验证字符串是否是有效的电子邮件地址的最优雅的代码是什么?
当前回答
来自@齿轮的投票最多的答案是最好的答案,但我已经尝试实现trim()字符串方法,因此它将从字符串开始到结束修剪所有用户空白。检查代码下面的完整示例-
bool IsValidEmail(string email)
{
try
{
email = email.Trim();
var addr = new System.Net.Mail.MailAddress(email);
return addr.Address == email;
}
catch
{
return false;
}
}
其他回答
基于@Cogwheel的回答,我想分享一个修改后的解决方案,适用于SSIS和“脚本组件”:
Place the "Script Component" into your Data Flow connect and then open it. In the section "Input Columns" set the field that contains the E-Mail Adresses to "ReadWrite" (in the example 'fieldName'). Switch back to the section "Script" and click on "Edit Script". Then you need to wait after the code opens. Place this code in the right method: public override void Input0_ProcessInputRow(Input0Buffer Row) { string email = Row.fieldName; try { System.Net.Mail.MailAddress addr = new System.Net.Mail.MailAddress(email); Row.fieldName= addr.Address.ToString(); } catch { Row.fieldName = "WRONGADDRESS"; } }
然后,您可以使用条件分割过滤掉所有无效记录或任何您想做的事情。
.net 4.5增加了System.ComponentModel.DataAnnotations.EmailAddressAttribute
你可以浏览EmailAddressAttribute的源代码,这是它内部使用的正则表达式:
const string pattern = @"^((([a-z]|\d|[!#\$%&'\*\+\-\/=\?\^_`{\|}~]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])+(\.([a-z]|\d|[!#\$%&'\*\+\-\/=\?\^_`{\|}~]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])+)*)|((\x22)((((\x20|\x09)*(\x0d\x0a))?(\x20|\x09)+)?(([\x01-\x08\x0b\x0c\x0e-\x1f\x7f]|\x21|[\x23-\x5b]|[\x5d-\x7e]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(\\([\x01-\x09\x0b\x0c\x0d-\x7f]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF]))))*(((\x20|\x09)*(\x0d\x0a))?(\x20|\x09)+)?(\x22)))@((([a-z]|\d|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(([a-z]|\d|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])([a-z]|\d|-|\.|_|~|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])*([a-z]|\d|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])))\.)+(([a-z]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(([a-z]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])([a-z]|\d|-|\.|_|~|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])*([a-z]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])))\.?$";
For the simple email like goerge@xxx.com, below code is sufficient.
public static bool ValidateEmail(string email)
{
System.Text.RegularExpressions.Regex emailRegex = new System.Text.RegularExpressions.Regex(@"^([\w\.\-]+)@([\w\-]+)((\.(\w){2,3})+)$");
System.Text.RegularExpressions.Match emailMatch = emailRegex.Match(email);
return emailMatch.Success;
}
private static bool IsValidEmail(string emailAddress)
{
const string validEmailPattern = @"^(?!\.)(""([^""\r\\]|\\[""\r\\])*""|"
+ @"([-a-z0-9!#$%&'*+/=?^_`{|}~]|(?<!\.)\.)*)(?<!\.)"
+ @"@[a-z0-9][\w\.-]*[a-z0-9]\.[a-z][a-z\.]*[a-z]$";
return new Regex(validEmailPattern, RegexOptions.IgnoreCase).IsMatch(emailAddress);
}
来自@齿轮的投票最多的答案是最好的答案,但我已经尝试实现trim()字符串方法,因此它将从字符串开始到结束修剪所有用户空白。检查代码下面的完整示例-
bool IsValidEmail(string email)
{
try
{
email = email.Trim();
var addr = new System.Net.Mail.MailAddress(email);
return addr.Address == email;
}
catch
{
return false;
}
}
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