我想从纬度和经度在安卓得到以下值
街道地址 城市/州 邮政编码 完整的地址
如何做到这一点?
我想从纬度和经度在安卓得到以下值
街道地址 城市/州 邮政编码 完整的地址
如何做到这一点?
当前回答
使用Geocoder类从纬度和经度中获得完整地址非常容易。下面是代码示例。希望这能有所帮助!
if (l != null) {
val lat = l.latitude
val lon = l.longitude
val geocoder = Geocoder(this, Locale.getDefault())
val addresses: List<Address>
addresses = geocoder.getFromLocation(lat, lon, 1)
val address = addresses[0].getAddressLine(0)
val address2 = addresses[0].getAddressLine(1)
val city = addresses[0].locality
val state = addresses[0].adminArea
val country = addresses[0].countryName
val postalCode = addresses[0].postalCode
val knownName = addresses[0].featureName
val message =
"Emergency situation. Call for help. My location is: " + address + "." + "http://maps.google.com/maps?saddr=" + lat + "," + lon
}
您可以只使用地址值,因为它提供了所有完整的地址。如果需要单独的组件,也可以使用其他组件。
其他回答
Geocoder geocoder;
List<Address> addresses;
geocoder = new Geocoder(this, Locale.getDefault());
addresses = geocoder.getFromLocation(latitude, longitude, 1); // Here 1 represent max location result to returned, by documents it recommended 1 to 5
String address = addresses.get(0).getAddressLine(0); // If any additional address line present than only, check with max available address lines by getMaxAddressLineIndex()
String city = addresses.get(0).getLocality();
String state = addresses.get(0).getAdminArea();
String country = addresses.get(0).getCountryName();
String postalCode = addresses.get(0).getPostalCode();
String knownName = addresses.get(0).getFeatureName(); // Only if available else return NULL
要了解更多可用细节,请查看Android-Location-Address
在onCreate () . .
LocationManager locationManager = (LocationManager) getSystemService(LOCATION_SERVICE);
locationManager.requestLocationUpdates(LocationManager.GPS_PROVIDER, 30000, 0, this);
Criteria criteria = new Criteria();
String bestProvider = locationManager.getBestProvider(criteria, true);
Location location = locationManager.getLastKnownLocation(bestProvider);
if (location == null) {
Toast.makeText(getApplicationContext(), "GPS signal not found",
3000).show();
}
if (location != null) {
Log.e("location", "location--" + location);
Log.e("latitude at beginning",
"@@@@@@@@@@@@@@@" + location.getLatitude());
onLocationChanged(location);
}
在onLocationChanged()中编写代码
@Override
public void onLocationChanged(Location location) {
Geocoder geocoder;
List<Address> addresses;
geocoder = new Geocoder(this, Locale.getDefault());
latitude = location.getLatitude();
longitude = location.getLongitude();
Log.e("latitude", "latitude--" + latitude);
try {
Log.e("latitude", "inside latitude--" + latitude);
addresses = geocoder.getFromLocation(latitude, longitude, 1);
if (addresses != null && addresses.size() > 0) {
String address = addresses.get(0).getAddressLine(0);
String city = addresses.get(0).getLocality();
String state = addresses.get(0).getAdminArea();
String country = addresses.get(0).getCountryName();
String postalCode = addresses.get(0).getPostalCode();
String knownName = addresses.get(0).getFeatureName();
locationTxt.setText(address + " " + city + " " + country);
}
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
你可以这样做,以获得完整的经纬度地址:
public class MainActivity extends AppCompatActivity {
...
private Geocoder geocoder;
private TextView mAddressTxtVu;
...
// I assume that you got latitude and longitude correctly
mLatitude = 20.23232
mLongitude = 32.999
String errorMessage = "";
geocoder = new Geocoder(context, Locale.getDefault());
List<Address> addresses = null;
try {
addresses = geocoder.getFromLocation(
mlattitude,
mlongitude,
1);
} catch (IOException e) {
errorMessage = getString(R.string.service_not_available);
Log.e(TAG, errorMessage, e);
} catch (IllegalArgumentException illegalArgumentException) {
// Catch invalid latitude or longitude values.
errorMessage = getString(R.string.invalid_lat_long_used);
Log.e(TAG, errorMessage + ". " + "Latitude = " + mlattitude +", Longitude = " + mlongitude, illegalArgumentException);
}
// Handle case where no address was found.
if (addresses == null || addresses.size() == 0) {
if (errorMessage.isEmpty()) {
errorMessage = getString(R.string.no_address_found);
Log.e(TAG, errorMessage);
}
} else {
Address address = addresses.get(0);
ArrayList<String> addressFragments = new ArrayList<String>();
// Fetch the address lines using getAddressLine,
// join them, and send them to the thread.
for (int i = 0; i <= address.getMaxAddressLineIndex(); i++) {
addressFragments.add(address.getAddressLine(i));
}
// Log.i(TAG, getString(R.string.address_found));
mAddressTxtVu.setText(TextUtils.join(System.getProperty("line.separator"),
addressFragments));
}
public static String getAddressFromLatLng(Context context, LatLng latLng) {
Geocoder geocoder;
List<Address> addresses;
geocoder = new Geocoder(context, Locale.getDefault());
try {
addresses = geocoder.getFromLocation(latLng.latitude, latLng.longitude, 1);
return addresses.get(0).getAddressLine(0);
} catch (Exception e) {
e.printStackTrace();
return "";
}
}
使用地理编码器,你可以得到这样的东西!
try {
Geocoder geo = new Geocoder(MapsActivity.this.getApplicationContext(), Locale.getDefault());
List<Address> addresses = geo.getFromLocation(origin.latitude, origin.longitude, 1);
address.setText("Loading...");
if (addresses != null && addresses.size() > 0) {
String locality = addresses.get(0).getAddressLine(0);
String country = addresses.get(0).getCountryName();
String state = addresses.get(0).getAdminArea();
String sub_admin = addresses.get(0).getSubAdminArea();
String city = addresses.get(0).getFeatureName();
String pincode = addresses.get(0).getPostalCode();
String locality_city = addresses.get(0).getLocality();
String sub_localoty = addresses.get(0).getSubLocality();
if (locality != null && country != null) {
address.setText(locality + ", " + (sub_localoty != null ? sub_localoty + ", " : "") + (locality_city != null ? locality_city + ", " : "" ) + (city != null ? city + ", " : "") + (sub_admin != null ? sub_admin + ", " : "") + (state != null ? state + ", " : "") + country + ", " + (pincode != null ? pincode : ""));
} else {
address.setText("Location could not be fetched...");
}
}
} catch (Exception e) {
address.setText("Location could not be fetched...");
e.printStackTrace(); // getFromLocation() may sometimes fail
}