我想从纬度和经度在安卓得到以下值

街道地址 城市/州 邮政编码 完整的地址

如何做到这一点?


当前回答

  public static String getAddressFromLatLng(Context context, LatLng latLng) {
    Geocoder geocoder;
    List<Address> addresses;
    geocoder = new Geocoder(context, Locale.getDefault());
    try {
        addresses = geocoder.getFromLocation(latLng.latitude, latLng.longitude, 1);
        return addresses.get(0).getAddressLine(0);
    } catch (Exception e) {
        e.printStackTrace();
        return "";
    }
}

其他回答

城市和国家不总是在地址1号线和2号线…

例子在这里

So,

Geocoder geocoder = new Geocoder(context, Locale.getDefault());

List<Address> addresses  = geocoder.getFromLocation(latitude,longitude, 1);
String address = addresses.get(0).getAddressLine(0);
String city = addresses.get(0).getLocality();
String state = addresses.get(0).getAdminArea();
String zip = addresses.get(0).getPostalCode();
String country = addresses.get(0).getCountryName();
  Geocoder geocoder =new Geocoder(mContext, Locale.getDefault());
 // Get the current location from the input parameter list
  Location loc = params[0];
 // Create a list to contain the result address
  List<Address> addresses = null;
  try {
     addresses = geocoder.getFromLocation(loc.getLatitude(),
             loc.getLongitude(), 10);
 } catch (IOException e1) {
           Log.e("LocationSampleActivity","IO Exception in getFromLocation()");
      e1.printStackTrace();

 } catch (IllegalArgumentException e2) {
 // Error message to post in the log
 String errorString = "Illegal arguments " +
         Double.toString(loc.getLatitude()) +
         " , " +
         Double.toString(loc.getLongitude()) +
         " passed to address service";
 Log.e("LocationSampleActivity", errorString);
 e2.printStackTrace();

 }
 Address address=null;
 String zip=null;
 String city=null;
 String state=null;
 StringBuffer st=new StringBuffer();
 // If the reverse geocode returned an address
 if (addresses != null && addresses.size() > 0) {
 String       add=addresses.get(0).getAddressLine(0)+","
  +addresses.get(0).getSubAdminArea()+","
  +addresses.get(0).getSubLocality();
  city=addresses.get(0).getLocality();
  state=addresses.get(0).getAdminArea();
     // Get the first address
  for(int i=0 ;i<addresses.size();i++){
  address = addresses.get(i);
   if(address.getPostalCode()!=null){
zip=address.getPostalCode();
break;
     }

      }

你可以这样做,以获得完整的经纬度地址:

  public class MainActivity extends AppCompatActivity {

         ...

  private Geocoder geocoder;
  private TextView mAddressTxtVu;

         ...


  // I assume that you got latitude and longitude correctly 

  mLatitude  =  20.23232
  mLongitude =  32.999

  String errorMessage = "";

  geocoder = new Geocoder(context, Locale.getDefault());

  List<Address> addresses = null;

  try {
              addresses = geocoder.getFromLocation(
                       mlattitude,
                       mlongitude,
                       1);
      } catch (IOException e) {
              errorMessage = getString(R.string.service_not_available);
              Log.e(TAG, errorMessage, e);
      } catch (IllegalArgumentException illegalArgumentException) {
                        // Catch invalid latitude or longitude values.
              errorMessage = getString(R.string.invalid_lat_long_used);
              Log.e(TAG, errorMessage + ". " + "Latitude = " + mlattitude +", Longitude = " + mlongitude, illegalArgumentException);
      }

      // Handle case where no address was found.
      if (addresses == null || addresses.size() == 0) {
             if (errorMessage.isEmpty()) {
                      errorMessage = getString(R.string.no_address_found);
                      Log.e(TAG, errorMessage);
             }

      } else {
             Address address = addresses.get(0);
             ArrayList<String> addressFragments = new ArrayList<String>();

             // Fetch the address lines using getAddressLine,
             // join them, and send them to the thread.
             for (int i = 0; i <= address.getMaxAddressLineIndex(); i++) {
                      addressFragments.add(address.getAddressLine(i));
             }
             // Log.i(TAG, getString(R.string.address_found));


    mAddressTxtVu.setText(TextUtils.join(System.getProperty("line.separator"),
                                addressFragments));
                    }

似乎还没有人提供谷歌Docs (https://developer.android.com/training/location/display-address#java)建议的解决方案。正确的解决方案应该使用IntentService进行反向地理编码的网络调用。

使用意图服务而不是AsyncTask,因为它没有绑定到任何特定的活动。ie。它有自己的生命周期。当地理编码完成时,IntentService将自动停止。

public class GeocodingService extends IntentService {

    public GeocodingService() {
        super("GeocodingService");
    }


    @Override
    protected void onHandleIntent(@Nullable Intent intent) {
        if (intent == null) {
            return;
        }

        Geocoder geocoder = new Geocoder(this, Locale.getDefault());
        String errorMessage = "";
        BCCDatabase BCCDatabase = skicompanion.skicompanion.storage.BCCDatabase.getInstance(getApplicationContext());

        // Get the location passed to this service through an extra.
        Location location = intent.getParcelableExtra(
                "location");
        long trackID = intent.getLongExtra("trackID", -1);

        List<Address> addresses = null;
        String addressString = "";

        try {
            addresses = geocoder.getFromLocation(
                    location.getLatitude(),
                    location.getLongitude(),
                    1);
        } catch (IOException ioException) {
            // Catch network or other I/O problems.
            errorMessage = "service not available";
            Log.d(Constants.SkiCompanionDebug, errorMessage, ioException);
        } catch (IllegalArgumentException illegalArgumentException) {
            // Catch invalid latitude or longitude values.
            errorMessage = "invalid lat long used";
            Log.d(Constants.SkiCompanionDebug, errorMessage + ". " +
                    "Latitude = " + location.getLatitude() +
                    ", Longitude = " +
                    location.getLongitude(), illegalArgumentException);
        }

        // Handle case where no address was found.
        if (addresses == null || addresses.size()  == 0) {
            if (errorMessage.isEmpty()) {
                errorMessage = "no address found";
                Log.d(Constants.SkiCompanionDebug, errorMessage);
            }
        } else {
            if(addresses.get(0).getLocality() != null){
                addressString += addresses.get(0).getLocality() + ", ";
            }
            if(addresses.get(0).getAdminArea() != null){
                addressString += addresses.get(0).getAdminArea() + ", ";
            }
            if(addresses.get(0).getCountryName() != null){
                addressString += addresses.get(0).getCountryName();
            }
            //updating DB
            BCCDatabase.setTrackLocation(trackID, addressString);

            Log.d(Constants.SkiCompanionDebug, "address found: "+ addressString);
        }
    }
}

从latlong (Geo-coordinates)获取Address还有最后一个技巧。你可以简单地通过经度和纬度点击谷歌地图web服务。它只是一个GET-Method web服务。

它将返回JSON响应,可以很容易地解析以获得地址。它的URL是:

http://maps.googleapis.com/maps/api/geocode/json?latlng=32,75&sensor=true

你可以用lat,long代替32,75。