const data = res
const lista = []
let newElement: any

if (data && data.length > 0) {

  data.forEach(element => {
      newElement = element

      Object.entries(newElement).map(([key, value]) =>
        Object.assign(newElement, {
          [key.toLowerCase()]: value
        }, delete newElement[key], delete newElement['_id'])
      )
    lista.push(newElement)
  })
}
return lista

一般来说，如果你想获得一个新的对象(不改变原来的对象)，根据keyMap重命名键-你可以使用以下基于lodash mapKeys的实现:

const {mapKeys} = require('lodash');
const renameKeys = (obj, keyMap) => _.mapKeys(obj, (value, key) => keyMap[key] || key);

使用的例子:

renameKeys({a: 1, b: 2, c: 3}, {c: 'p', a: 'm'})
> {m: 1, b: 2, p: 3}

我认为最完整(和正确)的方法是:

if (old_key !== new_key) {
    Object.defineProperty(o, new_key,
        Object.getOwnPropertyDescriptor(o, old_key));
    delete o[old_key];
}

此方法确保重命名的属性的行为与原始属性相同。

另外，在我看来，把它包装成一个函数/方法，并把它放入对象的可能性。原型与你的问题无关。

尝试使用lodash transform。

var _ = require('lodash');

obj = {
  "name": "abc",
  "add": "xyz"
};

var newObject = _.transform(obj, function(result, val, key) {

  if (key === "add") {
    result["address"] = val
  } else {
    result[key] = val
  }
});
console.log(obj);
console.log(newObject);

function iterate(instance) {
  for (let child of instance.tree_down) iterate(child);

  instance.children = instance.tree_down;
  delete instance.tree_down;
}

iterate(link_hierarchy);

console.log(link_hierarchy);

如果你想保持对象的相同顺序

changeObjectKeyName(objectToChange, oldKeyName: string, newKeyName: string){
  const otherKeys = cloneDeep(objectToChange);
  delete otherKeys[oldKeyName];

  const changedKey = objectToChange[oldKeyName];
  return  {...{[newKeyName] : changedKey} , ...otherKeys};

}

使用方法:

changeObjectKeyName ( {'a' : 1}, 'a', 'A');