我喜欢这样的Copyconstructors：

    public AnyObject(AnyObject anyObject)
    {
        foreach (var property in typeof(AnyObject).GetProperties())
        {
            property.SetValue(this, property.GetValue(anyObject));
        }
        foreach (var field in typeof(AnyObject).GetFields())
        {
            field.SetValue(this, field.GetValue(anyObject));
        }
    }

如果您有更多内容要复制，请添加它们

不使用ICloneable的原因不是因为它没有通用接口。不使用它的原因是因为它很模糊。它不清楚你得到的是浅拷贝还是深拷贝；这取决于实施者。

是的，MemberwiseColone生成一个浅拷贝，但MemberwiseClone的反面不是克隆；可能是DeepClone，但它并不存在。当您通过对象的ICloneable接口使用对象时，您无法知道底层对象执行哪种克隆。（而且XML注释不会很清楚，因为您将得到接口注释，而不是对象的Clone方法上的注释。）

我通常只做一个Copy方法，它完全符合我的要求。

我已经创建了一个可接受答案的版本，该版本同时适用于“[Serializable]”和“[DataContract]”。我写它已经有一段时间了，但如果我没有记错，[DataContract]需要一个不同的序列化程序。

需要System、System.IO、System.Runtime.Serialization、System.Runtime.Serialization.Formatters.Binary、System.Xml；

public static class ObjectCopier
{

    /// <summary>
    /// Perform a deep Copy of an object that is marked with '[Serializable]' or '[DataContract]'
    /// </summary>
    /// <typeparam name="T">The type of object being copied.</typeparam>
    /// <param name="source">The object instance to copy.</param>
    /// <returns>The copied object.</returns>
    public static T Clone<T>(T source)
    {
        if (typeof(T).IsSerializable == true)
        {
            return CloneUsingSerializable<T>(source);
        }

        if (IsDataContract(typeof(T)) == true)
        {
            return CloneUsingDataContracts<T>(source);
        }

        throw new ArgumentException("The type must be Serializable or use DataContracts.", "source");
    }


    /// <summary>
    /// Perform a deep Copy of an object that is marked with '[Serializable]'
    /// </summary>
    /// <remarks>
    /// Found on http://stackoverflow.com/questions/78536/cloning-objects-in-c-sharp
    /// Uses code found on CodeProject, which allows free use in third party apps
    /// - http://www.codeproject.com/KB/tips/SerializedObjectCloner.aspx
    /// </remarks>
    /// <typeparam name="T">The type of object being copied.</typeparam>
    /// <param name="source">The object instance to copy.</param>
    /// <returns>The copied object.</returns>
    public static T CloneUsingSerializable<T>(T source)
    {
        if (!typeof(T).IsSerializable)
        {
            throw new ArgumentException("The type must be serializable.", "source");
        }

        // Don't serialize a null object, simply return the default for that object
        if (Object.ReferenceEquals(source, null))
        {
            return default(T);
        }

        IFormatter formatter = new BinaryFormatter();
        Stream stream = new MemoryStream();
        using (stream)
        {
            formatter.Serialize(stream, source);
            stream.Seek(0, SeekOrigin.Begin);
            return (T)formatter.Deserialize(stream);
        }
    }


    /// <summary>
    /// Perform a deep Copy of an object that is marked with '[DataContract]'
    /// </summary>
    /// <typeparam name="T">The type of object being copied.</typeparam>
    /// <param name="source">The object instance to copy.</param>
    /// <returns>The copied object.</returns>
    public static T CloneUsingDataContracts<T>(T source)
    {
        if (IsDataContract(typeof(T)) == false)
        {
            throw new ArgumentException("The type must be a data contract.", "source");
        }

        // ** Don't serialize a null object, simply return the default for that object
        if (Object.ReferenceEquals(source, null))
        {
            return default(T);
        }

        DataContractSerializer dcs = new DataContractSerializer(typeof(T));
        using(Stream stream = new MemoryStream())
        {
            using (XmlDictionaryWriter writer = XmlDictionaryWriter.CreateBinaryWriter(stream))
            {
                dcs.WriteObject(writer, source);
                writer.Flush();
                stream.Seek(0, SeekOrigin.Begin);
                using (XmlDictionaryReader reader = XmlDictionaryReader.CreateBinaryReader(stream, XmlDictionaryReaderQuotas.Max))
                {
                    return (T)dcs.ReadObject(reader);
                }
            }
        }
    }


    /// <summary>
    /// Helper function to check if a class is a [DataContract]
    /// </summary>
    /// <param name="type">The type of the object to check.</param>
    /// <returns>Boolean flag indicating if the class is a DataContract (true) or not (false) </returns>
    public static bool IsDataContract(Type type)
    {
        object[] attributes = type.GetCustomAttributes(typeof(DataContractAttribute), false);
        return attributes.Length == 1;
    }

} 

我提出这一点是为了克服.NET的一个缺点，即必须手动深度复制List<T>。

我使用这个：

static public IEnumerable<SpotPlacement> CloneList(List<SpotPlacement> spotPlacements)
{
    foreach (SpotPlacement sp in spotPlacements)
    {
        yield return (SpotPlacement)sp.Clone();
    }
}

在另一个地方：

public object Clone()
{
    OrderItem newOrderItem = new OrderItem();
    ...
    newOrderItem._exactPlacements.AddRange(SpotPlacement.CloneList(_exactPlacements));
    ...
    return newOrderItem;
}

我试图提出一个这样做的oneliner，但这是不可能的，因为yield不能在匿名方法块中工作。

更好的是，使用通用的List<T>克隆器：

class Utility<T> where T : ICloneable
{
    static public IEnumerable<T> CloneList(List<T> tl)
    {
        foreach (T t in tl)
        {
            yield return (T)t.Clone();
        }
    }
}

我在Silverlight中使用ICloneable时遇到了问题，但我喜欢序列化的想法，我可以序列化XML，所以我这样做了：

static public class SerializeHelper
{
    //Michael White, Holly Springs Consulting, 2009
    //michael@hollyspringsconsulting.com
    public static T DeserializeXML<T>(string xmlData) 
        where T:new()
    {
        if (string.IsNullOrEmpty(xmlData))
            return default(T);

        TextReader tr = new StringReader(xmlData);
        T DocItms = new T();
        XmlSerializer xms = new XmlSerializer(DocItms.GetType());
        DocItms = (T)xms.Deserialize(tr);

        return DocItms == null ? default(T) : DocItms;
    }

    public static string SeralizeObjectToXML<T>(T xmlObject)
    {
        StringBuilder sbTR = new StringBuilder();
        XmlSerializer xmsTR = new XmlSerializer(xmlObject.GetType());
        XmlWriterSettings xwsTR = new XmlWriterSettings();
        
        XmlWriter xmwTR = XmlWriter.Create(sbTR, xwsTR);
        xmsTR.Serialize(xmwTR,xmlObject);
        
        return sbTR.ToString();
    }

    public static T CloneObject<T>(T objClone) 
        where T:new()
    {
        string GetString = SerializeHelper.SeralizeObjectToXML<T>(objClone);
        return SerializeHelper.DeserializeXML<T>(GetString);
    }
}

使用System.Text.Json：

https://devblogs.microsoft.com/dotnet/try-the-new-system-text-json-apis/

public static T DeepCopy<T>(this T source)
{
    return source == null ? default : JsonSerializer.Parse<T>(JsonSerializer.ToString(source));
}

新的API使用Span<T>。这应该很快，最好做一些基准测试。

注意：不需要像Json.NET那样使用ObjectCreationHandling。Replace，因为默认情况下它将替换集合值。您现在应该忘记Json.NET，因为所有的东西都将被新的官方API所取代。

我不确定这是否适用于私人领域。