign > 0 && !hasWhitespace)
{
string afterAtSign = emailTrimed.Substring(indexOfAtSign + 1);
int indexOfDotAfterAtSign = afterAtSign.LastIndexOf('.');
if (indexOfDotAfterAtSign > 0 && afterAtSign.Substring(indexOfDotAfterAtSign).Length > 1)
return true;
}
}
return false;
}
例子:
IsValidEmail(“@b.com”) // false IsValidEmail(“a@.com”) // false IsValidEmail(“a@bcom”) // false IsValidEmail(“a.b@com”) // false IsValidEmail(“a@b.”) // false IsValidEmail(“a b@c.com”) // false IsValidEmail(“a@b c.com”) // false IsValidEmail(“a@b.com”) // true IsValidEmail(“a@b.c.com”) // true IsValidEmail(“a+b@c.com”) // true IsValidEmail(“a@123.45.67.89”) // true
它意味着简单,因此它不处理罕见的情况,如电子邮件的括号域包含空格(通常是允许的),电子邮件的IPv6地址等。
其他回答
一个简单的没有使用Regex(我不喜欢它的可读性差):
bool IsValidEmail(string email)
{
string emailTrimed = email.Trim();
if (!string.IsNullOrEmpty(emailTrimed))
{
bool hasWhitespace = emailTrimed.Contains(" ");
int indexOfAtSign = emailTrimed.LastIndexOf('@');
if (indexOfAtSign > 0 && !hasWhitespace)
{
string afterAtSign = emailTrimed.Substring(indexOfAtSign + 1);
int indexOfDotAfterAtSign = afterAtSign.LastIndexOf('.');
if (indexOfDotAfterAtSign > 0 && afterAtSign.Substring(indexOfDotAfterAtSign).Length > 1)
return true;
}
}
return false;
}
例子:
IsValidEmail(“@b.com”) // false IsValidEmail(“a@.com”) // false IsValidEmail(“a@bcom”) // false IsValidEmail(“a.b@com”) // false IsValidEmail(“a@b.”) // false IsValidEmail(“a b@c.com”) // false IsValidEmail(“a@b c.com”) // false IsValidEmail(“a@b.com”) // true IsValidEmail(“a@b.c.com”) // true IsValidEmail(“a+b@c.com”) // true IsValidEmail(“a@123.45.67.89”) // true
它意味着简单,因此它不处理罕见的情况,如电子邮件的括号域包含空格(通常是允许的),电子邮件的IPv6地址等。
我发现这个正则表达式在检查@标记以外的东西和接受奇怪的边缘情况之间是一个很好的权衡:
^[^@\s]+@[^@\s]+(\.[^@\s]+)+$
它至少会让你在@标记周围放一些东西,并且至少放一个正常的域。
There are a lot of strong answers here. However, I recommend that we take a step back. @Cogwheel answers the question https://stackoverflow.com/a/1374644/388267. Nevertheless, it could be costly in a bulk validation scenario, if many of the email address being validated are invalid. I suggest that we employ a bit of logic before we enter into his try-catch block. I know that the following code could be written using RegEx but that could be costly for new developers to understand. This is my twopence worth:
public static bool IsEmail(this string input)
{
if (string.IsNullOrWhiteSpace(input)) return false;
// MUST CONTAIN ONE AND ONLY ONE @
var atCount = input.Count(c => c == '@');
if (atCount != 1) return false;
// MUST CONTAIN PERIOD
if (!input.Contains(".")) return false;
// @ MUST OCCUR BEFORE LAST PERIOD
var indexOfAt = input.IndexOf("@", StringComparison.Ordinal);
var lastIndexOfPeriod = input.LastIndexOf(".", StringComparison.Ordinal);
var atBeforeLastPeriod = lastIndexOfPeriod > indexOfAt;
if (!atBeforeLastPeriod) return false;
// CODE FROM COGWHEEL'S ANSWER: https://stackoverflow.com/a/1374644/388267
try
{
var addr = new System.Net.Mail.MailAddress(input);
return addr.Address == input;
}
catch
{
return false;
}
}
另一个正则表达式匹配答案:
/// <summary>
/// Validates the email input
/// </summary>
internal static bool ValidateEmail(string _emailAddress)
{
string _regexPattern = @"^(([\w-]+\.)+[\w-]+|([a-zA-Z]{1}|[\w-]{2,}))@"
+ @"((([0-1]?[0-9]{1,2}|25[0-5]|2[0-4][0-9])\.([0-1]?[0-9]{1,2}|25[0-5]|2[0-4][0-9])\."
+ @"([0-1]?[0-9]{1,2}|25[0-5]|2[0-4][0-9])\.([0-1]?[0-9]{1,2}|25[0-5]|2[0-4][0-9])){1}|"
+ @"([a-zA-Z]+[\w-]+\.)+[a-zA-Z]{2,4})$";
return (string.IsNullOrEmpty(_emailAddress) == false && System.Text.RegularExpressions.Regex.IsMatch(_emailAddress, _regexPattern))
? true
: false;
}
For the simple email like goerge@xxx.com, below code is sufficient.
public static bool ValidateEmail(string email)
{
System.Text.RegularExpressions.Regex emailRegex = new System.Text.RegularExpressions.Regex(@"^([\w\.\-]+)@([\w\-]+)((\.(\w){2,3})+)$");
System.Text.RegularExpressions.Match emailMatch = emailRegex.Match(email);
return emailMatch.Success;
}
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