是否有一种方法可以确定一个方法需要执行多少时间(以毫秒为单位)?


当前回答

我使用非常少的,一页的类实现,灵感来自这篇博客文章的代码:

#import <mach/mach_time.h>

@interface DBGStopwatch : NSObject

+ (void)start:(NSString *)name;
+ (void)stop:(NSString *)name;

@end

@implementation DBGStopwatch

+ (NSMutableDictionary *)watches {
    static NSMutableDictionary *Watches = nil;
    static dispatch_once_t OnceToken;
    dispatch_once(&OnceToken, ^{
        Watches = @{}.mutableCopy;
    });
    return Watches;
}

+ (double)secondsFromMachTime:(uint64_t)time {
    mach_timebase_info_data_t timebase;
    mach_timebase_info(&timebase);
    return (double)time * (double)timebase.numer /
        (double)timebase.denom / 1e9;
}

+ (void)start:(NSString *)name {
    uint64_t begin = mach_absolute_time();
    self.watches[name] = @(begin);
}

+ (void)stop:(NSString *)name {
    uint64_t end = mach_absolute_time();
    uint64_t begin = [self.watches[name] unsignedLongLongValue];
    DDLogInfo(@"Time taken for %@ %g s",
              name, [self secondsFromMachTime:(end - begin)]);
    [self.watches removeObjectForKey:name];
}

@end

它的用法很简单:

调用[DBGStopwatch start:@"slow-operation"];一开始 然后[DBGStopwatch stop:@"slow-operation"];做完之后,才能得到时间

其他回答

我用这个:

clock_t start, end;
double elapsed;
start = clock();

//Start code to time

//End code to time

end = clock();
elapsed = ((double) (end - start)) / CLOCKS_PER_SEC;
NSLog(@"Time: %f",elapsed);

但我不确定iPhone上的CLOCKS_PER_SEC。你还是别打了吧。

NSDate *methodStart = [NSDate date];

/* ... Do whatever you need to do ... */

NSDate *methodFinish = [NSDate date];
NSTimeInterval executionTime = [methodFinish timeIntervalSinceDate:methodStart];
NSLog(@"executionTime = %f", executionTime);

迅速:

let methodStart = NSDate()

/* ... Do whatever you need to do ... */

let methodFinish = NSDate()
let executionTime = methodFinish.timeIntervalSinceDate(methodStart)
print("Execution time: \(executionTime)")

Swift3:

let methodStart = Date()

/* ... Do whatever you need to do ... */

let methodFinish = Date()
let executionTime = methodFinish.timeIntervalSince(methodStart)
print("Execution time: \(executionTime)")

易于使用,具有亚毫秒精度。

许多答案很奇怪,并没有真正以毫秒为单位给出结果(而是以秒或其他单位):

这里是我用来获得MS(毫秒):

迅速:

let startTime = NSDate().timeIntervalSince1970 * 1000

// your Swift code

let endTimeMinusStartTime = NSDate().timeIntervalSince1970 * 1000 - startTime
print("time code execution \(endTimeMinStartTime) ms")

objective - c:

double startTime = [[NSDate date] timeIntervalSince1970] * 1000.0;

// your Objective-C code

double endTimeMinusStartTime = [[NSDate date] timeIntervalSince1970] * 1000.0 - startTime;
printf("time code execution %f ms\n", endTimeMinusStartTime );

一个在Swift 4中使用mach_absolute_time()的细粒度计时的例子:

let start = mach_absolute_time()

// do something

let elapsedMTU = mach_absolute_time() - start
var timebase = mach_timebase_info()
if mach_timebase_info(&timebase) == 0 {
    let elapsed = Double(elapsedMTU) * Double(timebase.numer) / Double(timebase.denom)
    print("render took \(elapsed)")
}
else {
    print("timebase error")
}

我在我的utils库中使用这个(Swift 4.2):

public class PrintTimer {
    let start = Date()
    let name: String

    public init(file: String=#file, line: Int=#line, function: String=#function, name: String?=nil) {
        let file = file.split(separator: "/").last!
        self.name = name ?? "\(file):\(line) - \(function)"
    }

    public func done() {
        let end = Date()
        print("\(self.name) took \((end.timeIntervalSinceReferenceDate - self.start.timeIntervalSinceReferenceDate).roundToSigFigs(5)) s.")
    }
}

…然后调用如下方法:

func myFunctionCall() {
    let timer = PrintTimer()
    // ...
    timer.done()
}

…运行后在控制台中看起来是这样的:

MyFile.swift:225 - myFunctionCall() took 1.8623 s.

虽然不像上面的TICK/TOCK那样简洁,但它足以清楚地看到它在做什么,并自动包括正在计时的内容(通过文件、方法开头的行和函数名)。显然,如果我想要更多的细节(例如,如果我不只是计时一个方法调用,因为是通常的情况下,而是在该方法内计时块),我可以在PrintTimer init上添加“name="Foo""参数来命名它除了默认值之外的东西。