Is there a performance or code maintenance issue with using assert as part of the standard code instead of using it just for debugging purposes? Is assert x >= 0, 'x is less than zero' better or worse than if x < 0: raise Exception('x is less than zero') Also, is there any way to set a business rule like if x < 0 raise error that is always checked without the try/except/finally so, if at anytime throughout the code x is less than 0 an error is raised, like if you set assert x < 0 at the start of a function, anywhere within the function where x becomes less then 0 an exception is raised?
当前回答
当x在整个函数中小于零时,能够自动抛出错误。您可以使用类描述符。这里有一个例子:
class LessThanZeroException(Exception):
pass
class variable(object):
def __init__(self, value=0):
self.__x = value
def __set__(self, obj, value):
if value < 0:
raise LessThanZeroException('x is less than zero')
self.__x = value
def __get__(self, obj, objType):
return self.__x
class MyClass(object):
x = variable()
>>> m = MyClass()
>>> m.x = 10
>>> m.x -= 20
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "my.py", line 7, in __set__
raise LessThanZeroException('x is less than zero')
LessThanZeroException: x is less than zero
其他回答
我补充说,我经常使用断言来指定属性,比如循环不变量或我的代码应该具有的逻辑属性,就像我在正式验证的软件中指定它们一样。
它们有两个目的,告诉读者,帮助我推理,并检查我在推理中没有犯错误。例如 :
k = 0
for i in range(n):
assert k == i * (i + 1) // 2
k += i
#do some things
或者在更复杂的情况下:
def sorted(l):
return all(l1 <= l2 for l1, l2 in zip(l, l[1:]))
def mergesort(l):
if len(l) < 2: #python 3.10 will have match - case for this instead of checking length
return l
k = len(l // 2)
l1 = mergesort(l[:k])
l2 = mergesort(l[k:])
assert sorted(l1) # here the asserts allow me to explicit what properties my code should have
assert sorted(l2) # I expect them to be disabled in a production build
return merge(l1, l2)
因为当python在优化模式下运行时,断言是禁用的,所以不要犹豫在它们中编写代价高昂的条件,特别是当它使您的代码更清晰,更不容易出现错误时
assert的四个目的
假设您与四位同事Alice、Bernd、Carl和Daphne一起处理20万行代码。 他们喊你的代码,你喊他们的代码。
那么assert有四个角色:
Inform Alice, Bernd, Carl, and Daphne what your code expects. Assume you have a method that processes a list of tuples and the program logic can break if those tuples are not immutable: def mymethod(listOfTuples): assert(all(type(tp)==tuple for tp in listOfTuples)) This is more trustworthy than equivalent information in the documentation and much easier to maintain. Inform the computer what your code expects. assert enforces proper behavior from the callers of your code. If your code calls Alices's and Bernd's code calls yours, then without the assert, if the program crashes in Alices code, Bernd might assume it was Alice's fault, Alice investigates and might assume it was your fault, you investigate and tell Bernd it was in fact his. Lots of work lost. With asserts, whoever gets a call wrong, they will quickly be able to see it was their fault, not yours. Alice, Bernd, and you all benefit. Saves immense amounts of time. Inform the readers of your code (including yourself) what your code has achieved at some point. Assume you have a list of entries and each of them can be clean (which is good) or it can be smorsh, trale, gullup, or twinkled (which are all not acceptable). If it's smorsh it must be unsmorshed; if it's trale it must be baludoed; if it's gullup it must be trotted (and then possibly paced, too); if it's twinkled it must be twinkled again except on Thursdays. You get the idea: It's complicated stuff. But the end result is (or ought to be) that all entries are clean. The Right Thing(TM) to do is to summarize the effect of your cleaning loop as assert(all(entry.isClean() for entry in mylist)) This statements saves a headache for everybody trying to understand what exactly it is that the wonderful loop is achieving. And the most frequent of these people will likely be yourself. Inform the computer what your code has achieved at some point. Should you ever forget to pace an entry needing it after trotting, the assert will save your day and avoid that your code breaks dear Daphne's much later.
在我看来,assert的两个文档目的(1和3)和 保障措施(2和4)同样有价值。 告知人民甚至可能比告知计算机更有价值 因为它可以防止assert要捕捉的错误(在情况1中) 无论如何,接下来还有很多错误。
无论如何,如果你处理的代码依赖assert来正常工作,那么添加以下代码将确保assert被启用:
try:
assert False
raise Exception('Python assertions are not working. This tool relies on Python assertions to do its job. Possible causes are running with the "-O" flag or running a precompiled (".pyo" or ".pyc") module.')
except AssertionError:
pass
当x在整个函数中小于零时,能够自动抛出错误。您可以使用类描述符。这里有一个例子:
class LessThanZeroException(Exception):
pass
class variable(object):
def __init__(self, value=0):
self.__x = value
def __set__(self, obj, value):
if value < 0:
raise LessThanZeroException('x is less than zero')
self.__x = value
def __get__(self, obj, objType):
return self.__x
class MyClass(object):
x = variable()
>>> m = MyClass()
>>> m.x = 10
>>> m.x -= 20
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "my.py", line 7, in __set__
raise LessThanZeroException('x is less than zero')
LessThanZeroException: x is less than zero
是否存在性能问题?
Please remember to "make it work first before you make it work fast". Very few percent of any program are usually relevant for its speed. You can always kick out or simplify an assert if it ever proves to be a performance problem -- and most of them never will. Be pragmatic: Assume you have a method that processes a non-empty list of tuples and the program logic will break if those tuples are not immutable. You should write: def mymethod(listOfTuples): assert(all(type(tp)==tuple for tp in listOfTuples)) This is probably fine if your lists tend to be ten entries long, but it can become a problem if they have a million entries. But rather than discarding this valuable check entirely you could simply downgrade it to def mymethod(listOfTuples): assert(type(listOfTuples[0])==tuple) # in fact _all_ must be tuples! which is cheap but will likely catch most of the actual program errors anyway.
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