我想从纬度和经度在安卓得到以下值
街道地址 城市/州 邮政编码 完整的地址
如何做到这一点?
我想从纬度和经度在安卓得到以下值
街道地址 城市/州 邮政编码 完整的地址
如何做到这一点?
当前回答
只要用这个方法,把你的背,长。
public static void getAddress(Context context, double LATITUDE, double LONGITUDE{
//Set Address
try {
Geocoder geocoder = new Geocoder(context, Locale.getDefault());
List<Address> addresses = geocoder.getFromLocation(LATITUDE, LONGITUDE, 1);
if (addresses != null && addresses.size() > 0) {
String address = addresses.get(0).getAddressLine(0); // If any additional address line present than only, check with max available address lines by getMaxAddressLineIndex()
String city = addresses.get(0).getLocality();
String state = addresses.get(0).getAdminArea();
String country = addresses.get(0).getCountryName();
String postalCode = addresses.get(0).getPostalCode();
String knownName = addresses.get(0).getFeatureName(); // Only if available else return NULL
Log.d(TAG, "getAddress: address" + address);
Log.d(TAG, "getAddress: city" + city);
Log.d(TAG, "getAddress: state" + state);
Log.d(TAG, "getAddress: postalCode" + postalCode);
Log.d(TAG, "getAddress: knownName" + knownName);
}
} catch (IOException e) {
e.printStackTrace();
}
return;
}
其他回答
从latlong (Geo-coordinates)获取Address还有最后一个技巧。你可以简单地通过经度和纬度点击谷歌地图web服务。它只是一个GET-Method web服务。
它将返回JSON响应,可以很容易地解析以获得地址。它的URL是:
http://maps.googleapis.com/maps/api/geocode/json?latlng=32,75&sensor=true
你可以用lat,long代替32,75。
似乎还没有人提供谷歌Docs (https://developer.android.com/training/location/display-address#java)建议的解决方案。正确的解决方案应该使用IntentService进行反向地理编码的网络调用。
使用意图服务而不是AsyncTask,因为它没有绑定到任何特定的活动。ie。它有自己的生命周期。当地理编码完成时,IntentService将自动停止。
public class GeocodingService extends IntentService {
public GeocodingService() {
super("GeocodingService");
}
@Override
protected void onHandleIntent(@Nullable Intent intent) {
if (intent == null) {
return;
}
Geocoder geocoder = new Geocoder(this, Locale.getDefault());
String errorMessage = "";
BCCDatabase BCCDatabase = skicompanion.skicompanion.storage.BCCDatabase.getInstance(getApplicationContext());
// Get the location passed to this service through an extra.
Location location = intent.getParcelableExtra(
"location");
long trackID = intent.getLongExtra("trackID", -1);
List<Address> addresses = null;
String addressString = "";
try {
addresses = geocoder.getFromLocation(
location.getLatitude(),
location.getLongitude(),
1);
} catch (IOException ioException) {
// Catch network or other I/O problems.
errorMessage = "service not available";
Log.d(Constants.SkiCompanionDebug, errorMessage, ioException);
} catch (IllegalArgumentException illegalArgumentException) {
// Catch invalid latitude or longitude values.
errorMessage = "invalid lat long used";
Log.d(Constants.SkiCompanionDebug, errorMessage + ". " +
"Latitude = " + location.getLatitude() +
", Longitude = " +
location.getLongitude(), illegalArgumentException);
}
// Handle case where no address was found.
if (addresses == null || addresses.size() == 0) {
if (errorMessage.isEmpty()) {
errorMessage = "no address found";
Log.d(Constants.SkiCompanionDebug, errorMessage);
}
} else {
if(addresses.get(0).getLocality() != null){
addressString += addresses.get(0).getLocality() + ", ";
}
if(addresses.get(0).getAdminArea() != null){
addressString += addresses.get(0).getAdminArea() + ", ";
}
if(addresses.get(0).getCountryName() != null){
addressString += addresses.get(0).getCountryName();
}
//updating DB
BCCDatabase.setTrackLocation(trackID, addressString);
Log.d(Constants.SkiCompanionDebug, "address found: "+ addressString);
}
}
}
您正在寻找“地理编码”一词。
你需要做的是:
Geocoder geocoder = new Geocoder(this, Locale.getDefault());
List<Address> addresses = geocoder.getFromLocation(lat, lng, 1);
要做更多,你应该在这里阅读Geocoder。
只要用这个方法,把你的背,长。
public static void getAddress(Context context, double LATITUDE, double LONGITUDE{
//Set Address
try {
Geocoder geocoder = new Geocoder(context, Locale.getDefault());
List<Address> addresses = geocoder.getFromLocation(LATITUDE, LONGITUDE, 1);
if (addresses != null && addresses.size() > 0) {
String address = addresses.get(0).getAddressLine(0); // If any additional address line present than only, check with max available address lines by getMaxAddressLineIndex()
String city = addresses.get(0).getLocality();
String state = addresses.get(0).getAdminArea();
String country = addresses.get(0).getCountryName();
String postalCode = addresses.get(0).getPostalCode();
String knownName = addresses.get(0).getFeatureName(); // Only if available else return NULL
Log.d(TAG, "getAddress: address" + address);
Log.d(TAG, "getAddress: city" + city);
Log.d(TAG, "getAddress: state" + state);
Log.d(TAG, "getAddress: postalCode" + postalCode);
Log.d(TAG, "getAddress: knownName" + knownName);
}
} catch (IOException e) {
e.printStackTrace();
}
return;
}
城市和国家不总是在地址1号线和2号线…
例子在这里
So,
Geocoder geocoder = new Geocoder(context, Locale.getDefault());
List<Address> addresses = geocoder.getFromLocation(latitude,longitude, 1);
String address = addresses.get(0).getAddressLine(0);
String city = addresses.get(0).getLocality();
String state = addresses.get(0).getAdminArea();
String zip = addresses.get(0).getPostalCode();
String country = addresses.get(0).getCountryName();