给定字符串“ThisStringHasNoSpacesButItDoesHaveCapitals”,什么是在大写字母之前添加空格的最好方法。所以结尾字符串是"This string Has No space But It Does Have大写"

下面是我使用正则表达式的尝试

System.Text.RegularExpressions.Regex.Replace(value, "[A-Z]", " $0")

当前回答

这个问题包括首字母缩写词和首字母缩写复数,比公认的答案快一点:

public string Sentencify(string value)
{
    if (string.IsNullOrWhiteSpace(value))
        return string.Empty;

    string final = string.Empty;
    for (int i = 0; i < value.Length; i++)
    {
        if (i != 0 && Char.IsUpper(value[i]))
        {
            if (!Char.IsUpper(value[i - 1]))
                final += " ";
            else if (i < (value.Length - 1))
            {
                if (!Char.IsUpper(value[i + 1]) && !((value.Length >= i && value[i + 1] == 's') ||
                                                     (value.Length >= i + 1 && value[i + 1] == 'e' && value[i + 2] == 's')))
                    final += " ";
            }
        }

        final += value[i];
    }

    return final;
}

通过以下测试:

string test1 = "RegularOTs";
string test2 = "ThisStringHasNoSpacesASCIIButItDoesHaveCapitalsLINQ";
string test3 = "ThisStringHasNoSpacesButItDoesHaveCapitals";

其他回答

下面是在SQL中如何做到这一点

create  FUNCTION dbo.PascalCaseWithSpace(@pInput AS VARCHAR(MAX)) RETURNS VARCHAR(MAX)
BEGIN
    declare @output varchar(8000)

set @output = ''


Declare @vInputLength        INT
Declare @vIndex              INT
Declare @vCount              INT
Declare @PrevLetter varchar(50)
SET @PrevLetter = ''

SET @vCount = 0
SET @vIndex = 1
SET @vInputLength = LEN(@pInput)

WHILE @vIndex <= @vInputLength
BEGIN
    IF ASCII(SUBSTRING(@pInput, @vIndex, 1)) = ASCII(Upper(SUBSTRING(@pInput, @vIndex, 1)))
       begin 

        if(@PrevLetter != '' and ASCII(@PrevLetter) = ASCII(Lower(@PrevLetter)))
            SET @output = @output + ' ' + SUBSTRING(@pInput, @vIndex, 1)
            else
            SET @output = @output +  SUBSTRING(@pInput, @vIndex, 1) 

        end
    else
        begin
        SET @output = @output +  SUBSTRING(@pInput, @vIndex, 1) 

        end

set @PrevLetter = SUBSTRING(@pInput, @vIndex, 1) 

    SET @vIndex = @vIndex + 1
END


return @output
END

你拥有的一切都很完美。只需要记住将value重新赋值给这个函数的返回值即可。

value = System.Text.RegularExpressions.Regex.Replace(value, "[A-Z]", " $0");

这是我的:

private string SplitCamelCase(string s) 
{ 
    Regex upperCaseRegex = new Regex(@"[A-Z]{1}[a-z]*"); 
    MatchCollection matches = upperCaseRegex.Matches(s); 
    List<string> words = new List<string>(); 
    foreach (Match match in matches) 
    { 
        words.Add(match.Value); 
    } 
    return String.Join(" ", words.ToArray()); 
}

在小写字母、大写字母或数字后添加空格的简单方法。

    string AddSpacesToSentence(string value, bool spaceLowerChar = true, bool spaceDigitChar = true, bool spaceSymbolChar = false)
    {
        var result = "";

        for (int i = 0; i < value.Length; i++)
        {
            char currentChar = value[i];
            char nextChar = value[i < value.Length - 1 ? i + 1 : value.Length - 1];

            if (spaceLowerChar && char.IsLower(currentChar) && !char.IsLower(nextChar))
            {
                result += value[i] + " ";
            }
            else if (spaceDigitChar && char.IsDigit(currentChar) && !char.IsDigit(nextChar))
            {
                result += value[i] + " ";
            }
            else if(spaceSymbolChar && char.IsSymbol(currentChar) && !char.IsSymbol(nextChar))
            {
                result += value[i];
            }
            else
            {
                result += value[i];
            }
        }

        return result;
    }

我知道这是一个旧的,但这是一个扩展我使用当我需要这样做:

public static class Extensions
{
    public static string ToSentence( this string Input )
    {
        return new string(Input.SelectMany((c, i) => i > 0 && char.IsUpper(c) ? new[] { ' ', c } : new[] { c }).ToArray());
    }
}

这将允许您使用MyCasedString.ToSentence()