Is there a performance or code maintenance issue with using assert as part of the standard code instead of using it just for debugging purposes? Is assert x >= 0, 'x is less than zero' better or worse than if x < 0: raise Exception('x is less than zero') Also, is there any way to set a business rule like if x < 0 raise error that is always checked without the try/except/finally so, if at anytime throughout the code x is less than 0 an error is raised, like if you set assert x < 0 at the start of a function, anywhere within the function where x becomes less then 0 an exception is raised?
当前回答
如前所述,当您的代码should NOT到达某个点(意味着那里存在错误)时,应该使用断言。在我看来,使用断言最有用的原因可能是不变量/前置/后置条件。在循环或函数的每次迭代的开始或结束时,这些必须为真。
例如,一个递归函数(两个独立的函数,一个处理错误的输入,另一个处理错误的代码,因为它很难与递归区分开来)。如果我忘记写if语句,这将很明显地显示出哪里出了问题。
def SumToN(n):
if n <= 0:
raise ValueError, "N must be greater than or equal to 0"
else:
return RecursiveSum(n)
def RecursiveSum(n):
#precondition: n >= 0
assert(n >= 0)
if n == 0:
return 0
return RecursiveSum(n - 1) + n
#postcondition: returned sum of 1 to n
这些循环不变量通常可以用断言表示。
其他回答
当x在整个函数中小于零时,能够自动抛出错误。您可以使用类描述符。这里有一个例子:
class LessThanZeroException(Exception):
pass
class variable(object):
def __init__(self, value=0):
self.__x = value
def __set__(self, obj, value):
if value < 0:
raise LessThanZeroException('x is less than zero')
self.__x = value
def __get__(self, obj, objType):
return self.__x
class MyClass(object):
x = variable()
>>> m = MyClass()
>>> m.x = 10
>>> m.x -= 20
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "my.py", line 7, in __set__
raise LessThanZeroException('x is less than zero')
LessThanZeroException: x is less than zero
在诸如PTVS、PyCharm、Wing assert isinstance()等IDE中,可以使用isinstance语句对一些不清楚的对象启用代码补全。
是否存在性能问题?
Please remember to "make it work first before you make it work fast". Very few percent of any program are usually relevant for its speed. You can always kick out or simplify an assert if it ever proves to be a performance problem -- and most of them never will. Be pragmatic: Assume you have a method that processes a non-empty list of tuples and the program logic will break if those tuples are not immutable. You should write: def mymethod(listOfTuples): assert(all(type(tp)==tuple for tp in listOfTuples)) This is probably fine if your lists tend to be ten entries long, but it can become a problem if they have a million entries. But rather than discarding this valuable check entirely you could simply downgrade it to def mymethod(listOfTuples): assert(type(listOfTuples[0])==tuple) # in fact _all_ must be tuples! which is cheap but will likely catch most of the actual program errors anyway.
我补充说,我经常使用断言来指定属性,比如循环不变量或我的代码应该具有的逻辑属性,就像我在正式验证的软件中指定它们一样。
它们有两个目的,告诉读者,帮助我推理,并检查我在推理中没有犯错误。例如 :
k = 0
for i in range(n):
assert k == i * (i + 1) // 2
k += i
#do some things
或者在更复杂的情况下:
def sorted(l):
return all(l1 <= l2 for l1, l2 in zip(l, l[1:]))
def mergesort(l):
if len(l) < 2: #python 3.10 will have match - case for this instead of checking length
return l
k = len(l // 2)
l1 = mergesort(l[:k])
l2 = mergesort(l[k:])
assert sorted(l1) # here the asserts allow me to explicit what properties my code should have
assert sorted(l2) # I expect them to be disabled in a production build
return merge(l1, l2)
因为当python在优化模式下运行时,断言是禁用的,所以不要犹豫在它们中编写代价高昂的条件,特别是当它使您的代码更清晰,更不容易出现错误时
Assert是检查- 1. 有效条件, 2. 有效的表述, 3.真正的逻辑; 源代码。它不会让整个项目失败,而是会发出警报,提示源文件中有些地方不合适。
在例1中,因为变量'str'不是空的。因此不会引发任何断言或异常。
示例1:
#!/usr/bin/python
str = 'hello Python!'
strNull = 'string is Null'
if __debug__:
if not str: raise AssertionError(strNull)
print str
if __debug__:
print 'FileName '.ljust(30,'.'),(__name__)
print 'FilePath '.ljust(30,'.'),(__file__)
------------------------------------------------------
Output:
hello Python!
FileName ..................... hello
FilePath ..................... C:/Python\hello.py
在例2中,var 'str'为空。因此,我们可以通过assert语句来避免用户走在错误程序前面。
示例2:
#!/usr/bin/python
str = ''
strNull = 'NULL String'
if __debug__:
if not str: raise AssertionError(strNull)
print str
if __debug__:
print 'FileName '.ljust(30,'.'),(__name__)
print 'FilePath '.ljust(30,'.'),(__file__)
------------------------------------------------------
Output:
AssertionError: NULL String
当我们不想调试并意识到源代码中的断言问题时。禁用优化标志
python -O assertStatement.py 没有东西会被打印出来
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