虽然这并不是一个更好的重命名键的解决方案，但它提供了一种快速简单的ES6方法来重命名对象中的所有键，同时不改变它们所包含的数据。

let b = {a: ["1"], b:["2"]};
Object.keys(b).map(id => {
  b[`root_${id}`] = [...b[id]];
  delete b[id];
});
console.log(b);

const clone = (obj) => Object.assign({}, obj);

const renameKey = (object, key, newKey) => {

    const clonedObj = clone(object);
  
    const targetKey = clonedObj[key];
  
  
  
    delete clonedObj[key];
  
    clonedObj[newKey] = targetKey;
  
    return clonedObj;
     };

  let contact = {radiant: 11, dire: 22};





contact = renameKey(contact, 'radiant', 'aplha');

contact = renameKey(contact, 'dire', 'omega');



console.log(contact); // { aplha: 11, omega: 22 };

使用对象解构和展开运算符的变体:

const old_obj = {
    k1: `111`,
    k2: `222`,
    k3: `333`
};    

// destructuring, with renaming. The variable 'rest' will hold those values not assigned to kA, kB, or kC.
const {
    k1: kA, 
    k2: kB, 
    k3: kC,
    ...rest
} = old_obj;
    

// now create a new object, with the renamed properties kA, kB, kC; 
// spread the remaining original properties in the 'rest' variable
const newObj = {kA, kB, kC, ...rest};

对于一个键，这可以很简单:

const { k1: kA, ...rest } = old_obj;
const new_obj = { kA, ...rest }

你也可能喜欢更“传统”的风格:

const { k1, ...rest } = old_obj
const new_obj = { kA: k1, ...rest}

本页列出的一些解决方案有一些副作用:

影响键在对象中的位置，将其添加到底部(如果这对你来说很重要) 不能在IE9+中工作(如果这对你来说很重要的话)

下面是一个解决方案，它保持键的位置在相同的地方，并在IE9+兼容，但必须创建一个新的对象，可能不是最快的解决方案:

function renameObjectKey(oldObj, oldName, newName) {
    const newObj = {};

    Object.keys(oldObj).forEach(key => {
        const value = oldObj[key];

        if (key === oldName) {
            newObj[newName] = value;
        } else {
            newObj[key] = value;
        }
    });

    return newObj;
}

请注意:IE9在严格模式下可能不支持forEach

我会这样做:

function renameKeys(dict, keyMap) {
  return _.reduce(dict, function(newDict, val, oldKey) {
    var newKey = keyMap[oldKey] || oldKey
    newDict[newKey] = val 
    return newDict
  }, {})
}

我只想用ES6(ES2015)的方式!

我们需要跟上时代!

const old_obj = { k1: `111`, k2: `222`, k3: `333` }; console.log(`old_obj =\n`, old_obj); // {k1: "111", k2: "222", k3: "333"} /** * @author xgqfrms * @description ES6 ...spread & Destructuring Assignment */ const { k1: kA, k2: kB, k3: kC, } = {...old_obj} console.log(`kA = ${kA},`, `kB = ${kB},`, `kC = ${kC}\n`); // kA = 111, kB = 222, kC = 333 const new_obj = Object.assign( {}, { kA, kB, kC } ); console.log(`new_obj =\n`, new_obj); // {kA: "111", kB: "222", kC: "333"}