我想从纬度和经度在安卓得到以下值
街道地址 城市/州 邮政编码 完整的地址
如何做到这一点?
我想从纬度和经度在安卓得到以下值
街道地址 城市/州 邮政编码 完整的地址
如何做到这一点?
当前回答
您正在寻找“地理编码”一词。
你需要做的是:
Geocoder geocoder = new Geocoder(this, Locale.getDefault());
List<Address> addresses = geocoder.getFromLocation(lat, lng, 1);
要做更多,你应该在这里阅读Geocoder。
其他回答
从latlong (Geo-coordinates)获取Address还有最后一个技巧。你可以简单地通过经度和纬度点击谷歌地图web服务。它只是一个GET-Method web服务。
它将返回JSON响应,可以很容易地解析以获得地址。它的URL是:
http://maps.googleapis.com/maps/api/geocode/json?latlng=32,75&sensor=true
你可以用lat,long代替32,75。
public static String getAddressFromLatLng(Context context, LatLng latLng) {
Geocoder geocoder;
List<Address> addresses;
geocoder = new Geocoder(context, Locale.getDefault());
try {
addresses = geocoder.getFromLocation(latLng.latitude, latLng.longitude, 1);
return addresses.get(0).getAddressLine(0);
} catch (Exception e) {
e.printStackTrace();
return "";
}
}
使用地理编码器,你可以得到这样的东西!
try {
Geocoder geo = new Geocoder(MapsActivity.this.getApplicationContext(), Locale.getDefault());
List<Address> addresses = geo.getFromLocation(origin.latitude, origin.longitude, 1);
address.setText("Loading...");
if (addresses != null && addresses.size() > 0) {
String locality = addresses.get(0).getAddressLine(0);
String country = addresses.get(0).getCountryName();
String state = addresses.get(0).getAdminArea();
String sub_admin = addresses.get(0).getSubAdminArea();
String city = addresses.get(0).getFeatureName();
String pincode = addresses.get(0).getPostalCode();
String locality_city = addresses.get(0).getLocality();
String sub_localoty = addresses.get(0).getSubLocality();
if (locality != null && country != null) {
address.setText(locality + ", " + (sub_localoty != null ? sub_localoty + ", " : "") + (locality_city != null ? locality_city + ", " : "" ) + (city != null ? city + ", " : "") + (sub_admin != null ? sub_admin + ", " : "") + (state != null ? state + ", " : "") + country + ", " + (pincode != null ? pincode : ""));
} else {
address.setText("Location could not be fetched...");
}
}
} catch (Exception e) {
address.setText("Location could not be fetched...");
e.printStackTrace(); // getFromLocation() may sometimes fail
}
Geocoder geocoder;
List<Address> addresses;
geocoder = new Geocoder(this, Locale.getDefault());
addresses = geocoder.getFromLocation(latitude, longitude, 1); // Here 1 represent max location result to returned, by documents it recommended 1 to 5
String address = addresses.get(0).getAddressLine(0); // If any additional address line present than only, check with max available address lines by getMaxAddressLineIndex()
String city = addresses.get(0).getLocality();
String state = addresses.get(0).getAdminArea();
String country = addresses.get(0).getCountryName();
String postalCode = addresses.get(0).getPostalCode();
String knownName = addresses.get(0).getFeatureName(); // Only if available else return NULL
要了解更多可用细节,请查看Android-Location-Address
你可以这样做,以获得完整的经纬度地址:
public class MainActivity extends AppCompatActivity {
...
private Geocoder geocoder;
private TextView mAddressTxtVu;
...
// I assume that you got latitude and longitude correctly
mLatitude = 20.23232
mLongitude = 32.999
String errorMessage = "";
geocoder = new Geocoder(context, Locale.getDefault());
List<Address> addresses = null;
try {
addresses = geocoder.getFromLocation(
mlattitude,
mlongitude,
1);
} catch (IOException e) {
errorMessage = getString(R.string.service_not_available);
Log.e(TAG, errorMessage, e);
} catch (IllegalArgumentException illegalArgumentException) {
// Catch invalid latitude or longitude values.
errorMessage = getString(R.string.invalid_lat_long_used);
Log.e(TAG, errorMessage + ". " + "Latitude = " + mlattitude +", Longitude = " + mlongitude, illegalArgumentException);
}
// Handle case where no address was found.
if (addresses == null || addresses.size() == 0) {
if (errorMessage.isEmpty()) {
errorMessage = getString(R.string.no_address_found);
Log.e(TAG, errorMessage);
}
} else {
Address address = addresses.get(0);
ArrayList<String> addressFragments = new ArrayList<String>();
// Fetch the address lines using getAddressLine,
// join them, and send them to the thread.
for (int i = 0; i <= address.getMaxAddressLineIndex(); i++) {
addressFragments.add(address.getAddressLine(i));
}
// Log.i(TAG, getString(R.string.address_found));
mAddressTxtVu.setText(TextUtils.join(System.getProperty("line.separator"),
addressFragments));
}