我想从纬度和经度在安卓得到以下值

街道地址 城市/州 邮政编码 完整的地址

如何做到这一点?


当前回答

城市和国家不总是在地址1号线和2号线…

例子在这里

So,

Geocoder geocoder = new Geocoder(context, Locale.getDefault());

List<Address> addresses  = geocoder.getFromLocation(latitude,longitude, 1);
String address = addresses.get(0).getAddressLine(0);
String city = addresses.get(0).getLocality();
String state = addresses.get(0).getAdminArea();
String zip = addresses.get(0).getPostalCode();
String country = addresses.get(0).getCountryName();

其他回答

试试这个,我的朋友

 private String getCompleteAddressString(double LATITUDE, double LONGITUDE) {
            String strAdd = "";
            Geocoder geocoder = new Geocoder(this, Locale.getDefault());
            try {
                List<Address> addresses = geocoder.getFromLocation(LATITUDE, LONGITUDE, 1);
                if (addresses != null) {
                    Address returnedAddress = addresses.get(0);
                    StringBuilder strReturnedAddress = new StringBuilder("");

                    for (int i = 0; i <= returnedAddress.getMaxAddressLineIndex(); i++) {
                        strReturnedAddress.append(returnedAddress.getAddressLine(i)).append("\n");
                    }
                    strAdd = strReturnedAddress.toString();
                    Log.w("My Current loction address", strReturnedAddress.toString());
                } else {
                    Log.w("My Current loction address", "No Address returned!");
                }
            } catch (Exception e) {
                e.printStackTrace();
                Log.w("My Current loction address", "Canont get Address!");
            }
            return strAdd;
        }
Geocoder geocoder;
List<Address> addresses;
geocoder = new Geocoder(this, Locale.getDefault());

addresses = geocoder.getFromLocation(latitude, longitude, 1); // Here 1 represent max location result to returned, by documents it recommended 1 to 5

String address = addresses.get(0).getAddressLine(0); // If any additional address line present than only, check with max available address lines by getMaxAddressLineIndex()
String city = addresses.get(0).getLocality();
String state = addresses.get(0).getAdminArea();
String country = addresses.get(0).getCountryName();
String postalCode = addresses.get(0).getPostalCode();
String knownName = addresses.get(0).getFeatureName(); // Only if available else return NULL

要了解更多可用细节,请查看Android-Location-Address

尝试使用geocoder使用下面的代码:

  Geocoder gcd = new Geocoder(MainActivity.this, Locale.getDefault());
  List<Address> geoAddresses = geoAddresses = gcd.getFromLocation(location.getLatitude(), location.getLongitude(), 1);
  if (geoAddresses.size() > 0) {
      String mUserLocation = "";
      for (int i = 0; i < 4; i++) { //Since it return only four value we declare this as static.
           mUserLocation = mUserLocation + geoAddresses.get(0).getAddressLine(i).replace(",", "") + ", ";
        } 
    }

使用地理编码器,你可以得到这样的东西!

           try {
                Geocoder geo = new Geocoder(MapsActivity.this.getApplicationContext(), Locale.getDefault());
                List<Address> addresses = geo.getFromLocation(origin.latitude, origin.longitude, 1);
                address.setText("Loading...");
                if (addresses != null && addresses.size() > 0) {
                    String locality = addresses.get(0).getAddressLine(0);
                    String country = addresses.get(0).getCountryName();
                    String state = addresses.get(0).getAdminArea();
                    String sub_admin = addresses.get(0).getSubAdminArea();
                    String city = addresses.get(0).getFeatureName();
                    String pincode = addresses.get(0).getPostalCode();
                    String locality_city = addresses.get(0).getLocality();
                    String sub_localoty = addresses.get(0).getSubLocality();
                    if (locality != null && country != null) {
                        address.setText(locality + ", " + (sub_localoty != null ? sub_localoty + ", " : "")  + (locality_city != null ? locality_city + ", " : "" ) + (city != null ? city + ", " : "")  + (sub_admin != null ? sub_admin + ", " : "") + (state != null ? state + ", " : "") + country + ", " + (pincode != null ? pincode : ""));
                    } else {
                        address.setText("Location could not be fetched...");
                    }
                }
            } catch (Exception e) {
                address.setText("Location could not be fetched...");
                e.printStackTrace(); // getFromLocation() may sometimes fail
            }

只要用这个方法,把你的背,长。

public static void getAddress(Context context, double LATITUDE, double LONGITUDE{
    //Set Address
    try {
        Geocoder geocoder = new Geocoder(context, Locale.getDefault());
        List<Address> addresses = geocoder.getFromLocation(LATITUDE, LONGITUDE, 1);

        if (addresses != null && addresses.size() > 0) {
            String address = addresses.get(0).getAddressLine(0); // If any additional address line present than only, check with max available address lines by getMaxAddressLineIndex()
            String city = addresses.get(0).getLocality();
            String state = addresses.get(0).getAdminArea();
            String country = addresses.get(0).getCountryName();
            String postalCode = addresses.get(0).getPostalCode();
            String knownName = addresses.get(0).getFeatureName(); // Only if available else return NULL
            Log.d(TAG, "getAddress:  address" + address);
            Log.d(TAG, "getAddress:  city" + city);
            Log.d(TAG, "getAddress:  state" + state);
            Log.d(TAG, "getAddress:  postalCode" + postalCode);
            Log.d(TAG, "getAddress:  knownName" + knownName);
        }

    } catch (IOException e) {
        e.printStackTrace();
    }
    return;
}